Equilibrium 2--Calculating Equilibrium

[@berezker]

God bless you Understood 3 hours worth of class in a 17 minute video

[@Randomly.cliche]

bro thats nothing ... he just saved me from my exams, chem is my weak spot.

[@goldenkill3298]

This is my Chem teacher lol

[@secrethandlehuhu]

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Freedom that's an acreiate statement ....another one...another one ....another

[@wolvesbane1748]

one

[@syedasalwa2391]

Your the best chemistry teacher ever! And I hate chemistry but the way you explain makes it all so easier and simplerYour a genius, thanks for uploading this!!

[@saytorz]

oooooh my. Im up all night preparing for my chem finals. While in class i just didnt understand the concept. And you worked different types of questions. It was clear. You're a life saver. Thank you. ^_^

[@JJ-Chantel]

You will never know the magnitude of how much this video helped me. Thank you so much

[@waodaaaaa]

literally saved my chemistry grade, god bless you !!!!

[@justinchaney7445]

thank you so much, I have a 100 point assignment due tomorrow and have been searching the internet for so long. you saved my life.

[@kiraivanich1264]

Thank you!!! I was on the verge of tears before I watched this.

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First conditions was so much helpful from me.. Best wishes for you from Bangladesh

[@Randomly.cliche]

i love how u include sarcastic comments and make this kind of fun then how boring and sleepy others do

[@jaidmubanga5328]

Thank you for this wonderful explanation 🎉❤

[@josephd8404]

thank you, seriously. i finally solved a hw problem i've been stuck on for hours simply by watching 10 minutes of this video.

[@amitbanerjee1325]

Searching for how to solve these for 1 week finally got it..god bless you

[@Anna-zy6hk]

i watched so many videos and didn’t get how to do it until this one! thank u sm!

[@DM77333]

Honestly, this is such a fun explanation for what I thought would be a super boring topic so thank you!

[@GinoTheSinner]

Thank you for clarifying the molarity bit. Of the ~100 videos I've watched this is the first one that specifically mentions that only M's should be in the ICE table.

[@hielenaug]

YOU! are the best!! thanks a lot! why can't I ever get a great teacher like you? I understood everything so clear!

[@ethanlawrence5502]

Thankyou for this video. It really helped me. You might just have saved me.

[@laurasalvaggio113]

Thank you so much this is the only video I've watched on this subject that actually explained it thoroughly.

[@kgaogeloakaaka7393]

Wow... You actually explained this better in 17 minutes and that's what my teacher couldn't do in 2 weeks.. 😂

[@emmanuelkalunga7916]

Well explained and you are just a good teacher

[@jagritbudhiraja6391]

thank you i wish i had a teacher like you

[@preidbass]

best explanation of this I've found...cheers bro!

[@luvzlife1]

If someone told me i would understand ICE BOX i would tell them they are crazy! Thanks you Mr.Seigel!

[@sentoiben]

Bro! Best 17:40 of my KZbin binge ever!

[@shamri4436]

thanks for the help! got at 67 on my test!! my parents love me again!!!!!!!

[@Wolfeywolf16]

Thank you so much! I was really dreading the quadratics equation and you just elminated so much of my anxiety

[@meganysc5246]

thank you so much!!! I finally understand what my teacher was trying to teach for a week:")

[@WAZZA1235]

Thanks for saving my exam.

[@abby4899]

Thanks a gazzilion yo! :) I adore peeps that teach using examples!

[@YoungFudge3]

youn the mannn i understood everything in this 17 minute video

[@donodestro4179]

i love you...you made me understand the ICE table...thanks

[@kayla7772]

Thank you so much for making this video, Mr. Seigel!

[@francieemanzano2034]

Very useful information and he's very good at explaining it. Thank you.

[@adityasaxena7374]

Very well explained keep uploading more videos

[@riak401]

Thank you soooooo much!!! You helped me wayyy more than my teacher :))))

[@kevingunawan3913]

isnt the 6:55 2H2O suppose to be 0.1 m at initial, why is it at 1.0?

[@jaidmubanga5328]

He might hv made a mistake

[@wallacet4789]

Appreciate that, very clear explanation and it helped me very much ! Hope i can answer the question for exam tomorrow!

[@lenzfaraday2077]

Thank you so much!! I missed the class on ICE so had to keep up

[@24OakRaiders]

Amazing!!!! More power to you. I love your teaching mechanism. Thank you.

[@Stelnice]

isn't Kp=Kc(RT)^change in n (where R is 0.0821 L.atm, T is temp in kelvin, and change in n is mol of gas products-mol gas reactants) ?

[@blankblank8176]

YES

[@michellengu3946]

good explanation man! better than my current teacher >

[@gangsterkami1]

Fantastic method. However I prefer to think of out logically and use ratios to work this out. I kind of wish I knew this method in the first place, I suppose thinking of it logically is the superior way as it shows your understanding of equilibria.

[@ankithrao7215]

Great explanation, but just one question: is Kc the same as Keq?

[@San-pu1gn]

jst awsummm👍👍

[@aprilharris8933]

Thank you so much your students are so lucky.

[@Rodger16]

Very good video to learn

[@majan374]

Why would you use square brackets on the Kp expression when they mean moldm^-3?

[@CoolVideoWatchpersn]

bloody fantastic thank you so much for doing this video! fantastic explaination

[@mongalo92]

You're a life saver!!!!!!

[@lindeeslife6513]

At 10.01 , is the unit for Kc M^-1 or M? Since you didn't include the unit when you calculated the final answer which was 0.16 >< thanks!

[@justinchaney7445]

+Shalinda Beevi M

[@WAZZA1235]

I got something quite odd when redoing the question at 14:30 myself, with another technic. What I did was when we were at the 64 = [HI]2 / [H2] * [I2]. I simply placed the 2 réactants (the 0.2 * 0.2) on the side of 64. So I have 64 * 0.2 * 0.2 = [HI]2. So i square root the result of 64 * 0.2 * 0.2 and get the answer 1.6. How come the equilibrium for 2HI, when calculated (as I just did), is equal to 1.6 rather than the 0 that is expected?

[@harikeshkaul5584]

Very good explanation. Thank you.

[@favourizuagba231]

Thank you sir. This video was helpful

[@Dev3z]

Thanks bro love from India

[@westsideconnection1258]

Thanks you’re a great teacher!

[@pastorpretty4121]

Does reactants always go down if for reverse reaction????

[@muskaanseher4144]

Thank you so much, you are a great teacher☺☺

[@aidanbailey6337]

Brilliant (taking Gen Chem 2: college).

[@nerdyblackgirl_x]

do you have a video that goes deeper into the ratio thing?

[@Kayla-ns7lm]

Thankyou, I found this really helpful :) really appreciate it

[@rhussain3180]

Thank you! You will help me get through chem eng! :D

[@surat8591]

Awesome!!Thank you so much!!!

[@TheIsotopes]

For the last problem why was it (2x)^2 ???

[@saladmona]

so for question #2, 0.16 is the answer and it ends there?

[@jumuahalabsbek731]

Well executed

[@iEpicness2k10]

This helped me so much! Thanks!!!!!

[@mickaylamihailovic4613]

Lifesaver!! Thank you soooo much :)

[@jamiecoleman773]

Do you do it the same same if your two starting moles of H2 O2 were different? say instead of them both being .200M, H2 = .033 and O2= .0081 what would you do?

[@justinchaney7445]

+Jamie Coleman The reactants (which I assume you meant H2 and I2, not that it matters) would have to change by the same amount so they still would change by "-x". 2HI would still increase by "2x". Therefore you would plug in these new values instead of .2. From there you would simplify the "64=" equation until you reached 60x2−2.6304x+0.017107=0. After that plug in the quadratic formula(If you don't know what that is go to this site here www.purplemath.com/modules/quadform.htm ). That should give you your answer for x. You will get two answers (.0359 and .0079) and it must be .0079 because .035 is greater than your H2 value. then just apply this to your ICE table giving you an HI value of .158. That is as far as my understanding is of this topic.

[@saimakhankhan2517]

How can u calculate Kp when you are given moles. plz someone tell me a link or something.

[@143BabyDoll143]

Wouldn't HI be 2(times) 0.32 making it 0.64

[@justinchaney7445]

+143BabyDoll143 Probably a little late to tell you, but know because when he multiplied .16 by 2 that was due to HI having a constant of 2.

[@crystal_fairy-n1u]

sir i've a problem in this chapter and i want to send u a question so i'll be pleased if u help me..

[@m3h3d1997]

thank you so much i highly appreciate that

[@beautyprincess6454]

Thank you very veryyyyy muchhhhhhh you help me alot

[@Jessiey404]

What about a limiting reagent?? How does that work it's way into the equilibrium???

[@marcseigel5949]

LRs don't get involved in Equilibrium because the reaction never goes to completion.

[@carefull8365]

Is this for as level?

[@thashen1690]

great video, thanks

[@carlosadams5478]

i do wanna say this but you are awesome

[@calseed]

where did u get 0.38 from tho ?

[@adityasaxena7374]

Please Add Questions Of Degree Of Dissociation.

[@peterkabwe9648]

This is awesome

[@shudidesai]

You da real OG

[@AbsurdoMX]

Eres mi dios.

[@sidarthavader9062]

Thanks, it helped a lot! :)

[@BunnyEthan]

how do you get the 8x in the 1.6-8x=2x?

[@TuyisengeJonas-id9sw]

I can't find where the -o.38 was got from

[@daretoawesome]

Since they tell you what the equilibrium concentration is you can subtract to find the change.

[@Jenny-mi3zq]

Made me laugh a lot 😂 thanks 👍

[@romies2999]

Your the best thanks

[@yuganeswarman8416]

Thank you internet

[@hafsaabid7454]

Thank you so much!!

[@Creacion83]

Calculate the equilibrium constant using the following concentrations [H2CO3] = 7.75 x 10-4 M and [CO2] = 5.65 x 10-1 M.

[@jagritbudhiraja6391]

what's the reaction?

[@trailblazer_98]

Thank you sooooo much!!!!!!

[@remiben-davies5781]

Unfortunately, this does not work on my ALEKS homework

[@TheJinxism]

Brilliant

[@mohammadhussainshah1475]

Thank you so much

[@jrod8807]

Subscribed

[@abigailjackson9288]

thank u so much!!!

[@toivomvula]

Thank you.

[@davidorange6397]

interesting 2 weeks of lecture in one video lol

[@alisaclark4560]

Thank you!!!