Rate law and reaction order | Kinetics | AP Chemistry | Khan Academy

[@KunaiKrazy]

Why can't HE be my chemistry professor? I actually get this.

[@Nessa-sj9ko]

I don’t comment. But this was one of the best videos ive ever watched. So clear and understandable. My Mcat prep course (BP) couldnt even explain it this well. I was stuck and feeling uncertain. This free resource has literally boosted my confidence. Im so grateful right now.

[@naushadnawaj162]

O my allah..!!..thank you for the essential tutorial

[@NotALie12]

I have a Chem final in 3 days and omg this made everything so clear Thank you 🙌🏽

[@matthew1992]

How did it go?

[@yamaa5190]

yes tell us

[@garchomp3136]

Yeah dawg, how did your chem final from 4 years ago, go?

[@nicholasrodriguez2312]

@@garchomp3136 Yeah dawg, how did your chem final from 6 years ago, go?

[@Pakplays1234]

​​@@nicholasrodriguez2312 dawg how did your Chem final go from 2 weeks ago?

[@Chris-ru7mj]

This was REALLY good at explaining the topic clearly and understandably. Thanks!!

[@Wolfeywolf16]

thank you! this was a big help

[@PratikPatel244644]

the best explaination ever on chemical kinetics ...Bingo U hit the target of my mind Thanx

[@michaelseh]

this guy teaches me so well

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I have A levels chemistry finals tomorrow and you just saved me. *THANK YOU*

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How did it go? 😂

[@naodp]

Blackisthenewgalaxy two years later lmao

[@blackisthenewgalaxy4133]

@@naodp I know lmao 😂

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jimiiin

[@jadeforest7924]

I was freaking out because my lecture notes didn't have anything on "third order rate laws". Thanks so much!

[@hafzasaeed3425]

I was about to give up but this video saved me. Thank you so much for explaining this.

[@t.c.5456]

I needed Zero order reaction explanation. Thanks, bro.

[@euroclydonftw9676]

I think it would be like if you multiplied [A] by 2 but the initial rate would remain the same.

[@francismjenkins]

Such a good job explaining this.

[@OwenGTA]

Fuck taking chem 2 over the summer.

[@billytragyu4679]

Im self studying it so I can go into ap Chem. What about you

[@OwenGTA]

Chemical engineering. Won't bother to go into my background but I don't want to fall behind such that I can take organic 1 and 2 these next two semesters.

[@scolton4life1]

Bro, me too. I'm taking an accelerated 8-week course with one of the toughest professors at my university. Just went over kinetics today. Nice Gnome child meme btw.

[@m7carj]

i'm taking chem 2 over the summer now -_-

[@tbviaemail]

how did it go? doesn't sound pleasant in the least :/

[@masterexplosive]

Very helpful, thanks.

[@AleezaFatima-cf4kq]

this video is truly an amazing concept clearing creation of a genius.

[@DOAInternationalEducation]

Such a good tutor!!!

[@navodadesilva]

You are awesome! Thank you so much!

[@abdulmajeedabdulmajeed449]

bless your soul

[@mahmudassociates8702]

Thank you so much. May God bless him❤

[@raygeorge6097]

absolute legend! xx

[@alexboudakian2148]

Clarified it all! THANK YOU

[@pooriakarimi953]

this guy is SUPERB he reminds me of high school forgoten topics

[@flamingjess]

Thankieeeeew so much this was a big help!!

[@aminahemeran8657]

this way so helpful!

[@oxztox610]

OMG my lifesaver

[@vighnesh5767]

Best video for this ever seen

[@r.abdulwahid9708]

excellent explanation

[@michaelkawamura9296]

Two years later and I'm surprised no one has realized that the title is misspelled. It's "kinetics", not knetics.

[@cutesunnyaegyo]

Thank you very much! You saved me from my report tomorrow!

[@SbongakonkeZondi-f5q]

❤❤❤❤😂i finally understand. thank you sir

[@anthonychineduifedigbo13]

I got a negative and a number in ratio form as my answer eg. -1.765. Any help?

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YOU ARE THE BEST

[@eragon2121]

Is the teacher for organic chemistry Mr. Anderson from Bozeman Science?

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eragon2121 no...he's from alagaesia

[@namasteyogis5004]

amazing video. Thank you!!

[@aaaa8784]

Making MCAT studying 10x manageable. Thank you!

[@TheElectrozoid]

Did you sit it yet? What did you get? When i sat it I got 524, I can give general tips if you want

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woah that's a crazy score congrats...I want to take it this summer. I'd appreciate any tips you have before I really start going hard on the studying

[@kawserferdous689]

Very good lecture

[@NellioStyle]

best explication ever Thanks you

[@audreystaten5528]

thanks for posting this video.

[@Jessica-ql5ji]

Thank you so much , this was very very helpful 💕😩🙏🏾👏🏾

[@Vanessa-zi4og]

Thank you so much

[@VWC7r4Qb4N8x]

WHERE'S SAL?!?!?!!!!

[@CLP97]

lmao, i said that out loud too but then i realized it was mean. he did just as good at explaining this as sal would so i'm happy with it

[@JemuzuDatsWho]

thank you!

[@Silenttreatment44]

The sound is TOO low!

[@giftchonka6562]

Is rate always m/s or it can change?

[@abdullah44925]

do pseudo first order reactions

[@rtgsuper1373]

Thanks very helpful

[@daniahasan5703]

this was a great way to explain this, thanks a lot ! :)

[@xxikxx101]

i love this guy

[@simplydivine746]

THANK YOU!!!!!!

[@ibrahimmuhammad270]

Why there is a difference in the order between different reactants? Why there is a zero order or a first order .. etc

[@KhanhTran-hq1oo]

There's a spelling error in the title. Goddamn it Khanacademy.

[@zijihelium1111]

Khanh Tran Khan Academy is two words. Khan...Academy.

[@itsjosephguise]

where the hell was this when i needed it in 2013

[@alienwalk]

At the end, shouldn't the units for k be mol/L*s ?

[@mohamedgahtan3941]

Great

[@veraj7369]

Thank you so much! Btw you sound like Tyler Oakley

[@heheheiamasupahstarchimera631]

Makes sense.

[@vanessaescalera4117]

saved my life

[@rabyabanory5054]

thanku man it was very helpful

[@carolinelana5527]

HELP! what if the one im trying to work out only has 1 table of initial rates? do i do what you did but compare A and B to that one table of initial rates?

[@DennisBolanos]

You're cute.

[@garen5594]

Anyone know when to use this average rate of reaction = (-1/a)(deltaA/deltat) First order and second order ln(k2/k1) = -Ea/R(1/t2-1/t1)

[@TMPChem]

Hi Garen. For a reactant "a" in a 1st order reaction, { -1/a d[A]/dt = k[A] }. This leads to the 1st order integrated rate law, { [A]_t = [A]_o exp( -a k t ) }. Your second equation comes from the Arrhenius equation { k = A exp( Ea / RT ) }, which describes the temperature dependence of the rate constant. If you plot the natural log of the rate constant versus the inverse of the temperature, you'll find a straight line whose slope is { -Ea / R }, the "activation energy" divided by the gas constant.

[@komalbhardwaj7216]

thanks

[@gersoncocjinjr.8566]

what if concentration [A] stays the same and the rate increased by 2 what would happen in that case

[@nightflares3572]

What u r talking about is impossible, bcz according to rate law, " (initial) rate of reaction " is dependent on "concentration of reactant", meaning that rate of reaction changes corresponding to change in concentration of reaction. There is no way that u keep the concentration of reactant same , but the rate of reaction changes. If it does, then rate of reaction is not in its initial stage ( meaning "t" will not be equal to 0), but some time will be passed after rate of reaction has started.

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kinetics

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I’m so lost

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THANK YOU!!!!

[@sciencenerd7639]

thank you

[@anitarana4835]

Thanks