[Solved]- Numerical for a BJT (Ib, Ic, Vce & Vcb =? )

[@narutokiller8432]

My first video for starting my (EDC engg sem 3) thnx sir... People like you are making world a better place

[@ElectronicsCircuitHubECH]

@@narutokiller8432 Hi Thanks for those words. Watch all the video of this channel. You will become HW engineer after 4 year lots of stuff are there.

[@abrahamansah94]

Thank you so much for this video It has really saved me in my exam 😊😊😊😊

[@ElectronicsCircuitHubECH]

Most welcome

[@AnujBommena]

How do we know that Vbe =0.7V? Is it a constant value that's true for any circuit?

[@ElectronicsCircuitHubECH]

VBE is base to emitter voltage of npn transistor. Which is fixed and in the range of 0.6V-0.7V. Si material is used to form a PN junction so the cut in voltage of Si is 0.6V-0.7V. You can refer transistor datasheet for more information.

[@chandasx]

if transister made with silicon, vbe is 0.7v

[@thijsgrimbergen8898]

@Electronics Circuit Hub, correct me if I'm wrong, but if you multiply 0.43A by 150 beta, how do you get a lower current? I would think that if you multiply 150 beta with 0.43A you should get 64,5A?

[@ElectronicsCircuitHubECH]

Hey...Thanks for bringing out this question. Sorry I may not able to watch this video again due to policy violation. But if you help me with the Vb = ? , Rb = ? I can re calculate for you. Sorry if I made mistakes somewhere. Generally ib = (Vb-Vbe)/Rb And ic = beta * ib. .43A base current is unrealistic and BJT will get damage. Isn't it 430uA current ?

[@thijsgrimbergen8898]

@@ElectronicsCircuitHubECH I'm sorry I've read your u as a m. You were right... My apologies, it made no sense if Ib was higher than Ic. Thank you for your fast response and your video!

[@ElectronicsCircuitHubECH]

@@thijsgrimbergen8898 Its my pleasure. Keep Learning , Keep Rocking !

[@ManshitaJalmi]

Sorry sir but can you explain how Vce=10V-64.5mA×100ohms=3.55V?? Shouldn't it be 6440??

[@ElectronicsCircuitHubECH]

Hi...Thanks for asking good question..do not feel sorry about it...=(64.5*100)/1000=6.45V. Now 10-6.45=3.55. 64.5mA = (64.5/1000) A. So current unit should be in A.

[@ManshitaJalmi]

Thank you so much sir!​@@ElectronicsCircuitHubECH

[@moonwise26]

hello! why Vbe=0.7V ? It's not given in the problem. How did you find it?

[@ElectronicsCircuitHubECH]

Ideally Vbe of non transistor is in the range of 0.6V-0.7V. Please look at the datasheet BC547.

[@amira66996]

Thank you so much sir , this is very helpful

[@ElectronicsCircuitHubECH]

Thank you very much.

[@panashepanaxe629]

All z correct n well explained 👏

[@ElectronicsCircuitHubECH]

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[@hannahjoydelatorre8315]

Thank you sir!

[@ElectronicsCircuitHubECH]

Most welcome, glad it helped you.

[@eunicejikana6086]

Thank you so much 👍😊 I've understood 🙏

[@ElectronicsCircuitHubECH]

Most welcome....pls find many more such video here in this channel.

[@eunicejikana6086]

Alright ❤️❤️

[@abhijeetbajpai..6725]

HOW YOU CALCULATD VCB PLZ TELL AGAIN

[@gabrielphiri8352]

Thanks I copy now 😊

[@ElectronicsCircuitHubECH]

Go ahead ! you may watch many more video here.

[@macvoice6439]

Hello po sorry newbie here how did you input 10k in the calculator that results into 430MA?

[@ElectronicsCircuitHubECH]

I think, you are talking about base resistance 10K, its 430uA not 430mA. 10K allows 430uA to flow in base of NPN BJT. This question i found in internet and trying to solve it.

[@Ommprakash19]

Hii bro how is it 430 mA ??

[@zaybienw]

Thank you this helped me

[@ElectronicsCircuitHubECH]

Glad to hear, it helped you. Many more learning video on this channel.

[@paulvasava07]

How to put the Vbe value

[@ElectronicsCircuitHubECH]

Vbe=0.7V

[@zvlaz]

shouldnt Vce = Vc + Vb ? 3.55V + 0.7V = Vce = 4.25V?

[@ElectronicsCircuitHubECH]

Hey...Vce =Vc-Ve always.

[@akopai-kk4yv]

hi sir if vbb start with +Vbb- then Vbb value will minus can u explain sir sry for bad eng

[@ElectronicsCircuitHubECH]

Hey...Thanks for asking good question. I think you are talking about B-E loop. So simply apply KVL : Vbb-ib*Rb-Vbe=0. Now you can calculate whatever you want. Please let me know if you have doubts.

[@abdulrauf9887]

Ye plus or minus sign kessy lgttty hn

[@ElectronicsCircuitHubECH]

Hi...Learn some basic network theory.

[@akki0908]

Its easy when we jump from + to - then the sign afterwards as in this case - will be taken but when we jump from - to + then + sign is taken

[@ElectronicsCircuitHubECH]

@@akki0908 great explanations, thank You.

[@akki0908]

@@ElectronicsCircuitHubECH welc

[@Shivbhakt-699]

​@@akki0908 it's like kirchhoff voltage law's sign convection..

[@a.j1298]

Thank yoo

[@ElectronicsCircuitHubECH]

@@a.j1298 Welcome

[@mohammedraqibulmomenadino9018]

Is Ie 0 here?

[@ElectronicsCircuitHubECH]

Hi..Thanks for question, No Ie=Ic (Ie value is close to Ic).

[@bestplatformyoucanmakeorde2624]

How do you get 0.7v

[@ElectronicsCircuitHubECH]

0.7V is the Vbe voltage of Si BJT. base to emitter voltage.

[@bikram2017]

🙏🙏🙏

[@ElectronicsCircuitHubECH]

@@bikram2017 🙏🙏

[@21owest75]

😢❤this same question can out as my exam question thanks ❤❤i give you a like and subscribe

[@ElectronicsCircuitHubECH]

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[@emmanuelbili6886]

Are the answers correct

[@ElectronicsCircuitHubECH]

what did you find wrong ?

[@emmanuelbili6886]

@@ElectronicsCircuitHubECH someone told me so but I trusted your answers

[@ElectronicsCircuitHubECH]

@@emmanuelbili6886 You should trust the step i explained in the video. All answers are correct.

[@gabrielphiri8352]

@@emmanuelbili6886 eee problem ba bili just copy ala

[@BASITMIRANI]

Your answers are making confusion for me and great work I appreciate your work very very beneficial video thanks a lot ❤

[@mohammadaftab3672]

Vce i think you get wrong answer Answer is 6440 correct

[@ElectronicsCircuitHubECH]

not sure, i need to review the video again. thanks for your feedback.

[@learningwithfrinds780]

😊

[@ElectronicsCircuitHubECH]

😬

[@dr-mnizam]

This video shows on solving DC of emitter bias circuit: kzbin.info/www/bejne/iKLTmq1slJiCi9k

[@ElectronicsCircuitHubECH]

Thanks

[@durgaprasadnaidu3723]

your pen sound suck my mind pls remove the audio

[@ElectronicsCircuitHubECH]

Hey...sorry for inconvenience. You will not see in upcoming videos.