Space and time analysis of Insertion Sorting-2 | Analyzing an algorithm |Data Structure & Algorithms

[@pragyan152]

what a explanation!!!!! I have gone through many no of lectures and book this one is simply amazing

[@rajnandinipatel81]

hats off to your pedagogy. literally understood every segment of the code.

[@karanamunjani8451]

WOWWW!! It is "the" best explanation I seen. Thank You so much!!!

[@GATEAppliedCourse]

Glad it was helpful!

[@Zleurstars]

indian teachers are so intuitive and know what the students struggle with absolutely amazing!!

[@TheFineDine_]

awsome explaianation...no one has teach this topic better than u

[@blue-go4gr]

GOD BLESS YOU ..... I can not express enough how much this vid helped me .... I was this close 👌 to cry ;-;

[@GATEAppliedCourse]

Thank you.

[@dishithagurram4154]

This way of explanation is just amazing!

[@SmilesOnly101]

this video and part 1 of this video togeather are the best possible explanation in a very detailed and relaxed manner. I am simply too amazed and grateful to find such an amazing lecture in this. I saw all this written in my notes and was not able to understand it myself. than you sir .

[@rajeshrajendran5512]

This is the explanation I always wanted from an Algorithm analysis point of view. Great job.

[@kanikakhatri09]

OMG!!! just loved the way u explained each and every concept. LOVE LOVE LOVE

[@Sam-kr5ix]

What an amazing explanation keep up the great work

[@GATEAppliedCourse]

Thanks, will do!

[@angitd3766]

one of the best explainations ever

[@tahirbintariq8934]

Such a beautiful explanation sir!!!

[@nadun_li]

This explation really helps. Thankyou so much

[@bassmw8175]

Excellent. You explain it very well!

[@jinhuang7258]

So good. Thank you for sharing your knowledge and passion with us.

[@muhammadabrar9057]

this man is love.... love from pakistan

[@daniaayad5874]

that was a very useful video, the explanation is perfect thank you soo much

[@naziyabegum9163]

thannkkk youuu sir for this video, I was struggling with this topic and I am glad that I have found this video.

[@ghulamahmad6688]

hats off !! amazaing !!

[@mrsmelaniecook]

Thank you so much. I finally got it!

[@madhuram6328]

But sir one doubt as you said the maximum number of comparison will be 1 (for j=2) for worst case . But this is not about comparison it is about no of time the while loop gets executed so the maximum number of times the for loop gets executed is 2 for (j=2)( ex a={10,9,8,7 } here n is the length therefore it is 4 and the element 9's for loop gets executed 2 time because first time the condition will be true and for the second time it becomes false and the loop gets terminated. So the minimum number is 2 not 1. and the contents or the statements inside while loop gets executed only one time). Someone correct me if I'm wrong.

[@thebishalpaul]

Absolutely correct for which the max times while loop(not comparison) will run would be (n*(n+1)/2)-1 i.e for j=2 while count: 2 for j=3 while count 3 and so on so exclude the first number from sum of n nos.

[@lmcst2821]

Thanks man. I had doubts because in Cormen's Algorithms book it said \sum_{i=2}^n t_i but I was not so clear about it.

[@paramjeetsingh3444]

sir I have a lot to write for the video but i think 1 word will cover it all.. THANK YOU

[@lzmkalos]

best explication everrrrrr

[@ManojK-jl2ue]

excellent explanation...thank you sir

[@HafidRecords]

Thank you. Finally I could understand!

[@arpitbhaliya2972]

Great👍😊

[@yoursgkt2927]

It will be really helpfull if you can share these slides.

[@3bood_kr]

Worst case is when the array is sorted in descending order

[@techso605]

I want to ask that the swapping and the decrement of i will be one less then the time while loop is executing so we should minus 1 in 6th and 7th step in worst case.

[@davewebb3540]

I was with you up until the a, b bit. How did you sum it all up? Feel like I'm missing something.

[@syedmuhammadmusab554]

Thankyou. you have explained beautifully. :)

[@gateprep8076]

Sir I have the same doubt In worst Case the array should be reverse sorted. Please make it clear. Rest of the content is super clear. I appreciate that.

[@RaniLink]

When you get to the 5th element the 4 elements prior to it have been sorted. so the array might as well been reverse sorted, then this individual worst case had happened for every number along the way up to the 5th one.

[@donkeykong5616]

Doin gods work

[@iamnottech8918]

Just wow

[@pruff5072]

My textbook for worst case on line 5 has a slightly different answer: c5 * ((n(n+1)/2) -1

[@SVNITPhool]

Yes that's correct becuase in worst case j comparison not j-1 .so 2+3+.......+n=(n*(n+1)/2)-1.

[@StatusKing12]

In the book did they use for loop?

[@oitik]

it helped thamks

[@amoodaniel]

pls, what app did you use for the onscreen writings?

[@gavinaren8534]

Perfect vid

[@АйдарБабанов-ж4п]

I think, you made a mistake in number of comparisons for j. if j == 2, then i == 1. We make comparison and after one iteration of while loop i becomes 0. Then we make last comparison. So, max amount of comparisons starts from 2 to n. Number of swaps is correct.

[@shreyanshayanger]

When i becomes 0 we don't compare as the conditon "i > 0" get's violated in while loop.

[@АйдарБабанов-ж4п]

@@shreyanshayanger well, if i becomes 0, we have to make one last comparison, the condition (i>0) why loop stops it's working.

[@АйдарБабанов-ж4п]

@@shreyanshayanger so if j==2, amount of comparisons for i is 2.

[@shreyanshayanger]

@@АйдарБабанов-ж4п no brother ....the program enters in comparison phase when "i>0" if i=0 the program won't run the code in while's body hence no comparison

[@shreyanshayanger]

@@АйдарБабанов-ж4п when j = 2 , i=j-1 ,so only one comparison between A[i]/A[1] and A[j]/A[2]

[@syedmuhammadmusab554]

isn't the value of c1,c2...cn should remain constant otherwise there will be arbitrarily growth which we do not want??

[@grandparick3176]

What will be the avg case for this? I know its the same as the worst case but can anyone show by steps.

[@louerleseigneur4532]

Thanks sir ji

[@safwansabir7566]

the math of time complexity is wrong is should be ((n+2)(n-1))/2 not n(n+1)/2 you can dry run the algo yourself and compare the answers with both equations yourself

[@captainabhijeeth3154]

Sir,I did't get that how it became "an+b"

[@aimenbaig6201]

same

[@punitpal315]

Sir here when u r explaining worst case , u taken array in which all element are sorted except element 0 . So it will not give worst case complexity. So according to me for worst case you have to take array which should be completely in descending order for worst case . Thank you

[@RaniLink]

When you get to the 5th element the 4 elements prior to it have been sorted. so the array might as well been reverse sorted, then this individual worst case had happened for every number along the way up to the 5th one

[@musmanmureed3728]

Excellent. You explain it very well!