Redox titrations | Chemical reactions | AP Chemistry | Khan Academy

[@ВладимирАнтипенко-х5ц]

That's amazing! I finally understand what we've done last half year on chemistry lessons, even if i am not a native speaker, the whole stuff is brilliantly explained!

[@joni2417]

I'm German and you explained it much better than my Chemics Teacher. Thank You

[@mmstutorhuraira5672]

just WOW! LITERALLY CLEARED EACH CONCEPT IN 7 MINUTES

[@isharadinho2898]

thanks Khan Academy, i had a lot of problems understanding this topic, thanks to your video now i can.

[@TheRealQuickSilver]

Thank you so much! You just saved me from getting a C in AP chem this semester.

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1 day before my German oral chemistry exam for the abitur...(like a levels) Thank u!

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What's oral chemistry

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@@bulitoni oral exam in chemistry

[@sidrazeitouni5673]

Perfect amazing! I finally could understand the whole concept which is very useful since I am preparing for my exam… BIG THANK YOU!!

[@ZachStarAttack]

THANK YOU! I never get these labs as the other kids do them, now I see the light!

[@arbindapandey1711]

Thank you Khan Academy!

[@vsalukir7019]

I'm having a lot of problems with the way that formal charge seems to be used interchangeably with oxidation state. I'm trying to image the Lewis dot structures and the separation of charges in things like MnO4- and Cr(OH)4- that would allow for the given oxidation states, and I can't do it. This makes me feel like I couldn't solve these problems on my own. I mean how does Chromium give up electrons or charge to hydroxide ions that want to give up charge?

[@tomatochemist]

formal charge and oxidation state are not the same thing. They exchange electrons which affect their charge, but they aren’t exchanging charges

[@Sofia-r2m7y]

Finally found a video that explains redox titration in detail

[@NikRakiqta]

For the concertrarion can't we use the formula C1 x V1 = C2 x V2 C1 - conc. of Fe solution V1 - volume of Fe solution C2 - conc. of MnO4 solution V2 - volume of MnO4 solution So we can solve for C1

[@samantharubinstein2699]

Thats the dilution formula, but there is a similar titration formula ; CaVa/a=CbVb/b, where a and b are the stoichiometric ratio of the reactants, so you could do CaVa/a=CbVb/b where Ca- conc. of Fe solution Va-- volume of Fe solution a=5 Cb- conc. of MnO4 solution Vb- volume of MnO4 solution b=1 Hope this helps!

[@aneeghagunasena5217]

Can't thank this video enough😻

[@janeemmanuel8885]

Aneegha Gunasena HI

[@adityashijikumar1131]

THANK YOU FOR EXPLAINING THE REDOX REACTION!

[@black_jack_meghav]

Thanks khan academy! You guys are great!

[@김정욱-i6o]

이해가 잘되네요 감사합니다 시험 잘 볼게요♡

[@grade7science310]

A good explanation . Thank u

[@fakhrulnawawi9681]

Clearly explained, thanks

[@bokuwatobi954]

Brilliant!!

[@veronicawicker5273]

How do you know that you havn't run out of H+ instead of Fe^2+? How would you know how much acid(H+) to add if the concentration of Fe^2+ is unknown?

[@gonzaloayalaibarre]

I guess an answer isn't of use to you anymore, but I guess someone else can read this. This reaction is supposed to happen in very acidic mediums (high H+ concentrations, low pH) in which the Mn+7 will accept 5 electrons and be reduced into Mn+2. The Mn+7 can be reduced to +2;+3;+4;+6 at different pHs.

[@veronicawicker5273]

Thanks. I'm not in chemistry this semester but I will be taking organic chemistry next semester. This reminded me that I need to review chemistry2 before then.

[@spookywizard4980]

if in doubt add some acid and see if the color persists

[@dibb1e374]

Epic Dr. Skipper

[@chenyijia8836]

Why is the final solution colourless? Isn't Mn2+ pale pink and Fe3+ yellow?

[@johnprice8458]

Iron (lll) which is a product is pale yellow and not colourless, even in dilute concentration!

[@nikhilpatel2442]

Is It possible to titrate a colored solution such as Iron(III) Oxide?

[@HEAR_Instrumentals]

subbed, perfectly explained!

[@Bananakid11]

nice thanks

[@johanan9987]

helpful and handsome!

[@enasabuelqmpoz749]

very thank

[@kumarirashmi8293]

great mam

[@rxa4_tm]

I'm waching this 30 minutes before the test

[@rowenaabbie995]

thanks this really help

[@shreyajain5814]

thanks!

[@amiramostafa7335]

please I need some help how can I compar between potassium permenganate and ceric ions as standard??

[@varlam1568]

It's double standard

[@opslol957]

@@varlam1568 2 years to late

[@varlam1568]

@@opslol957 time is relative

[@sameeragrawal2897]

@@varlam1568 lol

[@mayaaljundi5279]

can we know how many grams (m) of Fe +2 were needed for the titration?

[@satyamraj5570]

Yes you can just use, Mole= Constituent weight/Molecular weight of that Constituent

[@bilalkadri8851]

Isn't Fe3+ brown in colour, so it won't form a colourless solution ?

[@rakshithamrakshitham1627]

How to calculate Ecell for 0 ml addition of titrant??

[@sumairasardar8666]

Isn't this guy the same one that makes math videos. He speaks exactly the same

[@topnup3288]

Plss add more volume

[@xbbyhunny]

when i tried the mv=mv equation, my answer came out as 0.05M Fe x 5 moles = 0.05M of Fe why didnt it come out as 0.2M

[@vsalukir7019]

Okay, let's try this using the MV method. For the KMnO4 it would be .020 M x .020 L = .01 L x X M. Solving for X we get .04 M. But then you have to consider that a molar quantity of MnO4 can react 5 times as much Fe, so you need to multiply the MV answer by 5. And 5 x .04 M = 0.20 M.

[@victoriagong2620]

How in the world is that permanganate molarity so precise?

[@tiagomarques9153]

Why can't you cancel the fives of the irons if they're on both sides?

[@Misha-iw6kd]

Because they are two different ions. On the left he has Fe 2+ and on the right he has Fe 3+

[@tiagomarques9153]

Misha but why does he have the fives in the first place?

[@rkjstuff7402]

Improve sound pls

[@janeemmanuel8885]

rkj stuff hi

[@dr.rupeshkushwah]

redox titration(full hd)/must watch n subscribe kzbin.info/www/bejne/Y5XCdmiem6ykjdk

[@avishrohil929]

I'm confused. How does KMnO4 become MnO4 in the reaction

[@walterwhite4699]

MnO4-is the ion

[@andrewhan2894]

@@walterwhite4699 K is a neutral ion, so really it's just MnO4.

[@nowwhatdana373]

The potassium is considered a spectator ion...it does not impact the reaction and is not included when the reaction is written this way. The same goes for the HSO4- which contributes hydrogen ions. It was sulfuric acid (H2SO4) before, but the HSO4- part of the compound is only a spectator ion.

[@avishrohil929]

@@nowwhatdana373 thankss

[@champagnemoneyabuelo]

why didn't we mention potassium when writing the equation?

[@zack150]

ahmd1221 net ionic equation

[@kingcuber7796]

@@zack150 ahhhhh, now i get it !!

[@Ongneko]

Niceeee

[@spamspam7919]

Going too fast not explaining enough.

[@smp219]

Sir your voice is too loud to hear pls speak loudly

[@اال-ي6ق7ح]

❤❤❤

[@IfeomaOkeke-rw9wm]

WASSCE 2024 PRACTICAL

[@adnansubzibag9353]

sound quality is poor

[@janeemmanuel8885]

adnan subzibag hi

[@AscendXcell]

Shut up ya Indian nigga

[@dr.rupeshkushwah]

redox titration(full hd)/must watch n subscribe kzbin.info/www/bejne/Y5XCdmiem6ykjdk

[@samrosthstein6385]

LOLOL @ azura

[@DennisBolanos]

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[@kelvinhuang4710]

Thank you so much 😊 but you sound so nasally.

[@dhirajadhikari6918]

Abe angrej ke aawald hindi me samjha

[@vasupatel1474]

Angreji sikh le gawar

[@emanbadry8642]

Thank you for this video