Proof: Basic Properties of Homomorphisms (Identities and Inverses) | Abstract Algebra

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Wrath of Math

Wrath of Math

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We prove two basic properties of a homomorphism f from a group G to a group H. First, we prove the homomorphism maps the identity of G to the identity of H, that is: f(e) = e. Then we prove the homomorphism maps inverses of a to corresponding inverses in H. So, f(a^-1) = [f(a)]^-1. #abstractalgebra #grouptheory
Group Homomorphisms: • Intro to Group Homomor...
Abstract Algebra Course: • Abstract Algebra
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Пікірлер: 3
@OmarWehbeh-hXO
@OmarWehbeh-hXO 26 күн бұрын
Why is f^-1(x)*f(x) = e_H?
@WrathofMath
@WrathofMath 26 күн бұрын
f(x) and its inverse f^(-1)(x) both exist in H, the codomain of the homomorphism because they are images of the function. Since they are inverses, they undo each other and thus produce the identity of the appropriate group, which is H. Does that help?
@OmarWehbeh-hXO
@OmarWehbeh-hXO 26 күн бұрын
@@WrathofMath This really explained everything, Thank you so much🙏 You're the best👊👍
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