Solution of BJT based problems

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Here you get a solution of BJT based questions with a detailed explanation. Please don't forget to like, comment, share, and subscribe.
by Laxman Goswami Ph.D. Physics from IIT Delhi
| Physics by IITians |
For solving relevant questions :
1) Do previous year questions
2) Read some standard book for this
3) And we will post questions here as well
t.me/PhysicsbyIITians
4) Do follow our videos, we will cover more questions and concepts in coming lectures.

[@guy_is_2_shy_to_talk_to_girl]

Thank you bhaiya App iitian ho to sir bolte hai seniors ko na

[@sanjayharitwal1608]

Thanks guruji. It was helpful.

[@Savvy_trader]

Fantastic sweet and simple ✨

[@ajay-dp2si]

Please btayiye ke bjt ke symbol me emitter aur collector inclined hota hai jabki fet me drain aur sourse right angle par hota hai aise kyu

[@SakshiSingh-ln5iv]

A very helpful video sir.

[@jignesh72023]

Thank u very much sir.

[@oldisgold4217]

Thank u so much sir 😌

[@adityanarayan8260]

Salute 🙌 🙌🙌 🙏🙏🙏

[@akashjaiswal3120]

sir you have cleared my very big doubt which was related to Q point and load line thank you sir

[@chanchalsingh9423]

Great

[@niranjanaprasad4293]

Thank you sir😇

[@aspirerpj6924]

Efficient way to solve BJT related problems!! Helped me a lot!!

[@mr.jaydeepmakwana7457]

Thank you sir. Really helpful✨

[@mukeshkumargupta4353]

Sir reallyyyyyy mazaa aagya Shuruaat bahut acchi krdi aapne 😊😊sir plz it is really motivating us

[@ShivamMishra.2002]

Bhai ye btao ki jb resistance kiloohm me lie to current miliA me aaegi yaa microA me...????

[@ShivamMishra.2002]

Plz rply

[@Swati_9040]

@@ShivamMishra.2002 milliA

[@ShivamMishra.2002]

@@Swati_9040 i also think that... Bt now my that semester is over🤣🤣 Bt thnks for clear my doubt

[@umamishra9019]

Thank you sir

[@vijendra1150]

Great Bhai Ji Super explanation

[@ashutoshmishra3690]

thanku bhaiya

[@user-mw3rx6mg5n]

Best

[@og5278]

Sir you have ignore k in resistance and choosen simply 500

[@igxniisan6996]

But kvl is only and only applicable for closed path right??? How is that kvl if it's not a loop?

[@subhranshudas_]

KVL can be found between 2 potentials, not necessarily it has to be a loop

[@abduljabbar778]

Why did you ignore 10Ib ????

[@sandipansarkar3717]

❤️

[@b52_vishwajeetpatil99]

7:30 y cloack wise not anti

[@rohitgoud1339]

Excellent work sir thank you

[@vishnuchauhan6392]

Sir I,e bilkul I,c ki tarah dekh rha hai sir samj nhi aa rha hai kaun kya hai

[@sahilgoel2034]

👍👍👍👍☺️☺️

[@mr.jaydeepmakwana7457]

I m New subscriber.

[@MansoorbinTariq]

exam say 3 ghntay pehle dekh raha hoon ....chaa gayee app

[@PhysicsbyIITians]

Best of luck for the exam

[@samirgautam4342]

Maza aya 🤑

[@rozegaming8672]

2020-BME-1🥰

[@it28nitishkharwarkharwar21]

Thanks sir for question

[@vijaymeena8572]

Thanku sir 👍👍

[@Circle791]

Superb class

[@vinayakvmorigeri4703]

👍👍 thanks a lot sir 😌🤩

[@Learner-lq3vu]

Sir pnp transistor ka bhi questions krwa di ji ye?

[@PhysicsbyIITians]

Will share

[@Learner-lq3vu]

@@PhysicsbyIITians sir ek question hai uka solution chahiye question bhejna hai aapko insta bta do please.

[@divyasharma2212]

Keep it up sir, 👌👌✌

[@soumensaren7704]

Nice explanation

[@novestkuvimba1469]

Please do a video in english!!!!!!!!!!!!!

[@kennydalid9438]

i wish you all can teach in english language

[@PhysicsbyIITians]

We upload our videos in English as well. Thanks for your support

[@rizwanakhan0610]

Sir i think so there is a mistake in 2 problem Ic=3mA Vce=12-2Ic Vce=12 - 2*3m=12-6m=11.994=12Volts

[@bussasunitha1876]

Y axis is also in milli so no need

[@hssanlachgr6891]

why having english titles on your videos if you are actually explaining in your language

[@harithrarajarajan4465]

I feel your pain 😭🥺

[@kzy7923]

shutup

[@_aka_unknown]

This video is for JAM, TIFR, Jest, NET, GATE aspirants... Not for you... Don't spoil the efforts...

[@shanugaur8218]

How do know that the transistor Was in active region already while using Ic=betaIb and Ie=1+Betaib

[@josephsmth646]

Intially asumme active mode after checking that bjt in fb ,than see VCE greater than Vce(sat) if yes than bjt in active region if not than bjt in saturation and do calculations.

[@uttamkumar-du6ql]

c e confused

[@harithrarajarajan4465]

Sir , one suggestion .. when every single youtuber teaching physics is teaching in Hindi , why cant atleast one person try differently and teach in English .... the entire population of South India would be benefitted ... why not even one single person thinks of it ?????

[@sharma..8905]

Skill issue

[@harithrarajarajan4465]

@@sharma..8905 Yeah yeah .... Lack of empathy towards South Indians . Not for youtubers but you!

[@sharma..8905]

@@harithrarajarajan4465 it's just dumb of you to suggest a teacher to teach in a Different language than the one they are comfortable in.

[@asishdhal2824]

kuch samjhate ho hi nhi bas equation solve karte ho jese scl ki bache

[@BADALRAJ-jg6zp]

Thank you sir

[@s.b.physicsclasses6334]

Thank you so much sir 🙏🙏❤️

[@Abhi-cz3hf]

❤️