Solving Exponential Equations Using Logs

From Thinkwell's College Algebra
Chapter 6 Exponential and Logarithmic Functions, Subchapter 6.4 Exponential and Logarithmic Equations

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I was struggling with a question and this example just answered it for me. Thank you very much.

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Never thought I'd understand the maths. Thank you friend

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[@strongarmygraaape4132]

waht if you got a negavtive log and x and you got a positive log with x also how do u deal withit?

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Super helpful!!! Thanks a bunch

[@JossinJax]

Hello. Would you ever bring the log's coefficient's negative sign up to the log's power?

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Thank you! I don't understand logs. I feel a little better now

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[@tobygerig4822]

for the quesiton involving different bases cant you find a common factor and then u have the same base?

[@mrannunaki6852]

why is it when you are expanding the logs the "x" goes after the log but the number goes out front as a coefficient ..so (2x+1) log4 goes to (2log4)(x) + log4 .. but why not (log4)(2x)+Log4 ???

[@thelight7997]

Thanks alot this really helped

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Incredible

[@glasssmirror2314]

Tks sir for uploading Pls I was waiting whether you would prove those by solving without logs please help if for at least one.

[@severinus993]

Thank You very much

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[@ChelCoh]

I have problems like (1/216)^-x-3 = 36 , how would you do that?

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Not the hero we deserve but the hero we need

[@imogenclaire1069]

Does anyone know how to do a simpler exponential equation? I have to do 5^x = 200 and solve for x but I have no idea how. I can't find the common base because 5 and 200 have no common base and I've tried using logs but I don't see how they can help

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whte the base for log

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2:38 EASY and straight forward

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[@rizzexfolkman2012]

My 2 cents.... so at the end you have log(20)*x=log(8/5), isolation of x by dividing would give log(8/5)/log(20) ; this is not the quotient property of logs though, took me a minute to see it, have the log rules written down in front of you to easily cross reference when simplifying.

[@KaennC]

holy shit, bursted into laughs as soon as i the talking started

[@minarostai9335]

thank you very much, what law applies to solving this: 10 to the power of log X help please

[@zekayman]

+Amena Omari You can't solve that unless it's equal to something. What is it equal to?

[@carfordelgado]

Had I seen this video two days ago i probably had gotten a better number on my precalc. Test.