Resonance and Q Factor in Series RLC AC Circuits

engineers.acad...
This tutorial discusses resonance in series RLC circuits. At a particular frequency (resonant frequency), the reactance of the capacitor and inductor cancel, therefore we only have resistance in the circuit. This gives rise to a surge in current.
We are able to select capacitors to effectively cancel inductive reactance at a given frequency. This has the benefit of improving power and efficiency.
To learn more about our HNC programmes please visit: engineers.acad...

[@whoknewinfinity1021]

we are using your lessons in South Africa. Siyabonga (thank you)

[@AtomkeySinclair]

Studying for my Amateur Radio Extra Class exam - thanks for the instruction. Excellent content.

[@JRJunior8624]

I can be pretty critical of some of these, but this one, is outstanding, makes it nice and simple. Excellent work

[@masimbamusodza9045]

Wooow. I hav been going through other explanations and has been very diffficult to understand. You made everyone travel with you through out the presentation with very simplified explanations. I undestand Series Resonance. Off course i will ask my friends to check you on KZbin.

[@raedar7784]

you are way better than my professor when explaining these topics

[@martyrossiter8485]

Very nice explanation

[@brandonmwms]

Fantastic video. Very clear and intuitive instruction. Thank you. (I am studying for an advanced amateur radio license exam).

[@kabandajamir9844]

The world's best teacher thanks sir

[@johnpatrickobra5405]

You can also use XL=XC XL=2π(50)(56x10^-3) XL=17.593 17.593=XC 17.593=1/((2π)(50)C) C=1/((17.593)(2π)(50)) C=180.930microF

[@EngineersAcademyLTD]

Very true - in fact the formula for resonant frequency is derived from the relationship XL=XC that you propose here, since: XL = XC 2*pi*f*L = 1/(2*pi*f*C) f^2 = 1 / (4*pi^2*C*L) f = 1 / (2*pi*SQRT(LC))

[@spelunkerd]

Isn't it interesting that the formula for resonant frequency is the same, regardless of whether it is a parallel or a series circuit. I scratched my head about that, until I realized that you are simply trying to balance the reactance, so you get 1/(2pifC)=2pifL. Isolate and simplify and you get the formula. This applies whether parallel or series, provided parallel resistance isn't very high.

[@italktoomuch6442]

I hope that this channel's views, in future, are most conveniently plotted on a logarithmic scale.

[@EngineersAcademyLTD]

Thanks for the topical comment Niall! Have you seen our tutorials on log graphs?!

[@jammyscoot3646]

Great video!! Very helpful, I was very confused before finding your videos.

[@frankimhof8124]

Very clear explanation. Thank you!

[@aryanviolett4606]

damn... this video is amazing! thanks man :)

[@MclarenF1rocket]

Great explanation ! subbed!

[@user-hy3tr3rx9z]

Thank you sir for this, it is help me a lot.

[@rickyjohnson1342]

You deserve more subs 👍🏻👍🏻

[@hackercop]

This was a great video thanks

[@ElectricalEngineeringApp]

Good video

[@jakemackenzie4936]

What formulas would you use to calculate the current when the frequency value changes?

[@EngineersAcademyLTD]

Hi Jake - this video discusses the method for series RLC circuits at a given frequency: kzbin.info/www/bejne/naKblIhnfsd_m7c

[@Genet665]

Thanks!

[@swethasathuraman3118]

Thanks

[@lovisharora7604]

Increase your volume, rest is excellent 🔥

[@EngineersAcademyLTD]

Thanks - we have hopefully fixed the volume issue in our later videos.