Solving Modulus Equations and Inequalities

  Рет қаралды 56,022

Tulla Maths

Tulla Maths

Жыл бұрын

How to solve Modulus inequalities and equations. Also know as solving absolute value inequalities. Modulus inequalities revision questions / handout. Absolute Value Equations. Leaving Cert Maths and a levels.

Пікірлер: 50
@user-fv8xd7vm1p
@user-fv8xd7vm1p 15 күн бұрын
that's great sir
@tullamaths
@tullamaths 15 күн бұрын
very welcome
@crisismajoka7064
@crisismajoka7064 8 ай бұрын
Thank you Sir
@tullamaths
@tullamaths 8 ай бұрын
no problem - glad you found it helpful
@twistashorts403
@twistashorts403 6 ай бұрын
Thank you sir love from Pakistan
@tullamaths
@tullamaths 6 ай бұрын
Great Tulla Maths is reaching Pakistan
@pathummadusanka2271
@pathummadusanka2271 Жыл бұрын
Thank you...
@tullamaths
@tullamaths Жыл бұрын
Im glad it helped
@riyaskhan7276
@riyaskhan7276 22 күн бұрын
Thankyou sir.. 💌in part 12:17 how did you solve the eqn into (3x+ 7)(x+5) i mean which were the numbers that you considered?
@tullamaths
@tullamaths 14 күн бұрын
it is factorising quadratics. Please check this video if you need support. Any queries, let me know. kzbin.info/www/bejne/i5bOdaafq9yrj9E
@AD99111
@AD99111 10 ай бұрын
Explanation is good , TNX
@tullamaths
@tullamaths 9 ай бұрын
I'm glad it helped !
@mubitanosiku2904
@mubitanosiku2904 10 ай бұрын
Thank you
@tullamaths
@tullamaths 9 ай бұрын
you're welcome
@gemmadominic1096
@gemmadominic1096 29 күн бұрын
Thank you ❤
@tullamaths
@tullamaths 29 күн бұрын
you're welcome!
@kifayatshabir5468
@kifayatshabir5468 Жыл бұрын
thank u from kashmir
@tullamaths
@tullamaths Жыл бұрын
Glad to help !
@wooyoungwang8021
@wooyoungwang8021 3 ай бұрын
how do you solve inequalities when there is a - or + outside of the abs(x)? e.g abs(x-1)>4-abs(x+1)?
@user-ou2ze8nt7d
@user-ou2ze8nt7d 3 ай бұрын
Just question cus Im struggling with factoring. Where did you get the 15 (FIFTEEN) to add to (7+5) in the part 12:00 ?
@tullamaths
@tullamaths 3 ай бұрын
Factorising can always be though. The fifteen is coming from multiplying the 3x by 5 = 15x. Then multiplying the x by 7= 7x. Add 15x and 7x makes the 22x. Perhaps watch this video and it could help better kzbin.info/www/bejne/i5bOdaafq9yrj9E
@Carrymejane
@Carrymejane 2 ай бұрын
Polynomial
@landmine5702
@landmine5702 Ай бұрын
It's great but lengthy process!
@sameerajshortfilimes8959
@sameerajshortfilimes8959 3 ай бұрын
Thxs broo nice explanation tq soo much
@tullamaths
@tullamaths 3 ай бұрын
no problem at all - glad it helped
@yousafahmed9509
@yousafahmed9509 24 күн бұрын
taught me faster than my teacher
@tullamaths
@tullamaths 24 күн бұрын
great that it helped you
@user-ib5fp6hh5r
@user-ib5fp6hh5r Ай бұрын
It's easy of course but I'm alitle bit confused here (x-2)² ....was it not supposed to be difference of two square?
@tullamaths
@tullamaths Ай бұрын
difference of two squares is when squaring each part separately, such as (x)² -(2)² . Hope this clarifies.
@user-ib5fp6hh5r
@user-ib5fp6hh5r Ай бұрын
@@tullamaths much appreciation...it's clear now
@tullamaths
@tullamaths Ай бұрын
@@user-ib5fp6hh5r best of luck with your studies
@Carrymejane
@Carrymejane 2 ай бұрын
Crispy
@Erupto.
@Erupto. 27 күн бұрын
How do you solve |x-2| = |x| +1? Does anyone have any ideas?
@PumuloMwemba
@PumuloMwemba Ай бұрын
How did get to conclusion of example 1 and 2. In example 1,6 is correct however when you minus 2 from -2 it doesn't give you 4. In example 2 is it not suppose to be -25😢😢. I'm already confused ain't planning to go further 💔
@tullamaths
@tullamaths Ай бұрын
-2 -2 is = -4 modulus of -4 = 4 as per my video. Be careful with your rules of subtraction. Example 2 the answer is x=2 as per video (not -25 as you state).
@ManishiPabodini
@ManishiPabodini 7 ай бұрын
How to draw modular graph in Y = 4 - |2x - 8|
@mehzabinrashid890
@mehzabinrashid890 Жыл бұрын
Your method is too lengthy+complicated... infact the first math you have done is way too lengthy and on the other hand I completed it within 2 lines only. Please try to make it easy
@tullamaths
@tullamaths Жыл бұрын
There are many methods to solving mathematical problems. My tutorial video aims to explain just one of these methods.
@Jee2024IIT
@Jee2024IIT Жыл бұрын
You can't square both sides in inequalities 🤦 because x is a variable it can be a negative value too You have murdered all the laws in mathematics
@atharvsoni5308
@atharvsoni5308 10 ай бұрын
sguares are always positive. aise karega iit?
@Jee2024IIT
@Jee2024IIT 10 ай бұрын
@@atharvsoni5308 -4 < 3✅ Squaring both sides (-4)² < (3)² 16
@sttlok
@sttlok 7 ай бұрын
In this case you can because both sides are positive, plus |x| = sqrt(Re(x)^2 + Im(x)^2) which is sqrt(x^2) for all real numbers.
@ai-lingji4252
@ai-lingji4252 7 ай бұрын
Both sides can be squared when both sides of the modulus inequality are absolute values, because -4 < 3, but |-4|>|3|, so both equations can be squared
@VanshYadav-yb8dd
@VanshYadav-yb8dd 8 күн бұрын
its three not tree
@yifengxiao
@yifengxiao 7 ай бұрын
misleading, make easy to complicate!
@Uchiha...Itachi
@Uchiha...Itachi 5 ай бұрын
Agreed,this isnt hard but overcomplicated for no reason
@Carrymejane
@Carrymejane 2 ай бұрын
It's not that hard if u understand polynomial 😌
@Uchiha...Itachi
@Uchiha...Itachi 2 ай бұрын
@@Carrymejane doesn't matter there are easier ways
@xlr8gff215
@xlr8gff215 2 ай бұрын
Thank you
@tullamaths
@tullamaths 2 ай бұрын
You're very welcome
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