The 6 dislikes are all probably from EDC teachers whose lectures we've skipped to watch these videos.
@anushazehra81835 ай бұрын
00:51 Developing a circuit model for the bipolar transistor 04:29 Transconductance measures the strength of a bipolar device in translating a voltage change to a current change 10:19 Transistor can act as a current source and its values can change. 13:47 Finding IC as a function of time 19:59 Dependent current source placement in simplest bipolar transistor model 22:21 Modeling the base current using a diode 28:04 Transistor model replacement and circuit simplification 31:10 Analyzing large-signal and small-signal operation of Razavi Electronics 37:26 Nonlinear functions require mathematical labor in bipolar transistor circuits. 40:27 Analysis of voltage and current in the circuit with a sinusoidal microphone signal 47:45 Large signal operation allows for signals of any amplitude, leading to complex exponential expressions for IC. 50:57 Small-signal operation assumes input signal is small compared to the bias voltage. 57:35 Small signal operation leads to sinusoidal behavior of collector current. 1:00:42 GM times input voltage equals current fluctuation
@yasserel-azab70339 жыл бұрын
your videos are the electronics' reference to all Cairo university students in Egypt many thanks to you prof. you deserve more than some easy words !
@amritanshusinha86464 жыл бұрын
Dude correct your statement , "to the world" Love from , India
@mr.ANIMAT0N2 жыл бұрын
Greetings from Egypt. Razavi is the iconic masterpiece of electronics to us دكاترتنا زومبيز جنبه والله
@tinotendamarufu4470 Жыл бұрын
my lecturer tells us to watch Dr Razavi s lectures lol. You are a genius, you explain so well
@Peter_1986 Жыл бұрын
It is funny how amplifier circuit models look really scary in the beginning, but then after you have been working with them for a while they suddenly start to look incredibly simple.
@phanindrareddyinakollu93103 жыл бұрын
I believe this is the best explanation and interpretation of electronics circuits. Thank you so much sir for this valuable knowledge you have provided.
@intelligentdonkey69823 жыл бұрын
This kind of detailed observation is beyond my imagination , thanks for broadening our mind..❤️❤️
@anthonysavage15 жыл бұрын
You lectures are a work of art---sheer beauty and a delight to behold.
@mostafasaber44919 жыл бұрын
the king of electronics your student from Egypt :D
@shujasohail44012 жыл бұрын
Sir I can`t tell how much thankful I am to you .Such Excellent Lectures .So nice of you
@_Mohammad_Muzamil_Bhat11 ай бұрын
never seen anyone like him!
@veerappanplays22544 жыл бұрын
you are a saviour sir. Our professor either knows nothing or isn't willing to teach us.
@shivaniits3 жыл бұрын
These lectures are beyond amazing , I am only able to understand analog electronics thank to you Professor Razavi 🙏🏼
@mr.ANIMAT0N2 жыл бұрын
ICONIC LEGEND! TRULY A MASTERPIECE
@carlosgarzon98968 жыл бұрын
You were born to teach :)
@viratcheruku3 жыл бұрын
Thank You Dr Razavi. Please keep making such videos
@yaswanthvasu8775 жыл бұрын
You are best best best teacher in my career i have ever seen
@kolmikael88234 жыл бұрын
You really deserve a word of PROFESSOR!
@Ser3naaaa4 жыл бұрын
The last two minutes of the lecture are GOLDEN!!!
@Pulsonar11 ай бұрын
Last 2 minutes? The whole lecture series is Golden!
@Anointed4Him8 жыл бұрын
You make it easy as V=IR! Thanks you so much from Canada! It would be great if you do the same for electronics 2!
@EslamMohamedX9 жыл бұрын
ur way of explanation is too good to be true :D
@gopikrishnanm53104 жыл бұрын
oh god, this man is making my life easier. thanks, sir for such a wonderful explanation .
@muhammadalitehseen71818 жыл бұрын
Thank you soo soo soo much.... You are fantastic Best teacher...!!!
@zarthustramehr86987 ай бұрын
You>>>>>>>>> my prof.
@boraozturk36344 жыл бұрын
i am lovin the "mike"s
@ashikjayamon39633 жыл бұрын
I can't hope to imagine the life of those people who actually disliked this video. It must be really fucked up.
@klaotische5701 Жыл бұрын
At 1:03:02, why (Ic0/Vt) can be equal to gm, isn't gm = Ic0/V0? since Vt = 26mA @300K. ok i probably get it. gm = dIc / dVbe = dIc0 / dV0, which means the equation isn't derived from the previous one, it is a new way of expressing it.
@Itsmeaboud7 жыл бұрын
Gretting from jordan
@az-op8oc4 жыл бұрын
Best lecture ,, tq Very much sir
@mnada724 жыл бұрын
Beside that this and other lectures are totally awesome 👌 my question: is the model developed in this lecture the large signal model ?
I think he accidentally wrote the drain current for a MOSFET transistor, which is analogous to the collector current for a BJT transistor.
@Ben-sx5xb2 жыл бұрын
37:00 the equation doesnt work
@Pemmanator2 жыл бұрын
Me too, I have been trying it🤔
@aanur61516 ай бұрын
can't we solve the equation in 34:00 with calculator? actually i guess we can and i solved it and found Ic=0,019A where is my mistake?
@1412dante4 жыл бұрын
why the intro been change?
@raghuveersinghrawat28 жыл бұрын
nice
@aayushneupane52115 жыл бұрын
why not replacing base emitter terminal by current source? it also looks like it behaves as voltage controlled current source
@Singh-Rajveer4 жыл бұрын
Because If we replace that by current source, Voltage across that would be Vbe and if we change Vbe , then current also...so it would not be a current source....Collector emitter junction has Vce voltage....and by changing that voltage , Ic is constant thats why that is Voltage controlled current source...base emitter junction is not current source.
@user-mj3ef5 жыл бұрын
Are there lecture notes of the course?
@manvigupta87196 жыл бұрын
Can someone help me out wd the steps 57:10 how we can write exp vmsinwt by vt as (1+exp vmsinwt/vt)
@ДенисСами6 жыл бұрын
Same problem here. I think that it need to be calculated as same except Vt in the breckets because we are taking that Vt out of breckets. Please someone give a explanation for that step.
@raghavendrab53955 жыл бұрын
Here, we have followed a simple rule to deconstruct the exp term that is present in the equation. We have (e^epsilon ==> 1+epsilon if epsilon
@abrahamkennedy30165 жыл бұрын
Raghavendra B is right, Razavi himself wrote that basic approximation on the board just one line above {i.e.: exp(ϵ) = 1+ϵ if ϵ
@russellteejaymolina67363 жыл бұрын
e^x = x+1 will hold if x is much much smaller than 1, say x=0.1, using your caculator is approximately 1.1(1+0.1something something), try also x=. 2,.3, etc.. and notice that as you approach 1 that expression will no longer hold. For small swing razavi considered vm to be small as compare to vt to produced a linear output, and that will hold only for small input signal because in the graph of Ic vs Vbe which is exponential by nature, you can still find a straigh line if you consider a small part of which will correspond to gm as slope of that small part of the curve, hope that will help.
@RamaKrishna-oq4tw3 жыл бұрын
This is because.. Exp(x)=1 + x + x²/2! + x³/3! + ..... So when x
@ADITYAAGARWAL-o7y3 ай бұрын
the goddddd!!!!!!!!!!!!
@user-mj3ef5 жыл бұрын
39:41 That is not Vce.
@MinhLe-ho6fj5 жыл бұрын
What is the intro music plz ?
@shahnazmrs35296 жыл бұрын
Over a long time I have been thinking that BJT is a current controlled device, and now this man says it to be voltage controlled. How come everybody modifies electronics as they like?
@Upgradezz4 жыл бұрын
Maybe looking at the credentials of the one claiming might help
@kiromaisus4 жыл бұрын
It really depends wether you are ok if it's linear or not. If it's a current controlled device, then you just have the relation Ic=B*Ib. If you say its a voltage controlled device, then you have that non-linear function. In the end, even the beta isn't constant with magnitude of the currents or temperature. So the system is non-linear and thermically dependent. The good thing is that there are techniques to tie things, so you get an amplifier which is almost beta independent.