Resonance and Q Factor in Series RLC AC Circuits

  Рет қаралды 69,334

Engineers Academy

Engineers Academy

Күн бұрын

Пікірлер: 28
@whoknewinfinity1021
@whoknewinfinity1021 4 жыл бұрын
we are using your lessons in South Africa. Siyabonga (thank you)
@neo3times
@neo3times 2 ай бұрын
real
@masimbamusodza9045
@masimbamusodza9045 Жыл бұрын
Wooow. I hav been going through other explanations and has been very diffficult to understand. You made everyone travel with you through out the presentation with very simplified explanations. I undestand Series Resonance. Off course i will ask my friends to check you on KZbin.
@AtomkeySinclair
@AtomkeySinclair 4 жыл бұрын
Studying for my Amateur Radio Extra Class exam - thanks for the instruction. Excellent content.
@JRJunior8624
@JRJunior8624 3 жыл бұрын
I can be pretty critical of some of these, but this one, is outstanding, makes it nice and simple. Excellent work
@kabandajamir9844
@kabandajamir9844 Жыл бұрын
The world's best teacher thanks sir
@brandonmwms
@brandonmwms 4 жыл бұрын
Fantastic video. Very clear and intuitive instruction. Thank you. (I am studying for an advanced amateur radio license exam).
@raedar7784
@raedar7784 4 жыл бұрын
you are way better than my professor when explaining these topics
@martyrossiter8485
@martyrossiter8485 4 жыл бұрын
Very nice explanation
@jammyscoot3646
@jammyscoot3646 Жыл бұрын
Great video!! Very helpful, I was very confused before finding your videos.
@johnpatrickobra5405
@johnpatrickobra5405 3 жыл бұрын
You can also use XL=XC XL=2π(50)(56x10^-3) XL=17.593 17.593=XC 17.593=1/((2π)(50)C) C=1/((17.593)(2π)(50)) C=180.930microF
@EngineersAcademyLTD
@EngineersAcademyLTD 3 жыл бұрын
Very true - in fact the formula for resonant frequency is derived from the relationship XL=XC that you propose here, since: XL = XC 2*pi*f*L = 1/(2*pi*f*C) f^2 = 1 / (4*pi^2*C*L) f = 1 / (2*pi*SQRT(LC))
@spelunkerd
@spelunkerd 2 жыл бұрын
Isn't it interesting that the formula for resonant frequency is the same, regardless of whether it is a parallel or a series circuit. I scratched my head about that, until I realized that you are simply trying to balance the reactance, so you get 1/(2pifC)=2pifL. Isolate and simplify and you get the formula. This applies whether parallel or series, provided parallel resistance isn't very high.
@frankimhof8124
@frankimhof8124 5 жыл бұрын
Very clear explanation. Thank you!
@italktoomuch6442
@italktoomuch6442 5 жыл бұрын
I hope that this channel's views, in future, are most conveniently plotted on a logarithmic scale.
@EngineersAcademyLTD
@EngineersAcademyLTD 5 жыл бұрын
Thanks for the topical comment Niall! Have you seen our tutorials on log graphs?!
@ElectricalEngineeringApp
@ElectricalEngineeringApp 2 жыл бұрын
Good video
@MclarenF1rocket
@MclarenF1rocket 4 жыл бұрын
Great explanation ! subbed!
@hackercop
@hackercop 2 жыл бұрын
This was a great video thanks
@aryanviolett4606
@aryanviolett4606 4 жыл бұрын
damn... this video is amazing! thanks man :)
@rickyjohnson1342
@rickyjohnson1342 4 жыл бұрын
You deserve more subs 👍🏻👍🏻
@سفيانجمعة-ن9غ
@سفيانجمعة-ن9غ 4 жыл бұрын
Thank you sir for this, it is help me a lot.
@jakemackenzie4936
@jakemackenzie4936 3 жыл бұрын
What formulas would you use to calculate the current when the frequency value changes?
@EngineersAcademyLTD
@EngineersAcademyLTD 3 жыл бұрын
Hi Jake - this video discusses the method for series RLC circuits at a given frequency: kzbin.info/www/bejne/naKblIhnfsd_m7c
@swethasathuraman3118
@swethasathuraman3118 4 жыл бұрын
Thanks
@Genet665
@Genet665 4 жыл бұрын
Thanks!
@lovisharora7604
@lovisharora7604 2 жыл бұрын
Increase your volume, rest is excellent 🔥
@EngineersAcademyLTD
@EngineersAcademyLTD 2 жыл бұрын
Thanks - we have hopefully fixed the volume issue in our later videos.
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