SQL Mock Interview (Data Analyst): Departments with the Highest Revenues

  Рет қаралды 53,461

Exponent

Exponent

Күн бұрын

Пікірлер: 34
@tryexponent
@tryexponent Жыл бұрын
Don't leave your SQL interviews to chance. Sign up for Exponent's SQL interview course today: bit.ly/3TYla1W
@kaboyodaniel3630
@kaboyodaniel3630 Жыл бұрын
Thanks for all you do. Always a joy to follow along. Wish there was more videos like this.
@pakalupapito3202
@pakalupapito3202 9 ай бұрын
Landed my data analyst job thanks
@tryexponent
@tryexponent 8 ай бұрын
Congrats!! 🎉
@prateeksenapati2152
@prateeksenapati2152 Жыл бұрын
For the question on "second highest order amount in the fashion department", should we be using DENSE_RANK() instead of RANK() - since if 2 orders have the highest amount then the third order (which is the second highest amount order) will get a rank of 3 using RANK() and a rank of 2 using DENSE_RANK()?
@funtik_777
@funtik_777 Жыл бұрын
where o.order_date in (2019 etc) should not give expected result. Need to use year(o.order_date) in(2019,2020 etc
@mohammadnasser9951
@mohammadnasser9951 Жыл бұрын
at 27:27 do we really need to group by c.first_name and c.last_name? I mean we already grouping by c.customer_id which has a kind of one-to-one relation with the first and last name
@asceticadarsh8284
@asceticadarsh8284 10 ай бұрын
27:51 Mistake CTE order_rankings have mention but in query orders_ranked
@georgemouxios8248
@georgemouxios8248 2 ай бұрын
@27:46 orders_ranked =1 should be order_rankings = 1
@Alpha408
@Alpha408 Жыл бұрын
Thanks a million for this work, highly appreciated as i'll be applying for data positions at the end of the year. Quick observation; The cte in the third query was not used, cte = orders_per_year . And the rank was not also used either
@dickyalamsyah790
@dickyalamsyah790 Жыл бұрын
You can’t group by within rank function actually
@georgemouxios8248
@georgemouxios8248 2 ай бұрын
Great job dude. Well Donee
@sem1246
@sem1246 Жыл бұрын
thanks for the video, it's really useful
@ДаниилПетровский-ц7б
@ДаниилПетровский-ц7б 10 ай бұрын
hello! i would like get to know such information like: this interview is for what level, for instance, junior or middle, maybe senior?
@HoaTa-e4n
@HoaTa-e4n 5 ай бұрын
For the second to last question, can we do ORDER BY o.order_amount DESC, LIMIT 1, OFF SET 1, so that we don't have to use rank() ??
@MrTeslaX
@MrTeslaX 9 ай бұрын
I feel like interviewer's focus on the parts that aren't really important i.e 18:20. Focus should be on testing the logic and the ability to get to the solution.
@aliaksandrmatrunich2056
@aliaksandrmatrunich2056 Жыл бұрын
order_date>= YEAR(CURRENT_DATE - INTERVAL 5 YEAR);
@angkhoi6111
@angkhoi6111 9 ай бұрын
thanks for all
@AshishPatil-u1u
@AshishPatil-u1u Жыл бұрын
w7.w3 wrong to group by customer and year,.. it should be only group by customer.
@anshikarastogi1472
@anshikarastogi1472 6 ай бұрын
How would the Lag function pick up month 11 records when there is a where filter on month = 12?
@TalhaFurqan-l4n
@TalhaFurqan-l4n 6 ай бұрын
Is this mock interview for an entry-level data analyst position or a senior level?
@tryexponent
@tryexponent 6 ай бұрын
Generally, you can expect SQL questions for both entry-level and senior data analyst positions
@mildlydisastrous7818
@mildlydisastrous7818 4 ай бұрын
Almost every written query had very serious issues and either won't run at all or would give wrong answers. I'm not talking about typos, I'm talking about using an aggregate function when defining an order inside a partition clause, for example, which is not possible. Or using a window function AND a group by in a same query, which won't give the result he was hoping for. Or, as was done in his last query, filtering the data to only include one month and then using the lag function. Filtering with where is executed before the lag, so by the time lag is executed, the dataset has only records for december, meaning he will get nulls for every department. This is not a comprehensive list of issues, mind you, there are more. And that's just serious issues. In addition to that most of his filtering conditions were non-sargable, and he never thought about edge cases. For example, in the second problem it is possible that there were no users who bought something from one of the departments, and in that case the inner join he used would have lost that department, it wouldn't show in the result at all. Is it a plausible situation when working with real data? No. But it is definitely possible, and it should have been at least mentioned. Overall I am very disappointed with both the interviewee and the interviewer, who missed all of the mentioned mistakes.
@nilsaha8021
@nilsaha8021 9 ай бұрын
I did not understand the code of the last question. He had to calculate the increase or decrease in month-over-month growth for the year 2022. What was the basis for creating the CTE for November and December (hardcoded)? In the second CTE, he filtered out only the December amount. Does it calculate and compare all the data back to January?
@MrKhulaid
@MrKhulaid 6 ай бұрын
You also used orders_ranked=1 in your main query but your cte is orders_ranking. I don't think that'll work
@joaofernando9346
@joaofernando9346 4 ай бұрын
He could have used the extract() to get the year.
@ajaycb590
@ajaycb590 Жыл бұрын
The queries for sure have a lot of errors. Cant group by in rank
@Clazer07
@Clazer07 Жыл бұрын
for the last question...
@Clazer07
@Clazer07 Жыл бұрын
With nov_dec_sum as ( Select department_name, sum(case when year(order_date) = 2022 and month(order_date) = 11 then order_amount else 0 end as nov_sum, sum(case when year(order_date) = 2022 and month(order_date) = 12 then order_amount else 0 end as dec_sum From orders o join department d on o.orders_id = d.orders_id Group by department ) Select department_name, From nov_dec_sum Order by nov_sum - dec_sum desc Limit 1
@emmanuelameyaw9735
@emmanuelameyaw9735 6 ай бұрын
Can AI answer those questions?
@shubhamdabhade3004
@shubhamdabhade3004 Жыл бұрын
👍
@ArnavSinghRana-j3f
@ArnavSinghRana-j3f 2 ай бұрын
list of cust_id w most orders in last 5 years 5 years,5 last_name, 5 first_name, total amount of orders per customer SELECT c.cust_id, c.last_name, c.first_name, year(o.order_date) as years, COUNT(o.order_id) AS total_orders, SUM(o.order_amount) AS total_order_amount FROM customers c JOIN orders o ON c.cust_id = o.cust_id WHERE o.order_date >= DATE_SUB(CURDATE(), INTERVAL 5 YEAR) GROUP BY c.cust_id, c.last_name, c.first_name ORDER BY total_orders DESC LIMIT 5; how about this answer ?
@suchitkakirde1733
@suchitkakirde1733 11 ай бұрын
SELECT customer_id, COUNT(order_id) AS total_orders FROM orders WHERE order_date >= CURRENT_DATE - INTERVAL '5' YEAR GROUP BY customer_id ORDER BY total_orders DESC LIMIT 1;
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