Here I prove that the derivative of e^x is e^x. #calculus #calculusab #proofs #euler #derivatives #derivative
Пікірлер: 13
@NoahBugbee4 ай бұрын
Sorry if it got a little convoluted around the composite function part. The simpler but less rigorous reason we can put the limit in the natural logarithm is because n can only be found within the natural log. Please give me your feedback on this one.😀
@shafiqkhalil30384 ай бұрын
NICE! love the longer video bro!
@yassimolaoc28854 ай бұрын
Nice video👍
@dice-uj2sr4 ай бұрын
Great video sir 👍 I didn't get the inference of it being continuous and it's limits existing😅 like what does that means? Then I watched another video on it and it all clicked thanks a lot always found it strange that e^x is the same in differentiation 😮
@octs6094 ай бұрын
just discovered your stuff very nice content.
@sachavalette14374 ай бұрын
exp is ln^-1 so exp'(x)=1/ln'(exp(x))=exp(x)
@manganari80224 ай бұрын
nice vid tho i'm not sure this approach is correct: exponential is defined as a function f(x) such as f'(x)+c = f(x) what can be done tho is proving that e=lim n->0(1+n)^1/n or simply approximating the value of e, you can do that easily with tailor series i guess.