Great sir ...... I enjoy when you are solving questions within 15 sec. in almost every lecture. Thanks sir ❤❤
@shikhasarkar45527 ай бұрын
13:52 tan(3) to tan(8) is infinite for atleast one values as 3+(π/2)
@priyanjalitripathi4408 Жыл бұрын
great sir......Thankyou so much for giving all concept of bounded variation in one video.
@kunjkothiya79907 ай бұрын
At time 34:10. In this question A is correct option.
@VinayTiwari-hp1pp Жыл бұрын
Nice explanation sir
@RS10811 Жыл бұрын
❤❤❤ eske alawa kya hi likh den...kyuki sir se accha samjhane wala Aaj Tak dusra koi Mila nhi. Thank you sir. 🙏
@ashokisaini8427 Жыл бұрын
Superb 👍👍👍
@ChandanKumar-dn9lz Жыл бұрын
Excellent explanation... Outstanding....in just one hr lecture each and every thing got Cristal clear ....thanks a lot sir jee.
@Prayosi Жыл бұрын
These lectures are very good. Thank you so much sir.
@sarojsi890 Жыл бұрын
Good explanation with good collection 👍👍
@user-lo2qx8ow9e Жыл бұрын
Your explanations and the way you clear the concept is just wow...❤
@ManishMeena-eo4qh Жыл бұрын
Bht bht dhanyvad guru ji 😊😊😊😊
@ranusheoran3303 Жыл бұрын
Super explanation 👍
@RengalakshmiBabu2 ай бұрын
Excellent teaching sir. Thank you so much for your great lecture
@selfsearching1996 Жыл бұрын
Nice 👍👍
@akarshroy3905 Жыл бұрын
Thank you sir ❤
@nehajangra63627 ай бұрын
Mistakes in last bouned variation implies monotonicity Monotonic + bdd is b.v. but ek nbhm k question main closed interval per monotonic diya hua h how it implies that function is of b.v.
@positivethoughts6419 Жыл бұрын
Thank you so much for this important video 🙏🏼...
@jkmathematics..jitendrakoh85577 ай бұрын
Thanku so much sir love from ❤❤ uttarakhand
@MANTUKUMAR-nn8kk7 ай бұрын
Gajab sir ❤❤❤
@sadzone1434 Жыл бұрын
Nice
@amankumarbehera62323 ай бұрын
It is very helpful for us sir... keep it up,we are with you ❤😊🙏
@jaikmthomas5035 Жыл бұрын
@50:00 Sir if function is not continuous then need not be f is not reimann integrable
@professorragavan97836 ай бұрын
Thankyou very much sir. I did not know about a single concept of bounded variation. After watching your video, it is very useful to me. 🤩😍
@DrHarishGarg6 ай бұрын
You are most welcome
@KAREN-ye5pf7 ай бұрын
27.22 Problem (b) x=1 is not in the domain itself how can we find tan (pi/2)=infinity and we say it's not BV sir ?
@RanjangamingYT74773 ай бұрын
Great sir ❤
@madhavigandhi31818 ай бұрын
Thank You very much sir, for guiding us selflessly. Your videos are marvellous ! Very useful, clear and doubt solving.
@somduttakayal5067 Жыл бұрын
Thank you Sir
@meenakshiannamalai358419 күн бұрын
God bless u .......
@vivekgoswami474 Жыл бұрын
Thanks sir , next complex pleasr
@vishal-ez8tz10 ай бұрын
at 49:41 function is not continuous only at 1 . Therefore discontinuity at only finite number of points this implies f is riemann integerable .Am i right? plz verify sir
@jyotibharti6505 Жыл бұрын
Thank you so much sir 🙏🙏🙏🙏
@divyaverma89302 ай бұрын
thanku sir for this
@madhavigandhi31813 ай бұрын
NBHM 2014 For last option sir, we can say f is bounded by f(0) and below by f(1) therefore it is bdd.
@chinmoykumarpal5461Ай бұрын
Sinx is periodic function,so how you say it is monotonic?pls explain
@komalsaini0172 ай бұрын
44:14 option A is correct according to me
@steel679 Жыл бұрын
Thankyou so much sir,best youtube teacher i ever seen, ❤❤❤❤❤❤keep it sir, short time :=>max knowledge = Dr. HARISH GARG❤
@SahanaKhatun-z1dАй бұрын
Sir please give a lecture on lebesgue measure and lebesgue integrable function
@yashrajtripathi48325 ай бұрын
Apke lecture se pura topic revise ho jata + pyq to ho hi jate h
@sanjitha_dhivin8 ай бұрын
Sir if we get a function that asymptotically decreases at 1. how the function will become bounded on [0,1]?
@kavitachauhan20713 ай бұрын
. 31:44 f'is bounded variation
@mathematicslovers28886 ай бұрын
Thank you sir for giving us very good Content ❤❤
@DrHarishGarg6 ай бұрын
My pleasure... Kindly like, subscribe and share the video with others students too...
@mathematicslovers28886 ай бұрын
Sure sir ☺️ @@DrHarishGarg
@positivethoughts6419 Жыл бұрын
Sir... Please this type of one by one topic video with short explanation of complex analysis subject...🙏🏼
@sanjitha_dhivin8 ай бұрын
Sir how sinx becomes monotonous on [0,2phi]?
@celinjoseph-x4s6 ай бұрын
Very nice sir Kindly give on continous and differentiability uniform continuity topic sir before june 2024 csir pleaseeee
@ketemawdemeke90 Жыл бұрын
You email is not active i want to ask one question
@parijatnath4765 Жыл бұрын
Sir please upload an pyqs video on lebsigue integration
@easymathematics1341 Жыл бұрын
❤
@memebaaz4005 Жыл бұрын
48.59 min I’m confused how pointwish congt because it ls jo continuous
@techmath8922 Жыл бұрын
Really very happy ... thank you for your great effort
@keyproblemsinhighermathema17789 ай бұрын
If f is increasing on [a,b] then f is BV?
@vikashgupta-xw5np8 ай бұрын
❤❤❤
@hajeeranasreenqueenofscience Жыл бұрын
I have a doubt sir For the pointwise or piecewise continuous,is it enough to check limit exits or it must be both , limit exists and are same ?
@khushiracca49868 ай бұрын
just limit exists is enough....not necessary it should be same
@shrawankumarpatel2148 Жыл бұрын
🙏🌷🌷🌷🌷🙏🌷🌷🙏
@nishayadav9717 Жыл бұрын
Why x is not of BV over (-♾️,♾️)....x is lipschitz over (- ♾️, ♾️) so x is of BV... please correct it sir
@DrHarishGarg Жыл бұрын
Here domain is unbounded , w
@nishayadav9717 Жыл бұрын
@@DrHarishGarg sir x is of BV over (- ♾️, ♾️)
@nishayadav9717 Жыл бұрын
Because derivative bounded throughout the domain
@ankita-111689 ай бұрын
@@nishayadav9717 as you say x is bv over (-infinity, infinity) then it implies that x is bounded over (-infinity, infinity) but x is not bdd over this domain
@ruchibhardwaj9155 күн бұрын
There have been a lot of mistakes in the concepts
@nehajangra63627 ай бұрын
Plzzzz sir phle kud confirm krke bad main hume bataye u r little bit confused