Stable & Unstable Discrete Time Systems

[@awesomearchit111]

1. Unstable 2. Unstable 3. stable

[@MindfulHobbyist]

what if we take 2^-infinite=0.finite=0:finite then second become stable

[@Deepak_3860]

@@MindfulHobbyist we have to take atleast one value of n, for which it gets unbounded.

[@letwisdomgoviral2254]

I got 85% in my Signals & Systems end exam :)... I ve put in only 1 day to listen to urs... Exam done. 🤗🤓🤓 My entire clg follows ur channel only...

[@shabinaa6407]

1) unstable 2) unstable 3) stable

[@abhishek1830]

1,2 unstable 3 stable

[@sneharajpoot8377]

1. Unstable System 2. Unstable System 3. Stable System

[@prakashdjr172]

thanks sir, you are great

[@qaderexpert4316]

1 and 2 are unstable 3 is stable

[@vivekiyer9482]

Hw Problems 1) Unstable 2) Unstable 3) Stable

[@ertugrul98835]

Unstable, unstable, stable

[@DrAbdullahjameel]

i- Unstable. ii- Unstable. iii- Stable.

[@toppoint360]

1) y[n]=ln(x[n]) 2) y[n]=log(x[n]) 3) y(t)=e^at.x(t) 4) y(t)=1/x(t) can you determine each of them stable or not .also give reason please and thank you

[@dohamagdy6466]

how is the last one is stable???

[@rekcahenon5340]

I think for BI we get bounded output...

[@ujjawal1366]

Check the formula of even

[@karthikvenkata6484]

1)US 2)US 3)s

[@Cap_levi_23]

Q y(n) = ax(n-t)

[@rishabhbahoria1298]

1 unstable 2 unstable 3 unstable

[@lalitbindal7779]

how last one is stable

[@praveen929]

us -1,2 s-3

[@sanchitathombare6622]

👍👍

[@pathaktutorial5168]

Unstable unstable stable

[@ujjawal1366]

Only 3 is stable.

[@mbhagyarajareddy4639]

1. Unstable 2. Unstable 3. Stable

[@toppoint360]

1) y[n]=ln(x[n]) 2) y[n]=log(x[n]) 3) y(t)=e^at.x(t) 4) y(t)=1/x(t) can you determine each of them stable or not .also give reason please and thank you

[@vavilapallisatyavenkatasan6563]

@@toppoint360 For natural logarithm (logarithm with base e i.e, lnx ) and for the common logarithm (logarithm with base 10 i.e, logx ) As x approaches to zero the values of lnx and logx approaches to -infinity, so in the first two questions when the input is made zero i.e, bounded, the output is becoming unbounded, so the first two systems are unstable. In the third system, depending on 'a' value in the coefficient, for a>0, even with bounded input if you make t tend to infinity, the coefficient tend to infinity there by making output tending to infinity, making the system unstable. for a

[@itsformac]

@@toppoint360 all unstable

[@kaavyasameerasajja6730]

Unstable,unstable ,stable