Great sir ...... I enjoy when you are solving questions within 15 sec. in almost every lecture. Thanks sir ❤❤
@shikhasarkar45525 ай бұрын
13:52 tan(3) to tan(8) is infinite for atleast one values as 3+(π/2)
@sarojsi89011 ай бұрын
Good explanation with good collection 👍👍
@priyanjalitripathi440811 ай бұрын
great sir......Thankyou so much for giving all concept of bounded variation in one video.
@ashokisaini842711 ай бұрын
Superb 👍👍👍
@VinayTiwari-hp1pp11 ай бұрын
Nice explanation sir
@RengalakshmiBabu6 күн бұрын
Excellent teaching sir. Thank you so much for your great lecture
@ranusheoran330311 ай бұрын
Super explanation 👍
@Prayosi10 ай бұрын
These lectures are very good. Thank you so much sir.
@ChandanKumar-dn9lz10 ай бұрын
Excellent explanation... Outstanding....in just one hr lecture each and every thing got Cristal clear ....thanks a lot sir jee.
@RS1081111 ай бұрын
❤❤❤ eske alawa kya hi likh den...kyuki sir se accha samjhane wala Aaj Tak dusra koi Mila nhi. Thank you sir. 🙏
@ManishMeena-eo4qh10 ай бұрын
Bht bht dhanyvad guru ji 😊😊😊😊
@user-lo2qx8ow9e10 ай бұрын
Your explanations and the way you clear the concept is just wow...❤
@nehajangra63626 ай бұрын
Mistakes in last bouned variation implies monotonicity Monotonic + bdd is b.v. but ek nbhm k question main closed interval per monotonic diya hua h how it implies that function is of b.v.
@kunjkothiya79905 ай бұрын
At time 34:10. In this question A is correct option.
@RanjangamingYT7477Ай бұрын
Great sir ❤
@KAREN-ye5pf5 ай бұрын
27.22 Problem (b) x=1 is not in the domain itself how can we find tan (pi/2)=infinity and we say it's not BV sir ?
@MANTUKUMAR-nn8kk5 ай бұрын
Gajab sir ❤❤❤
@amankumarbehera6232Ай бұрын
It is very helpful for us sir... keep it up,we are with you ❤😊🙏
@jkmathematics..jitendrakoh85575 ай бұрын
Thanku so much sir love from ❤❤ uttarakhand
@selfsearching199611 ай бұрын
Nice 👍👍
@jaikmthomas503511 ай бұрын
@50:00 Sir if function is not continuous then need not be f is not reimann integrable
@vivekgoswami47411 ай бұрын
Thanks sir , next complex pleasr
@sadzone143411 ай бұрын
Nice
@akarshroy390511 ай бұрын
Thank you sir ❤
@professorragavan97834 ай бұрын
Thankyou very much sir. I did not know about a single concept of bounded variation. After watching your video, it is very useful to me. 🤩😍
@DrHarishGarg4 ай бұрын
You are most welcome
@yashrajtripathi48323 ай бұрын
Apke lecture se pura topic revise ho jata + pyq to ho hi jate h
@positivethoughts641911 ай бұрын
Thank you so much for this important video 🙏🏼...
@vishal-ez8tz8 ай бұрын
at 49:41 function is not continuous only at 1 . Therefore discontinuity at only finite number of points this implies f is riemann integerable .Am i right? plz verify sir
@madhavigandhi3181Ай бұрын
NBHM 2014 For last option sir, we can say f is bounded by f(0) and below by f(1) therefore it is bdd.
@somduttakayal506711 ай бұрын
Thank you Sir
@madhavigandhi31816 ай бұрын
Thank You very much sir, for guiding us selflessly. Your videos are marvellous ! Very useful, clear and doubt solving.
@divyaverma893028 күн бұрын
thanku sir for this
@SahanaKhatun-z1d3 күн бұрын
Sir please give a lecture on lebesgue measure and lebesgue integrable function
@jyotibharti650511 ай бұрын
Thank you so much sir 🙏🙏🙏🙏
@positivethoughts641911 ай бұрын
Sir... Please this type of one by one topic video with short explanation of complex analysis subject...🙏🏼
@mathematicslovers28884 ай бұрын
Thank you sir for giving us very good Content ❤❤
@DrHarishGarg4 ай бұрын
My pleasure... Kindly like, subscribe and share the video with others students too...
@mathematicslovers28884 ай бұрын
Sure sir ☺️ @@DrHarishGarg
@celinjoseph-x4s4 ай бұрын
Very nice sir Kindly give on continous and differentiability uniform continuity topic sir before june 2024 csir pleaseeee
@sanjitha_dhivin6 ай бұрын
Sir if we get a function that asymptotically decreases at 1. how the function will become bounded on [0,1]?
@parijatnath476511 ай бұрын
Sir please upload an pyqs video on lebsigue integration
@ketemawdemeke9011 ай бұрын
You email is not active i want to ask one question
@komalsaini01727 күн бұрын
44:14 option A is correct according to me
@keyproblemsinhighermathema17787 ай бұрын
If f is increasing on [a,b] then f is BV?
@kavitachauhan2071Ай бұрын
. 31:44 f'is bounded variation
@techmath892210 ай бұрын
Really very happy ... thank you for your great effort
@sanjitha_dhivin6 ай бұрын
Sir how sinx becomes monotonous on [0,2phi]?
@hajeeranasreenqueenofscience11 ай бұрын
I have a doubt sir For the pointwise or piecewise continuous,is it enough to check limit exits or it must be both , limit exists and are same ?
@khushiracca49866 ай бұрын
just limit exists is enough....not necessary it should be same
@easymathematics134111 ай бұрын
❤
@steel67911 ай бұрын
Thankyou so much sir,best youtube teacher i ever seen, ❤❤❤❤❤❤keep it sir, short time :=>max knowledge = Dr. HARISH GARG❤
@vikashgupta-xw5np7 ай бұрын
❤❤❤
@memebaaz400510 ай бұрын
48.59 min I’m confused how pointwish congt because it ls jo continuous
@nishayadav971711 ай бұрын
Why x is not of BV over (-♾️,♾️)....x is lipschitz over (- ♾️, ♾️) so x is of BV... please correct it sir
@DrHarishGarg11 ай бұрын
Here domain is unbounded , w
@nishayadav971711 ай бұрын
@@DrHarishGarg sir x is of BV over (- ♾️, ♾️)
@nishayadav971711 ай бұрын
Because derivative bounded throughout the domain
@ankita-111688 ай бұрын
@@nishayadav9717 as you say x is bv over (-infinity, infinity) then it implies that x is bounded over (-infinity, infinity) but x is not bdd over this domain
@shrawankumarpatel214811 ай бұрын
🙏🌷🌷🌷🌷🙏🌷🌷🙏
@nehajangra63626 ай бұрын
Plzzzz sir phle kud confirm krke bad main hume bataye u r little bit confused