Similar Matrices

[@SuBhAmVLoGS]

I totally respect this professor....at such an old age.....he is able to explain all the topics in a well-organized manner...

[@yusufozturk4609]

I really appreciate this guy

[@ahmetklavuz3820]

mezun olabildin mi .d

[@elenag.224]

Gilbert Strang... A true professional. I own a book of his and it's very helpful, even if the reader is a beginner in linear algebra.

[@NazriB]

Lies again? Singapore Manager

[@JordanEdmundsEECS]

This has been incredibly helpful, I'm starting to see the beauty of matrices.

[@JoffreyB]

is it yours theorem Jordan in dat video?

[@JoffreyB]

nah, i know this so stupid and childishly, but who cares

[@asrarulhaq1890]

hahaha

[@georgesadler7830]

I am learning linear algebra from one of MIT legends in mathematics.

[@anshumansingh9935]

First time I'm hearing someone refer to matrices as people and comparing their beauty with each other @08:01 😂😂

[@stealthysubie]

Thank you so much for making this simple explanation

[@aarifhussain3700]

No words for this genius

[@gyanendrabehura1761]

Love from IIT KGP INDUSTRIAL DEPARTMENT

[@piyushmourya3183]

Oh god , I was trying to understand the same thing from my prof lecture slide for hours .

[@aashishmalhotra]

Thanks for Providing quality education free

[@Can-tf5xz]

You are a saint

[@aidanhayter2160]

Great explanation!

[@Smoothcurveup52]

Wonderful explaination Thanks

[@LOG2007]

Amazing Professor!

[@libelldrian173]

I love his passion!

[@ElizaberthUndEugen]

4:15 shouldn't that be M = V^-1? similar(X, Y) iff M^-1 X M = Y Y = A X = L (lambda) Y = V L V^-1 = A => M = V^-1 (V^-1)^-1 L V^-1 = V L V^-1 = A

[@amrithaak4538]

It really helped me.....Thank you sir

[@RohitKumar-Haridwar1]

Great effort

[@helloworld-hv9oy]

so row equivalent matrices have the same eigenvectors and eigen values?

[@scooterking136]

very helpful, thanks!

[@amizadeesimpatia8989]

Can we raise a number to a matrix?

[@AdiJ8]

You can't

[@masbicudo]

It's possible. He did it in the video. As long as the matrix is square, it's possible. en.wikipedia.org/wiki/Matrix_exponential

[@hojunchoi858]

He is legend

[@VinothKumar-qo7ry]

Thanks Lot sir

[@stracci_5698]

Finally understood something

[@XxSaMuRaI123]

Sorry for the dumb question, can anybody explain to me how he expanded the matrices A and B when he was talking about the "caution", thank you!

[@amarkantsinha9400]

expansion of e^x =1+x+x^2/2! +....

[@dinleepound9466]

Amarkant Avinash thx!

[@zijiahu]

Taylor series representation of e^x

[@yigitcan824]

addaaam

[@gokhantore3651]

eyw kral

[@coop4476]

Ahhhh. I keep feeling like the board will just fall on his hand

[@zack_120]

9:35- it's weird that the exp rules are invalid here. This is Not math, my love for math gone 👎

[@alanfate4853]

He didn't really explain jordan form

[@furkangorgulu1]

🤓

[@Amine-gz7gq]

I hate matrices