This video deals with basics of Slater's Determinant. SUBSCRIBE | SHARE and LIKE this video. Follow me on Unacademy: unacademy.com/u... #SlaterDeterminant #Quantum
Пікірлер: 50
@chemistry-basicstoadvanced7145 жыл бұрын
appreciable effort... it would be better if you start a series of short lectures upto 30 min in which you can describe each and every aspect of a particular topic. i am telling you this because i feel you have a good art of teaching.. of course that will take time but i think you should forget about the nearest exam and think about those who has to serve for long... descriptive topics make a person to gain real knowledge...
@AllBoutChemistry5 жыл бұрын
Thank you for this detailed feedback, I'll definitely try to work on this.
@birkishoremahto17645 жыл бұрын
Provide lec. on variation and perturbation theorem
@sumanmondal65985 жыл бұрын
Thank you so much sir.... Waiting for more videos for upcoming CSIR NET exam...
@AllBoutChemistry5 жыл бұрын
😊
@abdulrauffaiq3 жыл бұрын
Thanks all about your vedios that I need more vedios about quantum chemistry. I am a student the physical chemistry at Kurdistan UUnivesity in Iran. Then I totally need a bout quantum chemistry. Please make a more vedio a bout quantum chemistry by numbering.
@aabidhamid58895 жыл бұрын
Sir please upload more videos on Quantum Chemistry, Ionic Equilbria and Data analysis. Thanks a lot sir.
@AllBoutChemistry5 жыл бұрын
Ya sure I'll try to make videos on them too.
@chemikamesh47885 жыл бұрын
Super..... If u have time means, Go-ahead with variation theorem, perturbation....
@AllBoutChemistry5 жыл бұрын
Sure, I'll try to make videos on them too
@bhoopsingh1535 жыл бұрын
I'm a physics student but this is very useful for me
@ShivamModiOfficial4 жыл бұрын
when we got where ms=0; so why we only add? why cant we subtract?
@angelriyavarghese58634 жыл бұрын
sir can you make a class on hydrogen atom and related questions of quantum mechanics. If you teach ,the difficult topic even become easy.
@chintadasatyavathi49605 жыл бұрын
very nice sir thankyou so much happy to see your lecture
@nehanishad42315 жыл бұрын
Thanks you. Plz make more video important for June net exam. I also follow in unacadmy.
@rosa-fr5fo5 жыл бұрын
Thanks sir ..☺
@AllBoutChemistry5 жыл бұрын
Welcome dear 😊
@sunitasingh-fz3wg3 жыл бұрын
Aab Jake samj aya....thnx a lot sir
@khesalafzal92429 ай бұрын
Thank you. Clear 🙏🏻
@karandoda18354 жыл бұрын
22.30 why we cant subtract? it is also a solution??
@chakrapanipani29125 жыл бұрын
Sir make a full video on quantum chemistry. Because most of organic students facing difficulties in this
@villageyoutubefact96115 жыл бұрын
Really u r my god...
@dishasingh52444 жыл бұрын
Sir june 12 Question me addition kyu hua h substraction kyu ni hua???
@birkishoremahto17645 жыл бұрын
Thanks sir
@keyapal93345 жыл бұрын
Pls make video on huckel determinant and delocalisation energy..
@user-to3fx2do4d5 жыл бұрын
Hello sir. Generally, Slaters Determinant (the anti-symmetric wave function) is not the eigenfunction of the system. Example. Please suppose the system composed of two electrons. Electron 1 is in a hydrogen atom. Electron 2 is in a helium ion He+. rA, rB : the position of each nucleus. The two electrons are far enough. H1=(p1^2/2m)-(e^2/4πε0❘r1-rA❘), H2=(p2^2/2m)-(2e^2/4πε0❘r2-rB❘), H1φA(r1)=EAφA(r1), H2φB(r2)=EBφB(r2). Hartree productφA(r1)φB(r2) is the eigenfunction of operator H1+H2, and lead us the energy of the system EA+EB. But, another productφA(r2)φB(r1) is not the eigenfunction of operator H1+H2. (Please calculate it. It's very easy.) Therefore, the anti-symmetric wave function ψ=φA(r1)φB(r2)-φA(r2)φB(r1) is not the eigenfunction of the system.
@Daisy-zz1tt3 жыл бұрын
Thank you sir
@prateekahuja50865 жыл бұрын
Respected Sir, at 25:13 the selected term doesn't represent triplet state and you misunderstood ms=0 with (2S+1=0). Both are different. ms is related to orbital angular momentum where as 2S+1 is purely dependent on total spin of the electrons present in the system. According to me the correct ans should be c
@aswanipv79195 жыл бұрын
👌explanation sir
@MASChemistry5 жыл бұрын
Awesome..
@lookaway84964 жыл бұрын
What is the difference between Slater determinant and secular determinants?
@Ayush-cs5tw3 жыл бұрын
Why option D even though it is symmetric.
@angelriyavarghese58634 жыл бұрын
at 21:55 in the first question as it is given ms=0 as well as triplet state it is confusing
@poojajoshi20145 жыл бұрын
Thank you sir☺️
@nittansingh75455 жыл бұрын
sir plzzz mention important topics from quantum chemistry
@gauravjyotid.kalita34174 жыл бұрын
Sir if we see the spin parts of the wave functions with spins ms = 0, we took the sum i. e. (Alpha 1beta 2 + beta 1 alpha 2), my question is why didn't we take the difference, i. e.( Alpha1beta2 - beta 1alpha2), because negative part is anti symmetric and positive part is symmetric and both are indistinguishable after finding their linear combination, which naturally gives a constructive and destructive wave function, constructive for plus spin part and destructive for minus spin part. So, being antisymmetric, the negative part was in a better position to be the answer, please clarify Sir?
@akb00144 жыл бұрын
Because orbital part is antisymmetric due to presence of one g and one u.. So over all u
@gauravjyotid.kalita34174 жыл бұрын
@@akb0014 thank you I got it
@samitadutta978 ай бұрын
Kal k exam may slaters determinate ki ans kya hoga?
@piccsirnetchemistry24335 жыл бұрын
Make more video on quantum sir
@aabidhamid58895 жыл бұрын
Dear Sir, Can you please make video on main group elements.... Important topics. Thanks in advance.
@deekshasaini96075 жыл бұрын
Sir plz upload more questions...
@abineshkrishnan8434 жыл бұрын
Please pass some references book...
@sumansarkar80174 жыл бұрын
For the june12 ques why not opt b?
@hemlatabhatt28655 жыл бұрын
Isme 25.15minute m hm subtraction wala combination kyu nhi le rhe,,,, please ans
@gauravjyotid.kalita34174 жыл бұрын
My question is same, why not the subtraction part, because it is antisymmetric so it has more chance to be the answer
@pallavjyotiarandhara5 жыл бұрын
Please tell me the expected cut off for CSIR NET dec 2018