Solving Exponential Equations Using Logarithms & The Quadratic Formula

  Рет қаралды 127,607

The Organic Chemistry Tutor

The Organic Chemistry Tutor

4 жыл бұрын

This math video tutorial explains how to solve exponential equations using logarithms and using the quadratic formula.
Logarithms - The Easy Way! • Logarithms - The Easy ...
Log to Exponential Form:
• Writing Logarithmic Eq...
Change of Base Formula:
• Change of Base Formula...
Change of Base Log Problem:
• Logarithms
Properties of Logarithms:
• Properties of Logarithms
____________________________________
Expanding Logarithmic Expressions:
• Expanding Logarithmic ...
Condensing Logarithmic Expressions:
• Condensing Logarithmic...
Natural Logarithms:
• Natural Logarithms
Solving Exponential Equations:
• Solving Exponential Eq...
Exponential Equations - Quadratic Form:
• Solving Exponential Eq...
_______________________________________
Solving Logarithmic Equations:
• Solving Logarithmic Eq...
Graphing Logarithmic Functions:
• Graphing Logarithmic F...
Graphing Exponential Functions:
• How To Graph Exponenti...
Compound Interest Word Problems:
• Compound Interest
Logarithms Practice Problems:
• Logarithms - Practice ...
_______________________________________
Final Exams and Video Playlists:
www.video-tutor.net/
Full-Length Videos and Worksheets:
/ collections

Пікірлер: 89
@TheOrganicChemistryTutor
@TheOrganicChemistryTutor Жыл бұрын
Next Video: kzbin.info/www/bejne/nJ_Ld6GbhN9ppJo Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Math & Science Videos: www.patreon.com/mathsciencetutor/collections
@jonathan-ww3sx
@jonathan-ww3sx 3 жыл бұрын
I really like how he repeats the concepts and properties to remind us. It's actually really helpful and not repetitive. It's great practice.
@alfonsomaurice7421
@alfonsomaurice7421 2 жыл бұрын
Sorry to be offtopic but does anyone know of a way to get back into an instagram account..? I stupidly lost my account password. I appreciate any assistance you can offer me!
@gordonpayton4846
@gordonpayton4846 2 жыл бұрын
@Alfonso Maurice instablaster ;)
@alfonsomaurice7421
@alfonsomaurice7421 2 жыл бұрын
@Gordon Payton i really appreciate your reply. I got to the site on google and Im waiting for the hacking stuff atm. I see it takes quite some time so I will get back to you later when my account password hopefully is recovered.
@alfonsomaurice7421
@alfonsomaurice7421 2 жыл бұрын
@Gordon Payton It worked and I finally got access to my account again. I am so happy:D Thanks so much, you really help me out :D
@gordonpayton4846
@gordonpayton4846 2 жыл бұрын
@Alfonso Maurice no problem :D
@maxamedaxmedn6380
@maxamedaxmedn6380 4 жыл бұрын
Yes i saw this example before many times but at this time actually i understood it very well because you explain things in a very understandable way
@zanemiracle6121
@zanemiracle6121 4 жыл бұрын
I saw this on flammable maths, I'm glad this channel is showing it too!
@krishivkothari5971
@krishivkothari5971 4 жыл бұрын
thats what I was going to comment
@z_.v
@z_.v 4 жыл бұрын
same
@maxamedaxmedn6380
@maxamedaxmedn6380 4 жыл бұрын
Ommm my god stop fucccccking lyyyyying
@davidsweeney111
@davidsweeney111 4 жыл бұрын
Zane Miracle papa flamy channel was hacked
@onefaith386
@onefaith386 4 жыл бұрын
Math lover here😊
@georgesadler7830
@georgesadler7830 2 жыл бұрын
MR. Organic Chemistry, thank you for another video on Solving Exponential Equations.
@innovbrain
@innovbrain Жыл бұрын
Ohhh thank you soo soo much finally someone who said we can divide x exponentials and get them subtracted. I consulted over 40 exponential equation videos and they all complicated the problem solving to an extent that no one allowed the exponentials division method. Thank youu
@hannukoistinen5329
@hannukoistinen5329 11 ай бұрын
:):)!! Keep up your good work!!!
@beanbean9019
@beanbean9019 4 жыл бұрын
I just wanna say thank you and I love u man❤
@tyronekim3506
@tyronekim3506 4 жыл бұрын
Very cool tutorial. Thanks.
@jcers
@jcers 4 жыл бұрын
This solution is so, so, golden
@dawnadmin8119
@dawnadmin8119 2 жыл бұрын
Nice! Next time, you might leave the substitution for y up while it’s still being used, for clarity. You might also have simplified the symbolic solution using the change-of-base theorem, to log_2 [(1+√5))/2]. or using the ɸ (phi) symbol for the Golden Ratio that you mentioned and Donald Knuth's notation lg for the binary logarithm that is so important in computer science, lg ɸ - 1.
@SAHIRVLOGCLP
@SAHIRVLOGCLP 2 жыл бұрын
Thank you for your sharing
@mathematicsmi
@mathematicsmi 4 жыл бұрын
Good job 👍
@davidsweeney111
@davidsweeney111 4 жыл бұрын
Excellent
@ardenkwong5299
@ardenkwong5299 3 жыл бұрын
You also just proved phi plus phi squared equals phi cubed!!! Congratulations Golden Ratio fans!
@eddjon
@eddjon 3 жыл бұрын
By definition of the log you can also skip the division by log(2) by converting x= log(y) in base 2; in Excel: =LOG((1+SQRT(5))/2;2)
@georgesbv1
@georgesbv1 3 жыл бұрын
one can even get rid of division: x = log2(1+sqrt(5))-1
@sail2byzantium
@sail2byzantium 3 жыл бұрын
Excellent! Thanks for this--very helpful.
@krachenford9594
@krachenford9594 2 жыл бұрын
Sehr gut!
@jrswizzle688
@jrswizzle688 4 жыл бұрын
I took pre cal dual credit last year and I mastered it completely and looking at this now I’m forgetting all the rules that goes to these things, im afraid I’ll forget all of this 😂
@cadkls
@cadkls 4 жыл бұрын
Practice it over time. Don't just master it in a short period of time, these things require experience to commit to memory.
@jrswizzle688
@jrswizzle688 4 жыл бұрын
cadkls you’re right
@swatitripathi9663
@swatitripathi9663 4 жыл бұрын
9:45 Just in case someone needs a linear equation for it : x = ((log((1+√5)÷2)÷log(2))
@bigshaqsmathematicalinstit3318
@bigshaqsmathematicalinstit3318 4 жыл бұрын
This is good practice for students taking elementary algebra!
@di-riso
@di-riso 11 ай бұрын
Elementary?!? Wtf u talking about
@Bostologia
@Bostologia 8 ай бұрын
@@di-riso if u dont know this is elementary algebra, believe it or not, algebra is a lot more complicated than just a exponential equation and logarithm
@sanopann1896
@sanopann1896 7 ай бұрын
are you serious did you skip elementary@@di-riso
@di-riso
@di-riso 7 ай бұрын
I actually found it quite easy and now I am doing calculus what I was saying is they don't teach you this in elementary school,there was a language barrier as when you put "elementary" before a subject in my language then that means that it's taught in the grades 1 through 5
@Dumb-Comment
@Dumb-Comment 4 жыл бұрын
The further it goes the more confusing it gets
@mastershooter64
@mastershooter64 4 жыл бұрын
Lol don't worry mah man just rewatch it you'll understand
@zissler1
@zissler1 4 жыл бұрын
It’s alright bruh you’ll get it
@krachenford9594
@krachenford9594 2 жыл бұрын
Same, as with marriage . . .
@paulocarvalho914
@paulocarvalho914 3 жыл бұрын
Matemática, linguagem universal.
@johubify
@johubify 4 жыл бұрын
DUDE, FLAMMABLE MATHS GOT HACKED, PLEASE SPREAD AWARENESS
@zachh6868
@zachh6868 4 жыл бұрын
When an add in the middle of a math youtube video disses math youtube videos... It's like getting paid to have your competition advertise in your video.
@mudassarm30
@mudassarm30 3 жыл бұрын
it was so easy ... the channel, Mind your decisions gives more challenging problems.
@italixgaming915
@italixgaming915 2 жыл бұрын
Solving this in C is a bit more challenging: 2^x+4^x=8^x 2^x+2^(2x)=2^(3x) 2^x+(2^x)²=(2^x)^3 If y=2^x we have: y+y²=y^3 So y=0 or y²-y-1=0 The solutions for y are: 0,(1+sqrt(5))/2, (1-sqrt(5))/2 2^x=0 has no solution. 2^x=(1+sqrt(5))/2 has a real solution which is log((1+sqrt(5))/2)/log(2). 2^x=(1-sqrt(5))/2 has no solutions in R but you can solve this in C. (1-sqrt(5))/2=-i².(sqrt(5)-1)/2=e^(i.(2k+1).pi).e^(log(sqrt(5)-1)/2)=e^(log(sqrt(5)-1)/2)+i.(2k+1).pi) (k is an relative integer ) So e^(log(2)x)=e^(log(sqrt(5)-1)/2)+i.(2k+1).pi) x=(log(sqrt(5)-1)/2)+i.(2k+1).pi)/log(2)
@unusaurus9714
@unusaurus9714 Жыл бұрын
that last question is just "don't judge a book by it's cover"
@paulocarvalho914
@paulocarvalho914 3 жыл бұрын
Através da HP-50g é fácil rsrsrs, graficamente, encontrei valor aproximado.
@kujmous
@kujmous 3 жыл бұрын
log base 2 of phi?
@Howto-ps3rm
@Howto-ps3rm 2 жыл бұрын
1:57 ... why did you divide the numbers with 2^x but not other number
@user-ku1cj9xm1r
@user-ku1cj9xm1r 4 жыл бұрын
Second place
@user-ku1cj9xm1r
@user-ku1cj9xm1r 4 жыл бұрын
I'm studying this and I'm 9yo!
@thelonelysponge5029
@thelonelysponge5029 4 жыл бұрын
Its because Asians are generally more smarter then most people
@mastershooter64
@mastershooter64 4 жыл бұрын
Damn everyone is sensitive and wanna feel like they're the smartest person in the room lol everyone's so butthurt about this one comment lol i love humanity
@Mralways
@Mralways 4 жыл бұрын
Good job you will be successful in the future well done kid
@njgskgkensidukukibnalt7372
@njgskgkensidukukibnalt7372 4 жыл бұрын
박제니 r/youngpeopleyoutube
@cadkls
@cadkls 4 жыл бұрын
@@mastershooter64 nothing to do with that Intelligent people don't need to brag about intelligence. Their actions speak for themselves. This person is not 9.
@Fmacian59
@Fmacian59 3 жыл бұрын
Has trabajado con el número áureo phi=(1+sqr5) /2
@MrIbrahimabutouq
@MrIbrahimabutouq 6 ай бұрын
👍👍👍👍
@sanopann1896
@sanopann1896 Жыл бұрын
at 2:47 why it was 1 and not 2^1 I'm confused
@dayarathnamunasinghe8444
@dayarathnamunasinghe8444 4 жыл бұрын
A spring placed on a horizontal surface.A 1 kg mass hit with it and spring shinked 4 m.calculate speed of mass if constant of kinetic friction is 0.25 and constant of spring is 2 N/m
@cadkls
@cadkls 4 жыл бұрын
No
@soracandles1979
@soracandles1979 4 жыл бұрын
First
@user-ku1cj9xm1r
@user-ku1cj9xm1r 4 жыл бұрын
Soooooo lucky!!!
@BabySagan
@BabySagan 11 ай бұрын
horribly confusing for me
@bilsonmathew7860
@bilsonmathew7860 4 жыл бұрын
Could you please give some examples where these equations which we need to use other than in some exams. it would be great
@cadkls
@cadkls 4 жыл бұрын
Plenty exponential equations in physics Nuclear decay equationnis a good example. Not all maths is for everyday life, a lot is usually mostly just applicable to physics
@JoeTaxpayer
@JoeTaxpayer 3 жыл бұрын
Am I mistaken? I got 1.1868 - did you round wrong or did I?
@harisazharibinzaharudin2079
@harisazharibinzaharudin2079 4 жыл бұрын
i saw phi right there..
@anthonyvan35
@anthonyvan35 3 жыл бұрын
passive !
@fillemptytummy
@fillemptytummy 4 жыл бұрын
Now you know.
@Jimmy-tv8tv
@Jimmy-tv8tv 3 жыл бұрын
Can you solve 3^x+4^x=5 ^x
@pharaohobame6187
@pharaohobame6187 2 жыл бұрын
X = 2
@Jimmy-tv8tv
@Jimmy-tv8tv 2 жыл бұрын
@@pharaohobame6187 step by step
@tae4thehyun
@tae4thehyun 4 жыл бұрын
4:13 I understand everything except this what is the right hand side thing, is it a formula?
@AJ-uz5hr
@AJ-uz5hr 3 жыл бұрын
yes it is a formula used to find variables in quadratic equation like if you want to find x in : x^2+5x+6=0....... then you can use the formula, the name of the formula is shridharacharya formula
@user-nz7rg9ri1e
@user-nz7rg9ri1e 3 жыл бұрын
+++
@italixgaming915
@italixgaming915 2 жыл бұрын
This problem is elementary: 2^x+4^x=8^x 2^x+2^(2x)=2^(3x) 2^x+(2^x)²=(2^x)^3 If y=2^x we have: y+y²=y^3 So y=0 or y²-y-1=0 The solutions for y are: 0,(1+sqrt(5))/2, (1-sqrt(5))/2 2^x=0 has no solution. 2^x=(1+sqrt(5))/2 has a real solution which is log((1+sqrt(5))/2)/log(2). 2^x=(1-sqrt(5))/2 has no solutions in R but you can solve this in C. (1-sqrt(5))/2=-i².(sqrt(5)-1)/2=e^(i.(2k+1).pi).e^(log(sqrt(5)-1)/2)=e^(log(sqrt(5)-1)/2)+i.(2k+1).pi) (k is an relative integer ) So e^(log(2)x)=e^(log(sqrt(5)-1)/2)+i.(2k+1).pi) x=(log(sqrt(5)-1)/2)+i.(2k+1).pi)/log(2)
@benjaminkarazi968
@benjaminkarazi968 Жыл бұрын
Hello, The fundamentals of this problem are wrong. There are many answers to the problem; nevertheless, they all are fallacies. x=-1.6580e³, x=-1.658001e³, x=-1.65808713446e³...→∞
@glosan
@glosan 4 жыл бұрын
It's very hard to understand 🤣🤣🤣
@bidarvandi
@bidarvandi 3 жыл бұрын
if you are interested you will undersyand math takes time it is just like watching movie in your free time.
@shaistabadar3529
@shaistabadar3529 2 жыл бұрын
Qabool ho
@shaistabadar3529
@shaistabadar3529 2 жыл бұрын
America ki apni oqat haqiqat
@cristianomoschella7715
@cristianomoschella7715 3 жыл бұрын
x+2x=3x 3x =3x x=1
@superheavydeathmetal
@superheavydeathmetal 11 ай бұрын
For 3x = 3x, x can be any number, not just 1. But, if you plug 1 into the original equation, you get 2^1 + 4^1 = 8^1 ... 2 + 4 = 8 ... and that is not correct.
@onlythewise1
@onlythewise1 2 жыл бұрын
learn the language first
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