Redox titrations | Chemical reactions | AP Chemistry | Khan Academy

[@ВладимирАнтипенко-х5ц]

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just WOW! LITERALLY CLEARED EACH CONCEPT IN 7 MINUTES

[@joni2417]

I'm German and you explained it much better than my Chemics Teacher. Thank You

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thanks Khan Academy, i had a lot of problems understanding this topic, thanks to your video now i can.

[@TheRealQuickSilver]

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[@zachstarattack7320]

THANK YOU! I never get these labs as the other kids do them, now I see the light!

[@moritzroh9361]

1 day before my German oral chemistry exam for the abitur...(like a levels) Thank u!

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What's oral chemistry

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[@Shreyaagrawal_1657]

Khan academy is unmatchable!! Thankyou so much. You guys are lifesaver

[@Sofia-r2m7y]

Finally found a video that explains redox titration in detail

[@adityashijikumar1131]

THANK YOU FOR EXPLAINING THE REDOX REACTION!

[@arbindapandey1711]

Thank you Khan Academy!

[@김정욱-i6o]

이해가 잘되네요 감사합니다 시험 잘 볼게요♡

[@aneeghagunasena5217]

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[@janeemmanuel8885]

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[@black_jack_meghav]

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[@grade7science310]

A good explanation . Thank u

[@NikRakiqta]

For the concertrarion can't we use the formula C1 x V1 = C2 x V2 C1 - conc. of Fe solution V1 - volume of Fe solution C2 - conc. of MnO4 solution V2 - volume of MnO4 solution So we can solve for C1

[@samantharubinstein2699]

Thats the dilution formula, but there is a similar titration formula ; CaVa/a=CbVb/b, where a and b are the stoichiometric ratio of the reactants, so you could do CaVa/a=CbVb/b where Ca- conc. of Fe solution Va-- volume of Fe solution a=5 Cb- conc. of MnO4 solution Vb- volume of MnO4 solution b=1 Hope this helps!

[@fakhrulnawawi9681]

Clearly explained, thanks

[@bokuwatobi954]

Brilliant!!

[@emanbadry8642]

Thank you for this video

[@vsalukir7019]

I'm having a lot of problems with the way that formal charge seems to be used interchangeably with oxidation state. I'm trying to image the Lewis dot structures and the separation of charges in things like MnO4- and Cr(OH)4- that would allow for the given oxidation states, and I can't do it. This makes me feel like I couldn't solve these problems on my own. I mean how does Chromium give up electrons or charge to hydroxide ions that want to give up charge?

[@tomatochemist]

formal charge and oxidation state are not the same thing. They exchange electrons which affect their charge, but they aren’t exchanging charges

[@HEAR_Instrumentals]

subbed, perfectly explained!

[@dibb1e374]

Epic Dr. Skipper

[@Bananakid11]

nice thanks

[@veronicawicker5273]

How do you know that you havn't run out of H+ instead of Fe^2+? How would you know how much acid(H+) to add if the concentration of Fe^2+ is unknown?

[@gonzaloayalaibarre]

I guess an answer isn't of use to you anymore, but I guess someone else can read this. This reaction is supposed to happen in very acidic mediums (high H+ concentrations, low pH) in which the Mn+7 will accept 5 electrons and be reduced into Mn+2. The Mn+7 can be reduced to +2;+3;+4;+6 at different pHs.

[@veronicawicker5273]

Thanks. I'm not in chemistry this semester but I will be taking organic chemistry next semester. This reminded me that I need to review chemistry2 before then.

[@spookywizard4980]

if in doubt add some acid and see if the color persists

[@chenyijia8836]

Why is the final solution colourless? Isn't Mn2+ pale pink and Fe3+ yellow?

[@enasabuelqmpoz749]

very thank

[@shreyajain5814]

thanks!

[@kumarirashmi8293]

great mam

[@johnprice8458]

Iron (lll) which is a product is pale yellow and not colourless, even in dilute concentration!

[@nikhilpatel2442]

Is It possible to titrate a colored solution such as Iron(III) Oxide?

[@johanan9987]

helpful and handsome!

[@rxa4_tm]

I'm waching this 30 minutes before the test

[@amiramostafa7335]

please I need some help how can I compar between potassium permenganate and ceric ions as standard??

[@varlam1568]

It's double standard

[@opslol957]

@@varlam1568 2 years to late

[@varlam1568]

@@opslol957 time is relative

[@sameeragrawal2897]

@@varlam1568 lol

[@sumairasardar8666]

Isn't this guy the same one that makes math videos. He speaks exactly the same

[@mayaaljundi5279]

can we know how many grams (m) of Fe +2 were needed for the titration?

[@satyamraj5570]

Yes you can just use, Mole= Constituent weight/Molecular weight of that Constituent

[@topnup3288]

Plss add more volume

[@victoriagong2620]

How in the world is that permanganate molarity so precise?

[@rkjstuff7402]

Improve sound pls

[@janeemmanuel8885]

rkj stuff hi

[@dr.rupeshkushwah]

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[@bilalkadri8851]

Isn't Fe3+ brown in colour, so it won't form a colourless solution ?

[@spamspam7919]

Going too fast not explaining enough.

[@rakshithamrakshitham1627]

How to calculate Ecell for 0 ml addition of titrant??

[@xbbyhunny]

when i tried the mv=mv equation, my answer came out as 0.05M Fe x 5 moles = 0.05M of Fe why didnt it come out as 0.2M

[@vsalukir7019]

Okay, let's try this using the MV method. For the KMnO4 it would be .020 M x .020 L = .01 L x X M. Solving for X we get .04 M. But then you have to consider that a molar quantity of MnO4 can react 5 times as much Fe, so you need to multiply the MV answer by 5. And 5 x .04 M = 0.20 M.

[@champagnemoneyabuelo]

why didn't we mention potassium when writing the equation?

[@zack150]

ahmd1221 net ionic equation

[@kingcuber7796]

@@zack150 ahhhhh, now i get it !!

[@tiagomarques9153]

Why can't you cancel the fives of the irons if they're on both sides?

[@Misha-iw6kd]

Because they are two different ions. On the left he has Fe 2+ and on the right he has Fe 3+

[@tiagomarques9153]

Misha but why does he have the fives in the first place?

[@Ongneko]

Niceeee

[@avishrohil929]

I'm confused. How does KMnO4 become MnO4 in the reaction

[@walterwhite4699]

MnO4-is the ion

[@andrewhan2894]

@@walterwhite4699 K is a neutral ion, so really it's just MnO4.

[@nowwhatdana373]

The potassium is considered a spectator ion...it does not impact the reaction and is not included when the reaction is written this way. The same goes for the HSO4- which contributes hydrogen ions. It was sulfuric acid (H2SO4) before, but the HSO4- part of the compound is only a spectator ion.

[@avishrohil929]

@@nowwhatdana373 thankss

[@smp219]

Sir your voice is too loud to hear pls speak loudly

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[@IfeomaOkeke-rw9wm]

WASSCE 2024 PRACTICAL

[@adnansubzibag9353]

sound quality is poor

[@janeemmanuel8885]

adnan subzibag hi

[@AscendXcell]

Shut up ya Indian nigga

[@dr.rupeshkushwah]

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LOLOL @ azura

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Abe angrej ke aawald hindi me samjha

[@kelvinhuang4710]

Thank you so much 😊 but you sound so nasally.

[@rowenaabbie995]

thanks this really help