"He knows a lot about the science talks! Professor Dave rocks!!!" thank you so much I used to struggle in ochem and now this has been my favourite subject!
@kristinakafle42492 жыл бұрын
Studying the day before my mcat, and this was the easiest and quickest explanations I could find and understand. Thank you SO much!
@andy06952 жыл бұрын
How was the exam????
@kristinakafle42492 жыл бұрын
@@andy0695 killed the chemistry/physics section! can't speak so much for the rest LOL
@CloudyGumption9 жыл бұрын
I am a great fan of this reaction mechanism, I do believe the OH is eliminated after electrons are pushed to the carbonyl oxygen in that last step. Like an E1cB
@ProfessorDaveExplains9 жыл бұрын
David Wells yes indeed, the last part of an aldol condensation is an elimination, as shown here!
@thebilla65689 жыл бұрын
One of the best on KZbin. Thanks.
@Mary-cv2fm8 жыл бұрын
Professor Dave!!!!! I love your videos. They are extremely helpful, thank you for making them!!
@ProfessorDaveExplains8 жыл бұрын
+Mary Bass my pleasure! spread the word!
@YuliyaTsishchanka5 жыл бұрын
I have never left a comment on a video before but you are literally the best ever teacher on youtube and I wish you were my teacher-which you kind of are! Thank you so much for this!
@ProfessorDaveExplains5 жыл бұрын
thanks kindly :)
@sevgiarslan18274 жыл бұрын
@@ProfessorDaveExplains Can I have your email
@sydneyesposito85727 жыл бұрын
Thank you so much for all your videos! You explain concepts so well, I always look for your videos before anything else when I need help. :)
@thirishar12373 жыл бұрын
We got more information with less span of time....thank you very much prof.dave 🤗
@tyedyegurl19995 жыл бұрын
T-5hr until my orgo exam and Dave out here saving my ass once again... not the hero I deserved, but the hero I needed.
@shrishtibhattarai83196 жыл бұрын
Thanks for making it so simplistic.
@mshisha9 жыл бұрын
This is wonderful. Thank you so much for your time!
@pierce12345678914 жыл бұрын
2020 coronavirus pandemic-sees professor dave cough-NO
@quentinmcilvaine44474 жыл бұрын
you're a solid guy, Dave.
@momijidoll139 жыл бұрын
WHERE were your videos when I was in first year?? Your videos are so effective and your style of simplifying complicated concepts is beyond brilliant. Would it be possible for you to make some videos on retrosynthesis? and maybe the organic chemistry of palladium? Thank you
@ProfessorDaveExplains9 жыл бұрын
momijidoll13 I will absolutely add retrosynthesis to the list of next topics! Thanks for watching!
@omayma35428 жыл бұрын
Thank you for that simple explanation !
@sudhagupta57194 жыл бұрын
Easy and good explanation
@giulialanza-billetta81338 жыл бұрын
You're honestly the greatest! Thank you :)
@nouralzahraafawaz88606 жыл бұрын
I have to thank you from the bottom of my heart 💜 I have been studying through your amazing videos since 3 weeks! My exam is on Monday and I hope to do well! Wish me luckkk🤞🏻
@PunmasterSTP2 жыл бұрын
I know it's been awhile, but how did your exam go?
@Emma-js7ui9 жыл бұрын
Thanks! This was super helpful
@Hauskkia7 жыл бұрын
Awesome tutorial! It is a very cool reaction indeed.
@Kittendu187 жыл бұрын
OMG thank you so much ! This video is very useful, and it's short, effecient. Thank you Prof
@PunmasterSTP2 жыл бұрын
Robinson annulation? More like "This is some great knowledge and information!" Thanks again so much for making and sharing such amazing videos.
@shaikhfirdousmuskanR8 жыл бұрын
awesome teaching ...thanku so much professor u have helped me alot for my xams.
@drgracional9 жыл бұрын
Thanks from Brasil. Great job, Professor.
@lyzzts9 жыл бұрын
Hi, sir. In regards to your mechanism at around 3:51 , I was wondering if there should be an arrow showing the movement of the bonding pair of electrons to the oxygen that will later have the negative charge?
@ProfessorDaveExplains9 жыл бұрын
+Alyaa Hakim ah yes, you're right, it seems i've omitted an arrow!
@Thaumius2 жыл бұрын
4:35, isn't OH- typically a bad leaving group?
@KoolViking39 жыл бұрын
Brilliant! Thanks!
@kirubabowneeth39287 жыл бұрын
thank you sir.
@AlexzandriaL4 жыл бұрын
What is the overall reaction? I mean what do we write as the reagents for this rxn?
@celinekim4328 ай бұрын
For the step after the tautomerism step, would the base used not have to be an LDA or stronger base to give the kinetic/less substituted product?
@suhaibaziz4597 Жыл бұрын
Thank you Pro.
@elifacet38096 жыл бұрын
Thank you very much for your effort
@kacubemember3077Ай бұрын
Damn the exact question came in my exam, thanks prof!
@simonbedenbender30875 жыл бұрын
Just watched two of your videos. They are very good and well explained. I was looking for some explanation for some name reactions during studying for my organic chemistry II examn. The script was very bad but just spending five minutes on your video gave me all explanation i needed thanks!! Just giving the links of your vids to the students would be better than reading the scrpit ;) Thanks from Germany!
@PunmasterSTP2 жыл бұрын
I know it's been a long time, but how did your exam go and how have your studies gone since then?
@simonbedenbender30872 жыл бұрын
The exam went well, I got a pretty good mark in the oral exam. But I havent got much contact with OC since then because I actually studied biochemistry, OC was just a subject we had to do
@PunmasterSTP2 жыл бұрын
@@simonbedenbender3087 I'm glad it went well! How did the rest of biochem go, and where did you end up career or academic-wise?
@nouryassin77217 жыл бұрын
Thank you professor 🤓
@DarlinaLiu8 жыл бұрын
How do you know which carbon to deprotonate (which enolate to form) during the intramolecular aldol condensation step? Also, at the end, do we really have hydroxide as a leaving group? Not water?
@ProfessorDaveExplains8 жыл бұрын
+Darlina Liu good questions! first, it's absolutely true that you could enolize on either side of the carbonyl for the second step, but a four-membered ring is much less likely to form, so enolization on the inside of the carbonyl might just be reversed to reform the carbonyl until enolization occurs on the other side, at which point the ring might snap shut to get the six-membered ring. and yes hydroxide is a reasonable leaving group in strong basic conditions, if there's a bunch of hydroxide swimming around in solution one more won't hurt.
@DarlinaLiu8 жыл бұрын
+Professor Dave Explains Thanks for the thoughtful replies, Professor Dave!! Your videos are so so helpful, wish I discovered them earlier!
@buckyrx76 ай бұрын
So this is kind of similar to a Dieckmann condensation being an intramolecular version of Claisen condensation?
@mrscience23146 күн бұрын
thank you sir
@ruger519953 жыл бұрын
Isnt OH a bad leaving group though?
@ProfessorDaveExplains3 жыл бұрын
in strongly basic conditions it's no problem
@claudiafeola92156 жыл бұрын
In the first step the enolization happens on the more substituted carbon. Why isn't the reaction controlled by a kinetik mechanism in basic conditions? (why not an attac on less substituted carbon?)
@ProfessorDaveExplains6 жыл бұрын
Like I say in the video it's just because that proton is the most acidic! The conjugate base has resonance across two carbonyls.
@youssefnaitlaarbi9226 жыл бұрын
thanks from morocco ... great professor
@chemicalscience24453 жыл бұрын
Really so helpful
@mariamejaz3429 Жыл бұрын
JazaqAllah Sir
@a1738k5 жыл бұрын
Will you get a racemic micture? The methyl group can be a wedge or a dash correct?
@ProfessorDaveExplains5 жыл бұрын
oh good question, i suppose so, i would probably have to draw it out with chairs to know for sure
@a1738k5 жыл бұрын
@@ProfessorDaveExplains Alright, I was thinking the enolate can attack the Michael acceptor from any face (re so si) so you'd get a racemic mixture.
@ProfessorDaveExplains5 жыл бұрын
well at that stage the molecule would be achiral because its meso, but the product is chiral, so i'm actually not positive if there is anything that would favor one isomer over another, there may be information in the chairs
@a1738k5 жыл бұрын
@@ProfessorDaveExplains Yeah exactly, thanks!
@TinaPhuong-hu8rc23 күн бұрын
Thank you so much, Professor Dave. You have saved me in ochem 2 when my professor doesn’t teach 😅! 😊
@alaanader99134 жыл бұрын
Thanks so much you really helped me 🖤
@heshamnasher49972 жыл бұрын
Thank you very much for the good and clear effort :)
@kainatshaikh57817 жыл бұрын
you're so amazing!
@shanemichael94045 жыл бұрын
Hey Prof. Dave. Me again. Pestering you by now probably. But, will be happy to donate by next month hopefully as I do deeply appreciate you answering my ridiculous questions. On the tauteromerization part (probably spelled it wrong) why does the OH grab that hydrogen on Carbon 4 shortly before the ring is made? I believe it's Carbon 4, it appears to be primary with 3 hydrogens. Anyway why that Carbon and not any on the other Carbons? Not surprised that curiosity hasn't killed me yet !
@ProfessorDaveExplains5 жыл бұрын
so it's the pi bond that grabs the hydroxyl proton, whereas the OH sigma bond because a CO pi bond. check out my tutorial on michael addition, i more thoroughly discuss tautomerization!
@christinamelita24126 жыл бұрын
sir how do we know whether the product will form ring or not. why can't it remain linear sir.
@christinamelita24126 жыл бұрын
sir I mean that how do we know for given two reagents, Robinson annulation will take place.
@joanad12462 ай бұрын
Thank youuuuuu❤❤
@sukainaalherz355410 жыл бұрын
I like your way in explanation Is there any video in this account about (syn) and (anti) or (Si/ Ri).
@GingerRootss9 жыл бұрын
Why doesn't the Robinson Annulation always happen because the product of a michael addition creates two carbonyl groups that could react as such?
@ProfessorDaveExplains9 жыл бұрын
Eva C well it depends on the structure of the electrophile, it needs to be able to form a six-membered ring in the transition state of the second step, so if there is a phenyl or tert-butyl group alpha to the carbonyl it won't work. there could also be issues due to sterics. but fundamentally you are correct that many michael additions could result in subsequent robinson annulation.
@ismailsarenkapic4855 жыл бұрын
Very helpfull tnx, can u pls next time film tje whole rection when u are done so we can see it
@jasonhowe50065 жыл бұрын
beast.
@korangalalita12296 жыл бұрын
Thanks sir
@sciencenerd76392 жыл бұрын
fascinating
@caseyhagg26577 жыл бұрын
Thanks for the clear explanation! I am curious what the significance of your tattoo is?
@ProfessorDaveExplains7 жыл бұрын
it's the diagram from which the parsec is derived!
@msathishkumar11597 жыл бұрын
Sir, it's very useful learns organic chemistry mechanism sir. I have one question about the Robinson annulation reaction sir. That is what is the stereo chemistry behind in the last water molecule elimination step sir
@ProfessorDaveExplains7 жыл бұрын
hmm, no stereochemistry that i can think of, it's just an E2
@niranjanpradhan12527 жыл бұрын
nice video sir
@SkudzYNBuddies8 жыл бұрын
how come you use hydroxide as a base? i've been taught to always use sodium ethoxide for these mechanisms and michael addition itself
@ProfessorDaveExplains8 жыл бұрын
+its Skudzy hydroxide is the classic, that's what i typically see. methoxide or ethoxide are fine too. kind of arbitrary i think.
@SkudzYNBuddies8 жыл бұрын
okay thank you for the answer!
@patmahgroyn68689 жыл бұрын
can you do a robinson annulation without a di-carbonyl reagent?
@ProfessorDaveExplains9 жыл бұрын
steven schulster I wouldn't think so, as you need one carbonyl to enolize for the first step, and the other to act as the electrophile in the second step.
@ayoub41446 жыл бұрын
merci beaucoup
@you-ik4oc5 жыл бұрын
Nice
@abdulbasit-qf7bb9 жыл бұрын
nice sir
@kusalseven35636 жыл бұрын
i think it doesnt stop there
@annagmg2303 жыл бұрын
J'adore merci beaucoup
@dancingdodo27687 жыл бұрын
If I pass my organic chemistry exam on Monday, I'll have you to thank!
@PunmasterSTP2 жыл бұрын
I know it's been a while, but did you pass?
@dancingdodo27682 жыл бұрын
@@PunmasterSTP to be honest, I can't remember if it came up on whatever exam it was for, but I sit here waiting to start a PhD in polymer chemistry in April so I can say the video is at least good enough not to have you fail
@PunmasterSTP2 жыл бұрын
@@dancingdodo2768 That's amazing, and that sounds like an awesome field to do research in! Is your ultimate goal to go into industry, stay in academia, or do something else?
@dancingdodo27682 жыл бұрын
@@PunmasterSTP the PhD is sponsored by the company I work for but afterwards, I don't really have a preference. I just want to do research. I haven't got the patience for the stupidity of commercialisation
@PunmasterSTP2 жыл бұрын
@@dancingdodo2768 I gotcha. Please forgive my ignorance, but what type (or subtypes) of polymer chemistry are there? Which one(s) would you hope to conduct?
@claudiafeola92156 жыл бұрын
sei un mago
@n.s.14969 жыл бұрын
I gotta tell my university about you...
@ProfessorDaveExplains9 жыл бұрын
+Nickolai indeed you must! spread the good word.
@n.s.14969 жыл бұрын
Any chance you could post organic chem videos on phenols, amines to amide conversion and Mass spect? :)
@n.s.14969 жыл бұрын
Oh and you are absolutely wonderful. The text book is way to thick in its terminology to understand
@ProfessorDaveExplains9 жыл бұрын
+Nickolai i will add to the list! i definitely plan to do all forms of spectroscopy/spectrometry.
@kaustavdas68298 жыл бұрын
hi, i really like your videos and i am having a hard time understanding Hofmann exhaustive methylation . Could you please upload a video explaining it's mechanism and everything.
@ProfessorDaveExplains8 жыл бұрын
+Kaustav Das nitrogen lone pair does SN2 on methyl iodide until no more methyls can be accommodated!
@kaustavdas68298 жыл бұрын
+Professor Dave Explains if the nitrogen lone pair is in resonance with the ring then what happens?
@ProfessorDaveExplains8 жыл бұрын
+Kaustav Das it can still be methylated, it will just probably be less kinetically favorable and also bear a formal positive charge in the product.