Razavi Electronics 1, Lec 16, Large-Signal & Small-Signal Operation

  Рет қаралды 96,441

Behzad Razavi (Long Kong)

Behzad Razavi (Long Kong)

Күн бұрын

Пікірлер: 64
@shubhammujumdar9270
@shubhammujumdar9270 4 жыл бұрын
The 6 dislikes are all probably from EDC teachers whose lectures we've skipped to watch these videos.
@anushazehra8183
@anushazehra8183 5 ай бұрын
00:51 Developing a circuit model for the bipolar transistor 04:29 Transconductance measures the strength of a bipolar device in translating a voltage change to a current change 10:19 Transistor can act as a current source and its values can change. 13:47 Finding IC as a function of time 19:59 Dependent current source placement in simplest bipolar transistor model 22:21 Modeling the base current using a diode 28:04 Transistor model replacement and circuit simplification 31:10 Analyzing large-signal and small-signal operation of Razavi Electronics 37:26 Nonlinear functions require mathematical labor in bipolar transistor circuits. 40:27 Analysis of voltage and current in the circuit with a sinusoidal microphone signal 47:45 Large signal operation allows for signals of any amplitude, leading to complex exponential expressions for IC. 50:57 Small-signal operation assumes input signal is small compared to the bias voltage. 57:35 Small signal operation leads to sinusoidal behavior of collector current. 1:00:42 GM times input voltage equals current fluctuation
@yasserel-azab7033
@yasserel-azab7033 9 жыл бұрын
your videos are the electronics' reference to all Cairo university students in Egypt many thanks to you prof. you deserve more than some easy words !
@amritanshusinha8646
@amritanshusinha8646 4 жыл бұрын
Dude correct your statement , "to the world" Love from , India
@mr.ANIMAT0N
@mr.ANIMAT0N 2 жыл бұрын
Greetings from Egypt. Razavi is the iconic masterpiece of electronics to us دكاترتنا زومبيز جنبه والله
@tinotendamarufu4470
@tinotendamarufu4470 Жыл бұрын
my lecturer tells us to watch Dr Razavi s lectures lol. You are a genius, you explain so well
@Peter_1986
@Peter_1986 Жыл бұрын
It is funny how amplifier circuit models look really scary in the beginning, but then after you have been working with them for a while they suddenly start to look incredibly simple.
@phanindrareddyinakollu9310
@phanindrareddyinakollu9310 3 жыл бұрын
I believe this is the best explanation and interpretation of electronics circuits. Thank you so much sir for this valuable knowledge you have provided.
@intelligentdonkey6982
@intelligentdonkey6982 3 жыл бұрын
This kind of detailed observation is beyond my imagination , thanks for broadening our mind..❤️❤️
@anthonysavage1
@anthonysavage1 5 жыл бұрын
You lectures are a work of art---sheer beauty and a delight to behold.
@mostafasaber4491
@mostafasaber4491 9 жыл бұрын
the king of electronics your student from Egypt :D
@shujasohail4401
@shujasohail4401 2 жыл бұрын
Sir I can`t tell how much thankful I am to you .Such Excellent Lectures .So nice of you
@_Mohammad_Muzamil_Bhat
@_Mohammad_Muzamil_Bhat 11 ай бұрын
never seen anyone like him!
@veerappanplays2254
@veerappanplays2254 4 жыл бұрын
you are a saviour sir. Our professor either knows nothing or isn't willing to teach us.
@shivaniits
@shivaniits 3 жыл бұрын
These lectures are beyond amazing , I am only able to understand analog electronics thank to you Professor Razavi 🙏🏼
@mr.ANIMAT0N
@mr.ANIMAT0N 2 жыл бұрын
ICONIC LEGEND! TRULY A MASTERPIECE
@carlosgarzon9896
@carlosgarzon9896 8 жыл бұрын
You were born to teach :)
@viratcheruku
@viratcheruku 3 жыл бұрын
Thank You Dr Razavi. Please keep making such videos
@yaswanthvasu877
@yaswanthvasu877 5 жыл бұрын
You are best best best teacher in my career i have ever seen
@kolmikael8823
@kolmikael8823 4 жыл бұрын
You really deserve a word of PROFESSOR!
@Ser3naaaa
@Ser3naaaa 4 жыл бұрын
The last two minutes of the lecture are GOLDEN!!!
@Pulsonar
@Pulsonar 11 ай бұрын
Last 2 minutes? The whole lecture series is Golden!
@Anointed4Him
@Anointed4Him 8 жыл бұрын
You make it easy as V=IR! Thanks you so much from Canada! It would be great if you do the same for electronics 2!
@EslamMohamedX
@EslamMohamedX 9 жыл бұрын
ur way of explanation is too good to be true :D
@gopikrishnanm5310
@gopikrishnanm5310 4 жыл бұрын
oh god, this man is making my life easier. thanks, sir for such a wonderful explanation .
@muhammadalitehseen7181
@muhammadalitehseen7181 8 жыл бұрын
Thank you soo soo soo much.... You are fantastic Best teacher...!!!
@zarthustramehr8698
@zarthustramehr8698 7 ай бұрын
You>>>>>>>>> my prof.
@boraozturk3634
@boraozturk3634 4 жыл бұрын
i am lovin the "mike"s
@ashikjayamon3963
@ashikjayamon3963 3 жыл бұрын
I can't hope to imagine the life of those people who actually disliked this video. It must be really fucked up.
@klaotische5701
@klaotische5701 Жыл бұрын
At 1:03:02, why (Ic0/Vt) can be equal to gm, isn't gm = Ic0/V0? since Vt = 26mA @300K. ok i probably get it. gm = dIc / dVbe = dIc0 / dV0, which means the equation isn't derived from the previous one, it is a new way of expressing it.
@Itsmeaboud
@Itsmeaboud 7 жыл бұрын
Gretting from jordan
@az-op8oc
@az-op8oc 4 жыл бұрын
Best lecture ,, tq Very much sir
@mnada72
@mnada72 4 жыл бұрын
Beside that this and other lectures are totally awesome 👌 my question: is the model developed in this lecture the large signal model ?
@kristitopollai6948
@kristitopollai6948 3 жыл бұрын
praise papa razavi
@chaitanyakumarkesana9218
@chaitanyakumarkesana9218 9 жыл бұрын
please upload electronics 2 videos plzzzzz plzzzzzzzz
@coolwinder
@coolwinder 7 жыл бұрын
Can you post the link if you find them :)
@KrishnaDN
@KrishnaDN 9 жыл бұрын
fantastic.....:)
@thanoskaraiskos
@thanoskaraiskos 4 жыл бұрын
What does that last Id represent?
@Peter_1986
@Peter_1986 4 жыл бұрын
I think he accidentally wrote the drain current for a MOSFET transistor, which is analogous to the collector current for a BJT transistor.
@Ben-sx5xb
@Ben-sx5xb 2 жыл бұрын
37:00 the equation doesnt work
@Pemmanator
@Pemmanator 2 жыл бұрын
Me too, I have been trying it🤔
@aanur6151
@aanur6151 6 ай бұрын
can't we solve the equation in 34:00 with calculator? actually i guess we can and i solved it and found Ic=0,019A where is my mistake?
@1412dante
@1412dante 4 жыл бұрын
why the intro been change?
@raghuveersinghrawat2
@raghuveersinghrawat2 8 жыл бұрын
nice
@aayushneupane5211
@aayushneupane5211 5 жыл бұрын
why not replacing base emitter terminal by current source? it also looks like it behaves as voltage controlled current source
@Singh-Rajveer
@Singh-Rajveer 4 жыл бұрын
Because If we replace that by current source, Voltage across that would be Vbe and if we change Vbe , then current also...so it would not be a current source....Collector emitter junction has Vce voltage....and by changing that voltage , Ic is constant thats why that is Voltage controlled current source...base emitter junction is not current source.
@user-mj3ef
@user-mj3ef 5 жыл бұрын
Are there lecture notes of the course?
@manvigupta8719
@manvigupta8719 6 жыл бұрын
Can someone help me out wd the steps 57:10 how we can write exp vmsinwt by vt as (1+exp vmsinwt/vt)
@ДенисСами
@ДенисСами 6 жыл бұрын
Same problem here. I think that it need to be calculated as same except Vt in the breckets because we are taking that Vt out of breckets. Please someone give a explanation for that step.
@raghavendrab5395
@raghavendrab5395 5 жыл бұрын
Here, we have followed a simple rule to deconstruct the exp term that is present in the equation. We have (e^epsilon ==> 1+epsilon if epsilon
@abrahamkennedy3016
@abrahamkennedy3016 5 жыл бұрын
Raghavendra B is right, Razavi himself wrote that basic approximation on the board just one line above {i.e.: exp(ϵ) = 1+ϵ if ϵ
@russellteejaymolina6736
@russellteejaymolina6736 3 жыл бұрын
e^x = x+1 will hold if x is much much smaller than 1, say x=0.1, using your caculator is approximately 1.1(1+0.1something something), try also x=. 2,.3, etc.. and notice that as you approach 1 that expression will no longer hold. For small swing razavi considered vm to be small as compare to vt to produced a linear output, and that will hold only for small input signal because in the graph of Ic vs Vbe which is exponential by nature, you can still find a straigh line if you consider a small part of which will correspond to gm as slope of that small part of the curve, hope that will help.
@RamaKrishna-oq4tw
@RamaKrishna-oq4tw 3 жыл бұрын
This is because.. Exp(x)=1 + x + x²/2! + x³/3! + ..... So when x
@ADITYAAGARWAL-o7y
@ADITYAAGARWAL-o7y 3 ай бұрын
the goddddd!!!!!!!!!!!!
@user-mj3ef
@user-mj3ef 5 жыл бұрын
39:41 That is not Vce.
@MinhLe-ho6fj
@MinhLe-ho6fj 5 жыл бұрын
What is the intro music plz ?
@shahnazmrs3529
@shahnazmrs3529 6 жыл бұрын
Over a long time I have been thinking that BJT is a current controlled device, and now this man says it to be voltage controlled. How come everybody modifies electronics as they like?
@Upgradezz
@Upgradezz 4 жыл бұрын
Maybe looking at the credentials of the one claiming might help
@kiromaisus
@kiromaisus 4 жыл бұрын
It really depends wether you are ok if it's linear or not. If it's a current controlled device, then you just have the relation Ic=B*Ib. If you say its a voltage controlled device, then you have that non-linear function. In the end, even the beta isn't constant with magnitude of the currents or temperature. So the system is non-linear and thermically dependent. The good thing is that there are techniques to tie things, so you get an amplifier which is almost beta independent.
@harsh9874
@harsh9874 2 жыл бұрын
@Upgradezz
@Upgradezz 4 жыл бұрын
Brilliance on steroids!!
@appatheskybison3016
@appatheskybison3016 8 ай бұрын
not long kong it was hong kong
@appatheskybison3016
@appatheskybison3016 8 ай бұрын
hahahhahahah
@kolmikael8823
@kolmikael8823 4 жыл бұрын
You really deserve a word of PROFESSOR!
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