The work done by this channel for the sake of students is beyond perfection.... the amount of hard work being put on by Neso academy is commendable ... Your work transcends all the best created contents ... Keep working hard and keep growing.. Lots of love and respect.. 😊😊❤🔥 🔥
@sukhdevasole18253 жыл бұрын
Sir I see your c programming lecture which I saw the best in yt platform......thanks sir for providing such a beautiful content for free❤️
@jonathancardonagarcia7476Ай бұрын
For part b, I performed the convolution of u(t) and h(t) where u(t) is the step input and h(t) is the time domain transfer function. The convolution of u(t) and h(t) is e^(-2t)*u(t). From here, take the derivative with respect to time on both sides. On the left hand side, use the fundamental theorem of calculus part 1 to figure out that the integral of h(tau) d(tau) from 0 to t is just h(t). Note, u(t-tau) is equal to 1 from 0 to t. u(t-tau) represents the shifted function in the convolution operation. On the right hand side, perform the product rule and realize that the derivative of the step input is the Dirac Delta Function (the impulse function). h(t) turns out to be -2e^(-2t)*u(t)+delta_0(t)*e^(-2t). Taking the Laplace Transform of h(t) gives H(s) which is the Transfer Function of the system. H(s) turns out to be -2/(s+2)+1. Multiplying H(s) by 1 gives Y(s), the impulse response. Taking the Inverse Laplace Transform of Y(s) gives y(t) equals delta_0(t)-2*e^(-2t).
@vishnuchandran2432 жыл бұрын
explained in very simple manner, got the concept very well, thanku sir
@mydearsantosh3 жыл бұрын
Outstanding explanation in short time.
@ushamemoriya53914 ай бұрын
Select all the correct answers. A discrete-time system's response to a step input can be found by: Select 2 correct answer(s) Using the convolution sum with a unit step sequence. Integrating the system's transfer function. Applying the initial conditions directly. Summing the impulse responses
@mohammadkhaliquekhan20413 жыл бұрын
Thanks a lot neso academy please complete control system before gate 2021 it would be so helpful ❤️
@PunmasterSTP2 жыл бұрын
How did the Gate go?
@kirtikansal73883 жыл бұрын
please explain the cover-up method in case of repeated roots with squared on the roots
@athuldas4411 ай бұрын
We can differentiate also right the step signal to get the impulse
@mateoarteaga82747 ай бұрын
You omitted the unit step function because it is equal to 1 from 0 to infinity, but when you integrate unit step function you get area under the curve which is not equal to 1
@alandeutsch77693 ай бұрын
Why didn't you just directly take the inverse laplace of H(s)=s/(s+2) to get del(t) - 2e^-2t ?
@bretthaddin80713 жыл бұрын
Thank you sir
@sahilyadav56623 жыл бұрын
why we can't find the impulse response by finding the inverse laplace transform of the transfer function H(s)....as in first part you had taken h(t) as impulse response
@PunmasterSTP2 жыл бұрын
Yeah I think that might have been conceptually simpler. But since the transform of an impulse is just 1, Y(s) = H(s) in that case and the inverse transforms are the same.
@sandysandy58662 жыл бұрын
great video!!! thanks a lot
@sanskarkumar64842 жыл бұрын
thanks Sir🙏❤
@PunmasterSTP2 жыл бұрын
Step response of a system? More like "Super great information!" Thanks again for making and sharing all of these really high-quality videos.
@archanatripathi66162 жыл бұрын
you are really dedicated with these comments.
@PunmasterSTP2 жыл бұрын
@@archanatripathi6616 Thanks, and I always try to leave a comment on each video to drive up engagement. I think Neso Academy’s content is outstanding, and more people would be able to benefit from it if it reached a wider audience.
@qozia1370 Жыл бұрын
so much cringe
@PunmasterSTP Жыл бұрын
@@qozia1370 And I wouldn’t have it any other way 👍
@qozia1370 Жыл бұрын
@@PunmasterSTP pathetic
@user-sq6xh6jm4z Жыл бұрын
Wonderful
@GokulGokul-iz2to3 жыл бұрын
Thank u sir
@biswajeetsahoo2073 жыл бұрын
Keep doing sir
@falgunichaskar32542 жыл бұрын
But I read that limits are from minus infinity to t.....pls guide
@PunmasterSTP2 жыл бұрын
I think that might be for the bilateral transform, but since most analysis deals only with causal systems, only the unilateral transform is used. Hence we start integrating from t = 0.
@falgunichaskar32542 жыл бұрын
@@PunmasterSTP okay! Thanks
@PunmasterSTP2 жыл бұрын
@@falgunichaskar3254 Np! I know I answered your question a long time after you asked it, but I kind of like replying to older comments. I think it drives up engagement on the videos, and it has also led to some cool conversations.
@biswajeetsahoo2073 жыл бұрын
Can u create an android playlist pls??
@eda-un8zr3 жыл бұрын
Wow
@kavithaooruchintala18193 жыл бұрын
Sir wt about the content writer?
@PunmasterSTP2 жыл бұрын
Was Neso Academy looking to hire a content writer?
@anandh196721 күн бұрын
❤
@dungaajay60853 жыл бұрын
why u r taking .u(t) for impulse and step responses sometimes
@elackiyasakthivel20023 жыл бұрын
u(t) is the input, h(t) is the impulse response and y(t) is the step response
@lordputinrasiaWale3 жыл бұрын
@@elackiyasakthivel2002 how h(t) is impulse response?
@takbotak90882 жыл бұрын
As someone who is not from control background, I also have the same confusion. Apparently u(t) is equal to "1" in Laplace table. Adding u(t) there is just for informing that it is a step function equation that we are dealing with. If there is better explanation, please also let me know.
@jainilpatel73752 жыл бұрын
If you see in the first relation of step and impulse response in the video he is saying h(t) as impulse response. You get impulse response when you give impulse signal to the system. Laplace of impulse signal (delta(t)) is 1. Now transfer function is Y(S)/X(S)=H(S) but X(S) would be equal to 1 for impulse response hence you can say Y(S)=H(S) hence your impulse response is equal to H(S).