Spring-Mass-Damper System, 2DOF

[@antoniosantos6104]

Amazing video, I am currently studying for my final for a Dynamic Systems and Modeling class and was looking for extra practice. You videos are exactly what I was looking for!

[@youham7066]

Finally found a helpful and full steps video related to my coursework. I hope youtube can recommend more similar video like this 😁. Thanks for saving my time!!!

[@Are-you-mad-at-me]

I was stuck on this concept and then i just went and compared class notes with your video and understood everything. Thank you so much.

[@aidanstark5381]

Thank you very much! This video was extremely helpful in my studies.

[@marcusmaree5338]

This has been extremely helpful. Thank you very much!

[@Jotaruiz30]

Muchas gracias por compartir, muy bien explicado y me sirvio para entender bien el tema.

[@Final1Boss]

Thank you!! you should get a Nobel prize for your perfect teaching

[@micahbaldonado4627]

i agree

[@natursweg7815]

Thank you for this video! It was very clear and helpful!

[@우창-n9t]

this video helped me a lot. Thank you

[@bowaleed3900]

I think "C2" force must be flipped since it "Pulled by the ext. force" , as well as the forces itself should be opposite to each other , Newton 3rd Law

[@omarrefe460]

Thank you so much ... THANK YOU !!!

[@cleternal]

good job! thanks a lot

[@aliakbas7387]

Sir, how can we demonstrate that if we chose C2 too large that system behaves as a single mass M=m1+m2?

[@fikrimisnadi2374]

Do you have any example with external force

[@diegomestrecam7674]

Thanks! One question how would tf change if we also had a spring and damper between car 1 and 2 ?

[@theryderproject5053]

Yes if you have more springs it would change transfer function.

[@behnazhadi7110]

Thanks

[@abdullatifaydn6681]

the left side of the equation must also be positive because they are in opposite directions...(+)kx + (+)cx + (+)c(x-x) =mx ....this correct

[@TheNightDevilX]

No, because left side is summing all forces, negative and positive, and right side is just m*a, or m*x in this case in positive x direction.

[@Final1Boss]

it's correct in the video, it could either be -kx1 -c1x'1 -c2(x'2-x'1) = m1x1" or -kx1 -c1x'1 +c2(x'1-x'2) = m1x1"

[@ridwanhusainishraq]

Dear Maam could you please make a video on transfer function of 2nd order differential equations involving friction coefficient on the floor?

[@devilal8388]

Hello mam Does this 2 DOF system will vibrate or not Like displacement is periodic function of time in this case Please tell me

[@theryderproject5053]

How it will vibrate is going to depend on the type of force input and the values associated with the components. This is demonstrated in some later videos in the vibration and control playlist.

[@danielmj4773]

But why dont we use x1 to find the transfer function

[@theryderproject5053]

Only because the original question asked for the transfer function X_2/F. If you were asked for X_1/F then you would solve for it using Cramer's rule.

[@danielmj4773]

@@theryderproject5053 oh . On thank you. This video has been a huge help

[@benguyldzzeyrek7388]

why do we write x1-x2

[@theryderproject5053]

I think it is the derivative of this (velocities) because that's the velocity that the damper is moving at - need to take the difference because both ends can move.

[@benguyldzzeyrek7388]

@@theryderproject5053 so can we write x2-x1 in the same manner

[@theryderproject5053]

@@benguyldzzeyrek7388 The direction matters. Try rewatch from around 1.45. I've assumed that m1 is going to move to the right so the force is directed back to the left. This makes the order for the force x1dot-x2dot.

[@theryderproject5053]

Also watch from 11.15 for a method to double check whether you've got the signs right.

[@benguyldzzeyrek7388]

@@theryderproject5053 okay thank you so much