Shear Force and Bending Moment of Uniformly Varying Load | SFD BMD of UVL

[@mohamedaamir4703]

Thank you so much I didn’t know the similar triangle concept until I watch your explanation... God bless you

[@structuralanalysisanddesign]

Happy to help, all the very best, keep watching

[@imranaliasr]

you are really great i saw many video about this topic but i dont understand now i am clear thank you so muchh

[@andrewsenorans8077]

Your parabola for the shear diagram is concave up though it should really be concave down because the shear approaches zero more quickly as the distributed load gets larger.

[@muhammadsyafiq5750]

Yes indeed i think so

[@pejhonsetareh4723]

yeah I was confused about that, but you guys are right. The bunny slope then black diamond. @jeff Hanson the man

[@sakhilegasa3645]

Well explained! thank you so much Sir

[@yela_liz]

You explain really well, thank you. Please sir, while finding the reaction at A, why didn't you use one-third of the base just like you used two-thirds of the base to find the reaction at B?

[@lourdesmhlongo1826]

Yhoooo it's been 2 years he hasn't answered and I got a test in 4 hours

[@nursyazwani5379]

Because while finding reaction at A, use the sum of Fy . Not sum of moment. If sum of Fy, u dont have to multiply with the distance

[@farsiyaqs704]

😂😂​@@lourdesmhlongo1826

[@SkhumbuzoMalwandeZulu]

Thanks sir i have mastered this topic ❤

[@techwalatushar2144]

Thank-you thankyou sir ek dam samajh aa gya uvl load

[@ntombentshalydia1030]

Awesome explanation Sir...thank you very much

[@structuralanalysisanddesign]

You are most welcome, keep watching and sharing

[@Diamond.100percent]

@@structuralanalysisanddesign replaying to the student's doubt will be better then repleying these .

[@yashokkumarmech5880]

Sir explain In detail that how u took 2/3 has moment point at

[@harikayadav3620]

Hi sir ur explanation is good then simply understand ur concept I have a small request sir that is in problem you saparate calculations you do sir it's sum confusion

[@moizudaipurwala563]

Thank you so much sir

[@tejasshelar475]

F=60 -4X^2/6 Sir how did find the values ? X= 0 Fx=60KN X=3 Fx=0kN

[@NitinPatel-yh6bo]

The moment arm should be 2/3 of x since moment is taken by A (Left side) Hence the 40x^3/18 should be 40x^3/9. Please clarify. This is for the triangular force.

[@brijeshpatel7969]

Sir can we cut the section from C side for B.M on AC points

[@yashokkumarmech5880]

Hello sir ,will u please clarify that how that 2/3 came

[@bikashkhadka5772]

Moment isn't about A rather it's about the point where section is taken( at x distance from A)

[@ansariabid5623]

@@yashokkumarmech5880 it's cg, If u want triangular cg fr from 90 degree side take l/3. If u want from decreasing or zero side take 2/3 L

[@glaciemontess2806]

@@ansariabid5623 what topic is this?

[@rudigar4319]

Dear Sir, if I am not wrong, concavity of the curve is incorrect here

[@onuminyadavid2807]

Sir, do you choose the direction to which the parabolic curve opens as you like when sketching the sfd for a uvl?

[@Maths0123]

Dear sir. Shear force diagram is parabolic. but y= =x2 shape. Not y=x2 shape.

[@aduseiebenezer3496]

Moment about point A, RB should be in anti-clockwise direction

[@amoghanjana5499]

Sir explain how u got the 480

[@amarami3970]

SFD & BMD sketch is wrong for section AC.

[@arukrishna8032]

U mean the calculations?

[@civiltechnology6211]

Yes... wrong calculation

[@pranjalkaushik7814]

No he took wrong values of x

[@jaygarden6840]

in moment sir where did you get the -80 (4.5) ??

[@ricoswabe2404]

Your explanation for finding maximum moment at point of zero shear is complicated. Actually you can simply take moment at point of zero shear at X=3, MX= RA(3) - (1/2 b x h)(1/3L) = (60*3) - (0.5*3*40)(1/3*3) MX= 120KN.m. Note: b= X = 3

[@arjunsachar4867]

Tq

[@lathaguntuku9110]

Sir y don't we take Me from left to right........what's the difficult we get

[@prashantgunjal5100]

Shear force parabola must be open downward 16:07

[@mujahidsalik5359]

I think Rb= 90?

[@knowledge-er2et]

Sir, you do mistake in span cd

[@prasannadahal5981]

bending moment diagram for sagging condition should be drawn downward from convention.

[@江江東隆]

0

[@normanka2905]

I think your curve is wrong because the triangle at the given problem is increasing negative load.

[@aniketkalgutkar4359]

Karwar cho re tu

[@SouravMondal-nm4xc]

Your sfd & bmd curve is not right.....

[@Armaainfratech]

Your shear diagram is wrong because the load is increasing in loading diagram and your theta is decreasing in your sfd

[@AdiruNancyJudith]

You are very correct @Armaainfratech I have been following very carefully his SFD is wrong the load is to be increasing not decreasing

[@kenjomnyorakofficial8823]

No you are wrong sfd is correct because in A there is a load so there theta can't be zero

[@rajprinceofficial7695]

Hindi mai batane mai dar lagta hai kya🤭🤭🤭🤭🤭🤭🤭🤭

[@jayshreeyadav5463]

Sir hindi m nhi. Bta skte ho ky india m rhte aur jyda hi english bol rhe

[@harsh2032]

english is more generalised to fetch more viewership. kahi bhi gobar mat likh dia karo. He's been helping for free, be grateful.

[@rk2869]

RA=40KN

[@penkeybharath8863]

Ra is 60kn only