Prove that 7^n - 6n -1 is divisible by 36 for any natural number, n. [Mathematical Induction]

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Prime Newtons

Prime Newtons

Күн бұрын

Пікірлер: 17
@jensberling2341
@jensberling2341 9 ай бұрын
The love able and lovely performance, and the subtle and clear persuasion of this math. Induction is breathtaking. Yes, breathtaking for me who has struggled to understand it. Thank you, Doctor
@ayaanmuslimcareafrica6623
@ayaanmuslimcareafrica6623 Жыл бұрын
the best way ever to understand Mathematical induction
@benjaminvatovez8823
@benjaminvatovez8823 Ай бұрын
Thank you very much for your video. I would have suggested to use the binomial theorem: 7^n=(6+1)^n=1+6n+36(sum with k from 2 to n) C^k_n 6^(k-2)
@giuliofalco9816
@giuliofalco9816 19 күн бұрын
Using congruence i proved in this way: 36 = 2^2 3^2 so I apply chinese theorem of remainder writing the following congruence systems: 7^n - 6n - 1 = 0 mod 2; and 7^n - 6n - 1 = 0 mod 3. Substitute 7 with and 6 with the remainder of nteger division by 2 and 3 and the equivalence follow.
@EzraSchroeder
@EzraSchroeder Ай бұрын
this one is straight out of an advanced calculus book haha! it is a problem in chapter one of Kenneth A. Ross: Analysis the Theory of Calculus -- love it!
@bhaveerathod2373
@bhaveerathod2373 Жыл бұрын
YOU ARE GENIUS MAN! THANK YOU, this has helped so much !
@robertveith6383
@robertveith6383 2 ай бұрын
Or, look at (6 + 1)^n - 6n - 1 = 6^n + n*6^(n - 1)*1^1 + [n(n - 1)/2]*6^(n - 2)*1^2 + ... + [n(n - 2)/2]*6^2*1^(n - 2) + n*6^1*1^(n - 1) + 1^n - 6n - 1 = 6^n + n*6^(n - 1) + ... + [n(n - 2)/2]*36 + 6n + 1 - 6n - 1 = 6^n + n*6^(n - 1) + ... + [n(n - 2)/2]*36 That is divisible by 36.
@gurdiprooprai6453
@gurdiprooprai6453 9 күн бұрын
Excellent work, but the most difficult part of this video is what determines whether or not you cross your "7's" or not. I am still working on it lol.
@bhaveerathod2373
@bhaveerathod2373 Жыл бұрын
Best teacher
@KamalAzhar-t7q
@KamalAzhar-t7q Ай бұрын
To prove such property :> (where f is a given fonction and p is a fixed integer) one generally can use induction. But the following is much harder
@lush1523
@lush1523 2 ай бұрын
Am gonna be here till I finish my degree, I have a discrete mathematics course this semester
@BP-gn2cl
@BP-gn2cl Ай бұрын
Write 7^n =(6+1) ^n, apply bionomial expansion and in fourth line you can prove the required thing
@ruthgonzalez6547
@ruthgonzalez6547 Ай бұрын
Nice!
@sumeetmahapatra9862
@sumeetmahapatra9862 9 ай бұрын
Thank you sir
@zazavitch1
@zazavitch1 Жыл бұрын
@aayushixi
@aayushixi 3 ай бұрын
omg tysmmmm
@abdussamadabubakar1746
@abdussamadabubakar1746 11 ай бұрын
Damn!!!!!
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