Formation of imines and enamines | Aldehydes and ketones | Organic chemistry | Khan Academy

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Khan Academy Organic Chemistry

Khan Academy Organic Chemistry

Күн бұрын

Пікірлер: 17
@shoaib456
@shoaib456 8 жыл бұрын
The person that makes the video is really good explaining concepts, I have been watching a lot your videos for my Ochem class and they are really helpful. Thank you so much.
@brianm.4368
@brianm.4368 5 жыл бұрын
How can you justify a direct nucleophilic attack on the carbonyl carbon without protonating the oxygen first? From what I can see, this reaction shouldn't meaningfully progress once the pH in solution eclipses 6-7 (optimum pH = 4-6).
@ujjwalrawat5105
@ujjwalrawat5105 7 жыл бұрын
Couldn't find a better teacher!
@alexmartinez3683
@alexmartinez3683 2 жыл бұрын
wow, thank you
@almiraalmira1451
@almiraalmira1451 5 жыл бұрын
Makes a lot of sense, thank you so much!
@rachaelmwaura1464
@rachaelmwaura1464 Жыл бұрын
Thank you sooo much ...❤🥺🥺🥺
@RockbandDrummer321
@RockbandDrummer321 6 жыл бұрын
Beyond helpful videos
@zeyrania
@zeyrania 4 жыл бұрын
You saved my ass in organic chemistry, thanks a lot
@miriamramos8873
@miriamramos8873 5 жыл бұрын
Thank you for all your help.
@arianacisneros1477
@arianacisneros1477 8 жыл бұрын
holy stepwise mechanism, batman!
@ariadinjones481
@ariadinjones481 7 жыл бұрын
Hey, was wondering why u kept using the lone electrons on your lsat 2 examples instead of HSO4- Wouldn't the O on the SO4- molecule be a better place to take the H+
@afc90501
@afc90501 7 жыл бұрын
thank you so much!
@tahani91kh80
@tahani91kh80 5 жыл бұрын
What's affecting on reductive elimination
@user-gx7em6dd8n
@user-gx7em6dd8n 7 жыл бұрын
At 5:31, why does acid protonate the OH rather than the N of the carbinolamine? My thinking is that NH3 is a stronger base than OH, so NH3 would be protonated over OH. Can anyone help me reason where I'm going wrong please?
@ujjwalrawat5105
@ujjwalrawat5105 7 жыл бұрын
Amanda Wong it's just being done to explain the product, giving mechanisms is nothing but an estimated guess as to what really the compounds would be undergoing in order to form the final product. In case acid protonates the N of carbinolamine, the final product would be different. It will happen though in nature, but this fact can't be used to explain the product formation here. Hope you get it.
@gmcenroe
@gmcenroe 2 жыл бұрын
Remember the principle of microscopic reversibility. All of these steps are in equilibrium, so yes you could reprotonate the N but then you would be back to the previous intermediate rather then going forward to the desired product. That is why in practice you want to remove water from the reaction mixture for instance by azeotropic distillation which drives the reaction to completion.
@edis9493
@edis9493 3 жыл бұрын
How come oxygen cannot just take the proton from the first amine that attacked rather than taking one from an amine floating in solution... steric reasons? 9:15
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