SFD BMD for Simply Supported Beam Subjected to UVL.

[@abdullahalzain3573]

I have watched like 10 videos and never understood but now from you I understood everything, thank you a lot bro you saved my marks

[@parameswarankrct7229]

This was very clear. Viewers pls dont skip. This guy teaching is understandable

[@tjmunnagaming7686]

Tq so much sir..love from Assam

[@Valli273p]

Really... very super and detailed explanation 🥳🤩🤩

[@sadiaanjumesha6521]

This was so helpful. Thankyou so much.

[@tarsohung5861]

Best explaination 👍

[@m-0116]

Thank you sir

[@priyanshukr.4834]

Cleared my doubts..Thanks a lot sir🙏🏼

[@CivilEnggLectures]

Thanks for Watching.

[@k.thangapandi4643]

very excellent, most helpful,thank u sir

[@CivilEnggLectures]

Thanks

[@shree7802]

Thankyou!!!!!

[@CivilEnggLectures]

You're welcome!

[@neeru8381]

THANK YOU SIR

[@omkardhamane269]

Thank you Sir....Nice and simple explanation ✌🏻

[@CivilEnggLectures]

Thanks

[@rajurampalli3511]

Love u bro

[@symsuree18]

Thank-you sir

[@CivilEnggLectures]

Thanks... please share

[@sankirbagh9259]

Nice🙏

[@KamalKumar-cg5xt]

It is the problem of uvl on simply supported beam of unsymmetrical which is very helpful for clearing the concept. You also must provide the symmetrical uvl on simply supported beam.

[@luvjoshi841]

You did a great job.

[@CivilEnggLectures]

Thanks

[@demonic1907]

I didn't get 5.19😢

[@adhitysrestha4547]

Me too😭

[@demonic1907]

​I got it

[@CivilEnggLectures]

Still in doubt?

[@SaiKiran-rb3by]

Why you wrote X value directly it makes little bit confusion

[@CivilEnggLectures]

What kind of confusion? If you state here I shall clarify for you.

[@SaiKiran-rb3by]

X= 5.19

[@CivilEnggLectures]

It's not written directly.. please check

[@Ck-gl8mt]

Thank you

[@CivilEnggLectures]

Thank you for watching.. please share

[@lkychadda7341]

🙏🙏🙏

[@tajciviler7393]

X and h value how to get?

[@CivilEnggLectures]

by using the concept that at maximum BM, sf is zero in case of simply supported beam... and then by applying concept of similar triangles

[@jasondezeal7286]

Bro for the last part finding bending moment at C, u can just find the area of the parabola from the SFD. Area will be( 2/3xbasexheight). Easiest.

[@CivilEnggLectures]

Yes can be done

[@shahnawazkhan596]

Great

[@CivilEnggLectures]

Thank you

[@fxchandan6124]

Please solve the equation of "X" value from SFD diagram.

[@Sa-mj5ms]

Gud

[@CivilEnggLectures]

Thanks

[@saikiranpolu423]

Thnq bro

[@ajays4350]

And for Ra wl/6. Rb wl/3

[@11221122gamer]

best best best

[@CivilEnggLectures]

Thanks

[@Swat_Roller_pigeon_998]

very confussing to understand .but not bad

[@CivilEnggLectures]

It depends

[@abadhbihari001]

nice brother

[@CivilEnggLectures]

Thanks

[@ajays4350]

To find x sub formula L/ROOT3

[@SaiKiran-rb3by]

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