How to solve Modulus inequalities and equations. Also know as solving absolute value inequalities. Modulus inequalities revision questions / handout. Absolute Value Equations. Leaving Cert Maths and a levels.
Пікірлер: 50
@user-fv8xd7vm1p15 күн бұрын
that's great sir
@tullamaths15 күн бұрын
very welcome
@crisismajoka70648 ай бұрын
Thank you Sir
@tullamaths8 ай бұрын
no problem - glad you found it helpful
@twistashorts4036 ай бұрын
Thank you sir love from Pakistan
@tullamaths6 ай бұрын
Great Tulla Maths is reaching Pakistan
@pathummadusanka2271 Жыл бұрын
Thank you...
@tullamaths Жыл бұрын
Im glad it helped
@riyaskhan727622 күн бұрын
Thankyou sir.. 💌in part 12:17 how did you solve the eqn into (3x+ 7)(x+5) i mean which were the numbers that you considered?
@tullamaths14 күн бұрын
it is factorising quadratics. Please check this video if you need support. Any queries, let me know. kzbin.info/www/bejne/i5bOdaafq9yrj9E
@AD9911110 ай бұрын
Explanation is good , TNX
@tullamaths9 ай бұрын
I'm glad it helped !
@mubitanosiku290410 ай бұрын
Thank you
@tullamaths9 ай бұрын
you're welcome
@gemmadominic109629 күн бұрын
Thank you ❤
@tullamaths29 күн бұрын
you're welcome!
@kifayatshabir5468 Жыл бұрын
thank u from kashmir
@tullamaths Жыл бұрын
Glad to help !
@wooyoungwang80213 ай бұрын
how do you solve inequalities when there is a - or + outside of the abs(x)? e.g abs(x-1)>4-abs(x+1)?
@user-ou2ze8nt7d3 ай бұрын
Just question cus Im struggling with factoring. Where did you get the 15 (FIFTEEN) to add to (7+5) in the part 12:00 ?
@tullamaths3 ай бұрын
Factorising can always be though. The fifteen is coming from multiplying the 3x by 5 = 15x. Then multiplying the x by 7= 7x. Add 15x and 7x makes the 22x. Perhaps watch this video and it could help better kzbin.info/www/bejne/i5bOdaafq9yrj9E
@Carrymejane2 ай бұрын
Polynomial
@landmine5702Ай бұрын
It's great but lengthy process!
@sameerajshortfilimes89593 ай бұрын
Thxs broo nice explanation tq soo much
@tullamaths3 ай бұрын
no problem at all - glad it helped
@yousafahmed950924 күн бұрын
taught me faster than my teacher
@tullamaths24 күн бұрын
great that it helped you
@user-ib5fp6hh5rАй бұрын
It's easy of course but I'm alitle bit confused here (x-2)² ....was it not supposed to be difference of two square?
@tullamathsАй бұрын
difference of two squares is when squaring each part separately, such as (x)² -(2)² . Hope this clarifies.
@user-ib5fp6hh5rАй бұрын
@@tullamaths much appreciation...it's clear now
@tullamathsАй бұрын
@@user-ib5fp6hh5r best of luck with your studies
@Carrymejane2 ай бұрын
Crispy
@Erupto.27 күн бұрын
How do you solve |x-2| = |x| +1? Does anyone have any ideas?
@PumuloMwembaАй бұрын
How did get to conclusion of example 1 and 2. In example 1,6 is correct however when you minus 2 from -2 it doesn't give you 4. In example 2 is it not suppose to be -25😢😢. I'm already confused ain't planning to go further 💔
@tullamathsАй бұрын
-2 -2 is = -4 modulus of -4 = 4 as per my video. Be careful with your rules of subtraction. Example 2 the answer is x=2 as per video (not -25 as you state).
@ManishiPabodini7 ай бұрын
How to draw modular graph in Y = 4 - |2x - 8|
@mehzabinrashid890 Жыл бұрын
Your method is too lengthy+complicated... infact the first math you have done is way too lengthy and on the other hand I completed it within 2 lines only. Please try to make it easy
@tullamaths Жыл бұрын
There are many methods to solving mathematical problems. My tutorial video aims to explain just one of these methods.
@Jee2024IIT Жыл бұрын
You can't square both sides in inequalities 🤦 because x is a variable it can be a negative value too You have murdered all the laws in mathematics
In this case you can because both sides are positive, plus |x| = sqrt(Re(x)^2 + Im(x)^2) which is sqrt(x^2) for all real numbers.
@ai-lingji42527 ай бұрын
Both sides can be squared when both sides of the modulus inequality are absolute values, because -4 < 3, but |-4|>|3|, so both equations can be squared
@VanshYadav-yb8dd8 күн бұрын
its three not tree
@yifengxiao7 ай бұрын
misleading, make easy to complicate!
@Uchiha...Itachi5 ай бұрын
Agreed,this isnt hard but overcomplicated for no reason
@Carrymejane2 ай бұрын
It's not that hard if u understand polynomial 😌
@Uchiha...Itachi2 ай бұрын
@@Carrymejane doesn't matter there are easier ways