Step Response of a System

[@princechoudhary5772]

The work done by this channel for the sake of students is beyond perfection.... the amount of hard work being put on by Neso academy is commendable ... Your work transcends all the best created contents ... Keep working hard and keep growing.. Lots of love and respect.. 😊😊❤🔥 🔥

[@sukhdevasole1825]

Sir I see your c programming lecture which I saw the best in yt platform......thanks sir for providing such a beautiful content for free❤️

[@vishnuchandran243]

explained in very simple manner, got the concept very well, thanku sir

[@mydearsantosh]

Outstanding explanation in short time.

[@mohammadkhaliquekhan2041]

Thanks a lot neso academy please complete control system before gate 2021 it would be so helpful ❤️

[@PunmasterSTP]

How did the Gate go?

[@mateoarteaga8274]

You omitted the unit step function because it is equal to 1 from 0 to infinity, but when you integrate unit step function you get area under the curve which is not equal to 1

[@jonathancardonagarcia7476]

For part b, I performed the convolution of u(t) and h(t) where u(t) is the step input and h(t) is the time domain transfer function. The convolution of u(t) and h(t) is e^(-2t)*u(t). From here, take the derivative with respect to time on both sides. On the left hand side, use the fundamental theorem of calculus part 1 to figure out that the integral of h(tau) d(tau) from 0 to t is just h(t). Note, u(t-tau) is equal to 1 from 0 to t. u(t-tau) represents the shifted function in the convolution operation. On the right hand side, perform the product rule and realize that the derivative of the step input is the Dirac Delta Function (the impulse function). h(t) turns out to be -2e^(-2t)*u(t)+delta_0(t)*e^(-2t). Taking the Laplace Transform of h(t) gives H(s) which is the Transfer Function of the system. H(s) turns out to be -2/(s+2)+1. Multiplying H(s) by 1 gives Y(s), the impulse response. Taking the Inverse Laplace Transform of Y(s) gives y(t) equals delta_0(t)-2*e^(-2t).

[@sanskarkumar6484]

thanks Sir🙏❤

[@ushamemoriya5391]

Select all the correct answers. A discrete-time system's response to a step input can be found by: Select 2 correct answer(s) Using the convolution sum with a unit step sequence. Integrating the system's transfer function. Applying the initial conditions directly. Summing the impulse responses

[@finkelsteinreaction364]

A AND D

[@sandysandy5866]

great video!!! thanks a lot

[@kirtikansal7388]

please explain the cover-up method in case of repeated roots with squared on the roots

[@athuldas44]

We can differentiate also right the step signal to get the impulse

[@bretthaddin8071]

Thank you sir

[@Guebong]

Wonderful

[@biswajeetsahoo207]

Keep doing sir

[@PunmasterSTP]

Step response of a system? More like "Super great information!" Thanks again for making and sharing all of these really high-quality videos.

[@archanatripathi6616]

you are really dedicated with these comments.

[@PunmasterSTP]

@@archanatripathi6616 Thanks, and I always try to leave a comment on each video to drive up engagement. I think Neso Academy’s content is outstanding, and more people would be able to benefit from it if it reached a wider audience.

[@qozia1370]

so much cringe

[@PunmasterSTP]

@@qozia1370 And I wouldn’t have it any other way 👍

[@qozia1370]

@@PunmasterSTP pathetic

[@GokulGokul-iz2to]

Thank u sir

[@sahilyadav5662]

why we can't find the impulse response by finding the inverse laplace transform of the transfer function H(s)....as in first part you had taken h(t) as impulse response

[@PunmasterSTP]

Yeah I think that might have been conceptually simpler. But since the transform of an impulse is just 1, Y(s) = H(s) in that case and the inverse transforms are the same.

[@alandeutsch7769]

Why didn't you just directly take the inverse laplace of H(s)=s/(s+2) to get del(t) - 2e^-2t ?

[@falgunichaskar3254]

But I read that limits are from minus infinity to t.....pls guide

[@PunmasterSTP]

I think that might be for the bilateral transform, but since most analysis deals only with causal systems, only the unilateral transform is used. Hence we start integrating from t = 0.

[@falgunichaskar3254]

@@PunmasterSTP okay! Thanks

[@PunmasterSTP]

@@falgunichaskar3254 Np! I know I answered your question a long time after you asked it, but I kind of like replying to older comments. I think it drives up engagement on the videos, and it has also led to some cool conversations.

[@biswajeetsahoo207]

Can u create an android playlist pls??

[@eda-un8zr]

Wow

[@anandh1967]

❤

[@kavithaooruchintala1819]

Sir wt about the content writer?

[@PunmasterSTP]

Was Neso Academy looking to hire a content writer?

[@dungaajay6085]

why u r taking .u(t) for impulse and step responses sometimes

[@elackiyasakthivel2002]

u(t) is the input, h(t) is the impulse response and y(t) is the step response

[@lordputinrasiaWale]

@@elackiyasakthivel2002 how h(t) is impulse response?

[@takbotak9088]

As someone who is not from control background, I also have the same confusion. Apparently u(t) is equal to "1" in Laplace table. Adding u(t) there is just for informing that it is a step function equation that we are dealing with. If there is better explanation, please also let me know.

[@jainilpatel7375]

If you see in the first relation of step and impulse response in the video he is saying h(t) as impulse response. You get impulse response when you give impulse signal to the system. Laplace of impulse signal (delta(t)) is 1. Now transfer function is Y(S)/X(S)=H(S) but X(S) would be equal to 1 for impulse response hence you can say Y(S)=H(S) hence your impulse response is equal to H(S).

[@MukeshKumar-uj1hi]

@@jainilpatel7375 Nice Explaination,really useful.