Sequence And Series (Summation of Series) || IIT-JEE ADVANCE 2022

[@krishsharma7088]

Type 3 : S infinity = 1/12

[@SONGS_CORNER]

-1/12

[@shūubhsóní]

Yes bro my also same

[@shūubhsóní]

​@@SONGS_CORNER no its 1/12 maam

[@lakshay3745]

Galt bhi confidence se bolte ho😂​@@shūubhsóní

[@ts9dream]

​@@lakshay3745 jo video me question diya hai uska s infinity arha hai 1/12 dusra banda ramanujan wala bata rha hai s infinity

[@krishna_000]

The problem is that in my coaching they don't taught me like this,they expect that this only top student batch A1 can understand because they have more brain .. But the way you teach I can understand everything clearly.

[@adityaagrawal5407]

u r a1

[@aditsaini5094]

​@@adityaagrawal5407 a100

[@yash7144]

Sir please do complex numbers next. Especially geometric application of complex numbers. Great content as usual thank you for your work.

[@anirudhsrivastava6042]

Yes i agree

[@anshumanarya9215]

Yess please 🙏

[@krishna_000]

Yes please

[@i.am.harsh.]

Yes.

[@friendlyneighbourhoodbrodude]

Yes agreed.

[@saurabhrana4160]

Type 6 is a question of the IOQM Examination. Beautiful indeed!

[@su-bro]

Tip for type 2: if differences forms ap then write an²+bn+c then we can substitute the value n=1,2,3.. to find a,b,c then type 1 If forms gp thrn ar^n+bn+c where r is common ratio and then again substitute n=1,2,3..... To find abc then again go to type 1 ;) Again another tip in telescopic series rather than writing by substituting n=1,2,3.... We can try to find r,r+1 or r-1 or anything between the seperated terms then we can substitute r=-1 if r+1 in r (precisely substitute in the smaller one) Hope it helps and it works everywhere. Anyways type 6,7,8 one really helped me

[@wanwanmlbb7100]

We know this shit

[@AKASHJEEASPIRANT26]

​@@wanwanmlbb7100🕺🕺🪩💃

[@navalgurjar2070]

Loving it sir. Mujhe ye channel 2 yrs phle kyun nhi mila.. Advance se just 20 days phle I found it... It's awesome sirr

[@kshitijverma7238]

been preparing for jee from last 3 1/2 years how the hell i never found this channel before 😭😭

[@tirtheshjadhav1898]

3 and a half years? Damn

[@jeeadvanced10]

This was the holy pill of wisdom i needed to solve questions of series summations. Thankyou sir🙂

[@himanshusharma4268]

such a fantastic lect on sum of series for jee adv

[@amoghsrivastava6324]

thank you sir but have a regret for not exploring this channel before

[@RZMATHS]

Thank you so much .... Please like and share the video so that many students get the benefit out of these videos.

[@amoghsrivastava6324]

@@RZMATHS already shared in all my coaching groups and all extra channels :)

[@shreyanshmishra6971]

@@amoghsrivastava6324 unacademy....?

[@amoghsrivastava6324]

@@shreyanshmishra6971 yes and are you albatross ??

[@temochnu]

I am got admire of u sir glad to see a wonderful mathematician sir

[@chromeee_7421]

in the last problem.. we can just add and substract 1 in Sn.. then substract Sn from (1+Sn)-1... so we get 3Sn-1=0 for n= INFINITE

[@ravibaraskar6007]

thanks sir aap probability or application of derivatives ke bhi tricks and advance problems upload kijiye ..

[@yadav_nitish428]

Thanks a lot sir just cleared all cocnepts with ques in just a short time...

[@shubhamgupta-4425]

Type 6 was literally unknown for me.thanku sir for giving and solving Advance problems .

[@abhinav788]

Type - 3 H.W. -- S(infinity)= 1/12

[@a-vinil]

Sir, please teach how to factorise the denominator as you did at 20:49

[@RZMATHS]

Check my inverse trigonometric series revision i have done the same factorisation there.

[@a-vinil]

@@RZMATHS ok

[@a-vinil]

@@RZMATHS Sir, I couldn't find it in all the trignometric series videos. Could you please make a video on that.

[@uditraj5729]

@@a-vinil Clearly sir said it's in inverse trigonometric series video

[@farista4667]

S Infiniti in first one is 1/12 In last one I am able to form rth term but couldn't express that as difference Tr=1.3.5...3r-2/4.6.8.....3r+1

[@himeshkumar5293]

Bro i wrote general as 1.3.5...2n-1/4.6...2n.2(n+1) Then in numerator do 2n+2-2n+1 Guess it works

[@adityashriwal5378]

@@himeshkumar5293 I have also form same rth term like u but what to do next???

[@nomadgamercao1177]

@@himeshkumar5293 right bro

[@himeshkumar5293]

@@adityashriwal5378 right 1 as 2n+2-2n-1 in numerator

[@adityashriwal5378]

@@himeshkumar5293 ok

[@shyger778]

loving ur videos sir thanks a bunch :)

[@RZMATHS]

Thank you so much ❤️... Please share the videos with your friends too...☺️

[@shyger778]

@@RZMATHS 😇

[@BhupendraGola-sz1tu]

Thank you sir 🥰🥰🥰😊😊😊

[@cutegirlakanshabag2449]

Thank you so much sir.. 😊😊👍👍Type -6 question 10MQ h 😊👍

[@vanshajverma2199]

sir please do all question types asked in permutation combination which will be very useful for us and also thank you for the great content helping me in my jee advanced prep

[@anurag_gautam00]

Great session sir big fan 🙏🔥 really you help a lot In Maths for jee advanced ..I hope abhi app ase hi aur session lenge advance ke pahle 🙏

[@herlim6927]

1/(2r-1)(2r+1)(2r+3)

[@suhassutre4658]

best explanation sir thank u for such efforts

[@akshatkarkar6588]

Thanks sir.....very good videos 👍

[@jatinreddy]

Type 5: exact question was asked in Mains 1st Feb Morning shift 2023

[@devanshukumar5740]

Sir please make a lecture on trigonometric summation series

[@tommyshelby6277]

sir pls next one on Matrices to be specific: questions on adjoint, orthogonal matrix, inverse matrix

[@GulshanJii-rw5dm]

In type 1 sum of first n natural no. Is n(n+1)/2

[@vivek-hb1ht]

Sir I solved type 7 and it is a really long ans in terms of n But one significant thing is 1/32[ (1•3•5+ (2n-1)(2n+1)(2n+3)(2n+5)][1/4•6 - 1/(2n+4)(2n+6)]

[@kushaankoul5775]

whats the general term

[@PIYUSH777MyNameIsPiyushSoni]

Sir pls cover the factorial summation aswell

[@Volase]

This was extremely helpful

[@commonman248]

Thank you sir please make video on trigo

[@shivankulcodezz]

There is another simple trick to do method of difference. Make a tree like then took first term of each to make the series Example: 6 +13 + 22 + 33_______n term 7. 9. 11 2. 2 O Now take first number and make Tn = 6 + 7(n-1)/1! + 2( n-1) (n-2) /2! Answer comes out Tn = n^2 +4n + 1

[@conceptisthekey5643]

But if diff becomes GP then this leads to wrong ans.

[@divyaj3493]

@@conceptisthekey5643 use a+b(common ratio)^n, and put diff values of n 2 times, u'll get 2 linear equationin 2 variabless, solve them , u'll get a and and b and then apply type 1 on it

[@sanjaijee7157]

Please DO Complex Numbers or3D GEO. on upcoming videos. I loved and learned a lot sir

[@atultiwari9528]

Sir please give solution for the last series, I wasn't able to do that, and also thank you for these lectures they are wonderful. I have been doing your questions for some days now, and i love all thr questions

[@nishantrathore5031]

Thank you sir for helping for us

[@olliver8031]

Sir please upload a video on jee advanced problem on 2 newton lebinitz formula Rollle's theorem

[@shūubhsóní]

Thank you very much sirji

[@manas-singh]

Sir its humble request aap compound angles fully jee adv++ level pr explain kr dijiye

[@ruhailkhan3165]

S of inf= 1/12 15:00

[@shivamshukla9129]

You are great sir❤

[@vishalmishra0014]

Sn = 2^2/3 - 1 for type 7

[@kushaankoul5775]

bro ☠

[@perfect_tex]

Type 6 was good👍

[@AnkitSingh-mv1oi]

Loved it 😊

[@Mysterious-735]

Bhaiya plz tell me one thing that if in a question limit and summation come together and summation koi equation na ho toh usme woh integration ban jayega Like this one 👉 Lim n -> ♾ summation r 1 se n tak r^p/n^p+1 Plz tell me

[@goodtuber3411]

Thank you very much sir , here i am your new student i have a doubt in type 3 que that you gave to us is that what will be the nth term because when i tried it my nth term is not giving me proper terms plz help...🙏

[@ruhailkhan3165]

Sir can you make vidoes on limits?

[@rahulkumarsingh4137]

this was the same video i was wanting, you did the same.

[@savagesyd29]

Thanks for the quick revision

[@deepamishra1737]

Thankyouuu sir!

[@prtk2verma]

Sir take a session on question solving approach in AOD (highest weightage topic of adv.)

[@khushpatel8176]

Can u pls as well add link to pdf notes of these videos

[@manamtiwari]

Was waiting for these kind , awesome sir

[@yashshindekar9088]

Sir please do continue this IIT Jee series likely to come for Jee advance 2023.

[@Abhi-kr6df]

27:37

[@soumyanamdeo2347]

sir please next video on trigonometric series 🙏🙏

[@agarwalaman123]

Intial concept used in limits

[@OCEAN_NINJA]

you are ammazin I enjoy a lot

[@divyanshgupta2012]

Sir 0lease do vector 3d next

[@geetapandey9956]

thanky0ou sir can u make some videos on imp properties of conics which may be asked in advanced currently i was revising conics so i thought

[@indreshpatel7764]

SIR PLEASE COMPLETE BINOMIAL SERIES LEFT PART

[@parijatgoyaliitkgp7572]

Sir when is the second part of binomial lecture coming ?

[@ligma_hairy-ass]

We need part 2

[@monurathore3241]

Thankyou bhaiya

[@parijatgoyaliitkgp7572]

Type 7, S(inf)=1

[@atharvasheershpandey2097]

Pretty GOOD

[@imankalyanbhunia1263]

Sir please coordinate geometry question series

[@gagannarang4362]

BINOMIAL COEFFICIENT PART 2 SIRR SOOON PLEASE

[@TruecriBge]

Thanks a lot

[@riteshpatil1941]

❤❤

[@vishalkumarkumar8128]

Thank you sir ❤️

[@ariflear_reactor]

Sir please make a leacture in hindi

[@hiteshverma1786]

S infinity=1/12

[@aditya1dhiman]

these are very helpful sir🙏

[@jeevan3226]

Sir i have prepared maths but due to lack of practice i am not much confident about it , what basic minimum i should do to clear subject cutoff or score min 25 to 30 marks in Maths

[@kiruthika4671]

After seeing your thumbnail I m freaking out to leave jee advanced

[@vikask2512]

Complex Numbers Please Sir.....

[@xeoldboy9714]

Helpfull

[@himanshugurjar5630]

s infinity of last qustion is 1

[@sudhirtiwary8111]

Sir I am from class 11 2024 bactch should I solve A Das gupta subjective or black book with my coaching module? Please tell sir

[@geetapandey9956]

cengage 5 parts will get you enough problems to command and excel a topic upto advance level ebven manny mains qs are framed directly fromm it but you should buy only jeee advanced cengage by g teani which has 5 subparts

[@itsmathslover...6617]

Ans of hw question is 1 of s infinity is calculated ....first step 2 se multiply and divide Kiya then numerator Mai 2n-1 ka term and denominator Mai 2n+2 aaya and uska hi difference lenge ...finally s infinity Mai 2x1/2 aaya then ans is 1 ...sahi hai kya sir ??

[@vempatisridhar7448]

14:45 sum of infinity terms is 1/3 and Sn Is 1/3-1/(2n+1)(2n+3) Can Any one confirm

[@samarthchaplot2998]

bro bahar 1/4 bhi rahega Therefore, S (infinity) = 1/12

[@jagdishprasad1140]

Bro you missed a factor of 1/4 .

[@shreyanshagrahari7217]

Sinfinty is 1/12

[@kunalkishor6058]

You missed the factor of 1/4

[@vempatisridhar7448]

yes I Missed 1/4 factor. Thanks for reminding

[@shailendrasingh9873]

Btw apart from everything,sir why is this channel named rz maths ? Is the shortform of your name is rz?

[@RZMATHS]

Yup

[@ARYAN_BAJPAI_IIT_BHU]

Tele gram group banao uspe discussion Kiya jye

[@gauravahuja7803]

Thx sir

[@AMANKUMAR-ww9us]

15:00 answer for S(infinity) is 1/60.

[@AMANKUMAR-ww9us]

Thanks bhai

[@pranavpurohit4693]

@Bhaskar ojha bhai bhaskar ojha 2nd term dekh 1/(n+1)(n+4) even ban jayga galat kiya h tumne Tn hoga= 1/(2n+1)*(2n+3)(2n+5) Aur summation n=0 se start krna padega

[@francisangelmanohar5020]

Thank you sir

[@4zvm]

Lastone 💥

[@anaysingh-iitdelhi8955]

27:10 Ans =1 🙂 it's the correct answer If any one needs solution reply karna I'll tell you

[@lakshya254]

I got the n term but no idea how to solve further So please help 😅😅

[@pranavpurohit4693]

Kya majak krre ho fraction me answer ayega dekhke hi lag rha h

[@anaysingh-iitdelhi8955]

@@pranavpurohit4693 la bhai tu fr answer maine ye question VMC illuminati sheet mai kiya hai waha 1 hi dia hai tu Le a apne hisab se fraction mai amswer maine kab mana kiya hao

[@abuzarazhar7959]

Bata Bhai kaise kiya

[@sabhyatachoudhary5491]

Bro how did u get the answer then?

[@yashpandey3.3.3]

You are missing out matrices and dets.

[@m.rohithkumar8212]

Answer to homework is 4^1/3-1 Using binomial expansion (1+x)^n = 1+nx+n(n-1)x^2/1.2+ n(n-1)(n-2)x^3/1.2.3 +..... Comparing the given expansion with the expansion of (1+x)^n.. nx= 1/4 and n(n-1)x^2/1.2 = 1.3/4.6 On solving we will get n=-1/3 and x= -3/4 , so answer is [(1-3/4)^-1/3 ] -1 (“-1” because at first I added 1 and subtracted 1 ).... 4^1/3 -1 Edit: SORRY I CANT DO THIS SUM BY USING DIFFERENCE OF TERMS..

[@devanshukumar5740]

S infinite=11/24

[@GauravKumar-et5zy]

S(infinite)=11/24

[@RohitKumar-jk8mw]

Hindi mai bol liya kr bhai 🥲

[@RZMATHS]

@@RohitKumar-jk8mw aati hi nahi h bro Maths ki kya hi language h bro ?? Feel karo questions ko bas 😅

[@yashs.gosavi4024]

Why did i not find this channel before 🥲?

[@ayyamguari6134]

Us bro us🥲

[@tinywrestler383]

beocz ur a legend..by name

[@mehulgoyal7727]

Cuz you are a legend both by your name and profile pic..... Also you must be very good at piano and calligraphy....and maybe tea ceremony.

[@arvind_24]

Thank you sir ❤❤❤

[@riteshpatil1941]

❤❤

[@AKASHJEEASPIRANT26]

Thx sir

[@shivangigaureichandra2136]

Thank u sir