Love a self-working trick ,Stephen. This one is cool, and I do like your twist on the end.
@michaelturner4729Ай бұрын
TLDR: There are two independent variables -- the number of cards before the first joker (call it X) and the number of cards between the jokers (call it Y). After the procedure, Spectator 1's card will be Y cards from the top and Spectator 2's card will be (52 - X) cards from the top. In the video, X = 9 and Y = 18, so Spectator 1's card is 18th from the top while Spectator 2's card is (52 - 9) = 43 from the top. Why it works: I will try to show the state of the playing cards from top to bottom... The SETUP: 9 cards Joker43 18 cards Joker18 25 cards LOCATIONS OF THE SPECTATOR'S CARDS: Spectator 1's card is the Nth card after the first joker. Spectator 2's card is the Mth card after the second joker. 9 cards Joker43 N cards (Spectator 1's card is the Nth card) -------------- Spectator 1 cut ------------- 18 - N cards Joker18 M cards (Spectator 2's card is the Mth card) -------------- Spectator 2 cut ------------- 25 - M cards Note in the above, the dashed lines indicate the locations of the spectator cuts. Checking consistency, there are still (N + 18 - N) = 18 cards between the two jokers and there are (M + 25 - M) = 25 cards after the second joker. FIRST REASSEMBLY: As in the video, keep the bottom packet and transpose the positions of the spectator's packets... 18 - N cards Joker18 M cards (Spectator 2's card is the Mth card) 9 cards Joker43 N cards (Spectator 1's card is the Nth card) 25 - M cards JOKER SPLIT: 18 - N cards -------------------------------------------- M cards (Spectator 2's card is the Mth card) 9 cards -------------------------------------------- N cards (Spectator 1's card is the Nth card) 25 - M cards SECOND REASSEMBLY: As in the video, keep the top packet and transpose the positions of the bottom two packets. 18 - N cards N cards (Spectator 1's card is the Nth card) 25 - M cards M cards (Spectator 2's card is the Mth card) 9 cards You are done! Spectator 1's card is (18 - N + N) = 18 cards from the top and Spectator 2's card is 18 + (25 - M + M) = 43 cards from the top.
@michaelrae9599Ай бұрын
I recognized the 18 from the setup, and 52-9=43. I knew there was some switching to get the cards between the jokers. Thanks for getting the HOW of that.
@springbloom5940Ай бұрын
OMG you suk
@georgefeshias9682Ай бұрын
Yh they are the wrong way round
@johnt2594Ай бұрын
This is Simon Aronson’s “Prior Commitment”, based on his “Undo Influence” principle. It can be found in his book “Try the Impossible”. He was an awesome creator.
@UniquetttАй бұрын
Time to re visit and read my copy I am glad so many know what can be found in what books👍👍👍👍
@alanbrownmusicАй бұрын
I'm not sure why Steven rarely credits the authors of these tricks (or even seeks permission in some cases).
@abhisheky7981Ай бұрын
Simon Aranson is a genius. If you can memorize a stack, there are impossible tricks that you can pull of which can absolutely floor people, including magicians!!
@dancmkiii8461Ай бұрын
@@alanbrownmusic I am very disappointed with the lack of crediting.
@MagicMaker-o5hАй бұрын
@@alanbrownmusic It's because he doesn't care, he just want to win money with the views, sad.
@KERRYLindo-c1fАй бұрын
Great i love it
@samwyckoff6216Ай бұрын
Amazing. Great tutorial
@philipnguyen3107Ай бұрын
I❤ your version.⭐⭐⭐👍⭐⭐⭐
@nagaryaАй бұрын
GREAT TRICK!!! I like very much those self working tricks, your explanations are absolutly clear and plesent. Thank you so much for the fun you bring into our lives!!!
@RobertBallMagicianАй бұрын
Wonderful trick, and tutorial. Graham Jolley fooled Penn & Teller several years back with this. 😊👍😊👍😊
@magicdrummer411Ай бұрын
I love this! I feel like using the breather card in Red Hot Mamma makes that trick stronger as well. Gonna play with this for a bit to see what I can get out of it. Thanks for sharing it!
@pasky641Ай бұрын
It's actually a Simon Aronson routine from a book called *Try The Imposible* if i'm not wrong. You can find different routines based on the same principle. Very clever method. Thank to refresh my mind on that trick. It's a good one. Very deceptiv.
@sudarshanrao8169Ай бұрын
Wonderful trick.. killer trick indeed
@Marcia_TomsАй бұрын
A brilliant trick! Please may I ask where you got the lovely green board you place the cards on? Thank you
@UniquetttАй бұрын
I used to have one It was a cut down foldable card table just reduced playing size area and removed legs
@markwillis7105Ай бұрын
Wow mate fantastic trick 👏🏻
@UniquetttАй бұрын
The first prediction I have always set up the second stage is new to me so thank you so much for taking it to a new level👍👍👍👍👍👍👍👍👍
@drhiteshbhatt1179Ай бұрын
Excellent
@MGD313Ай бұрын
Great trick (especially your version). However I'm struggling with the "kicker." Since the magician is the one who generates the numbers 18 and 43, will it feel like a reveal to see them on the jokers? It seems less like a kicker and more like confirmation of two arbitrary numbers that you brought into the trick.
@fendroun3780Ай бұрын
I know what you mean, but when he said the numbers i though "well, they could be calculated depending on what happened until there" as you would do in some tricks with stacked decks. When here turned the jokers I was like "huh, never mind". But I kinda agree, it wouldn't take much away if the numbers where shown before counting in my opinion...
@crashmagicАй бұрын
Agree totally. Love both versions of the trick, but don't think I like the numbers written on the cards 👍
@MartyHirschАй бұрын
Just ask "And do you have any idea how they told me where to look? (pause) Simple!" and turn over the jokers.
@MGD313Ай бұрын
@@MartyHirsch It still feels like a double beat. 1) These jokers made a prediction. 2) These jokers made the same prediction I already told you about.
@LarryDMitchellАй бұрын
NICE self-working trick and my older grandkids will love it. You explained it well and earned yourself a new subscriber. One question...how do you go to your next card trick without ditching the deck or adding the cards that the blue back replaced? Gonna have to do some binging of your channel this weekend. 😁
@superdavenАй бұрын
I guess you’d just have to do tricks that don’t require exactly 52 cards. Remove the odd backed cards and say, maybe if I do this 25 more times I’ll have a complete blue deck.
@brianmendenhall8387Ай бұрын
Im interested.....noce self worker! Sorry if you mention it later in the lesson but can these be done together as a two- phaser?.Or you can pnly do one or thr other because of the setup?
@lilgto64Ай бұрын
I have watched a few of his videos now, if there was an auto/easy reset I think he would have showed that. Once you pull the marker cards out of order it might be a bit difficult to put them back in the right place easily. I'd have to watch it slower or try it - maybe if you left the cards as you count them spread out or in multiple piles maybe you could restack them easily. The problem then is if you do the same trick in from of the same audience they already know that you have specific numbers written on the cards - of course, they would still be surprised in the original trick when the cards they chose are in fact random, however in the second version, with the particular cards already preset by you - it would be less surprising - even if they had no idea how you did it. I have a marked deck but I cannot use it to do tricks on anyone in my family because they originally belonged to my grandpa and everyone knows about them.
@superdavenАй бұрын
If you want to change the numbers (17,44) it’s easy. This works for the second tutorial (color changing selection) may be different for the other version. Idk. 44 is 52 minus the amount of cards you count off prior to placing the first prediction card. In this case it was 8. 52-8=44 17 is one more than the number of cards you count between the prediction cards. So if you want 39, you’d put 13 cards on top (52-13=39). If you wanted 15 you’d count 14 cards between the two prediction cards during setup. Now please understand this will change the spaces between selections and prediction cards. So play with it first. But I think it’s nice to have options. Maybe their age, or sport number.
@carlloud1187Ай бұрын
'Whispering Jokers' by Graham Jolley, it's been around a while.
@themagicbuzz5728Ай бұрын
Very nice Sir thank you❣️♠️♣️♦️
@billysimmons2887Ай бұрын
Really cool trick
@fjrd845Ай бұрын
Hola Steven, me parece un truco espectacular y muy desconcertante para el espectador. ¿Puedes por favor, activar los subtitulos en este video de youtube, para que pueda leer correctamente la explicación del tutorial en español? Muchas gracias por el canal, soy un suscriptor encantado de tu trabajo. Un saludo desde España Steven.
@mikeontheboxАй бұрын
Buscá en KZbin "Fool Us REVELADO // Penn & Teller / Graham Jolley" Hay un video en español que lo explica.
@panayamlijuАй бұрын
R u sure if we ask the spectators to cut, they will get this position? Or for safety, we cut for them?
@Zxhir_10Ай бұрын
As soon as I saw the ending to the first performance I said: hey this is the trick that tricked Penn and Teller! Great stuff mate!
@NathanStevenson-g6zАй бұрын
@@Zxhir_10 I haven't got to the episode where Penn and teller get fooled by this trick so that's exciting
@machwise6984Ай бұрын
But in the beginning of the trick the 6 of diamonds on the left and the 8 of diamonds on the right”I noticed when the cards are revealed the 6 of diamonds come out for the spectator on the left side, and the 8 of diamonds come out on the right. But in the beginning of the trick the 6 of diamonds on the left and the 8 of diamonds on the right
@nicpicot2297Ай бұрын
yes it's Simon's trick with the wispering queens!! not surprised P&T about they are not mathematicians! Latin? IV? MM?
@Jaujau933Ай бұрын
😱😱😱 not another one
@NathanStevenson-g6zАй бұрын
I learnt the first one just a few days ago it's quite mind blowing how it's self working. Your version is ofcourse great but relying on spectators to cut to the right card worries me 😂
@brianmendenhall8387Ай бұрын
Just put a nice breather into them
@magicdazАй бұрын
Mr Aronson was a beast.
@MikaelLummeАй бұрын
Here is how I figured it out. We can think that there are five stacks: S1 = 9, S2 + S3 = 18 and S4 + S5 = 25. We do not know what S2 is, because it depends on how the spectator cuts. The same with S4. As a result of all, the stacks are in the order S3 S2 S5 S4 S1. That’s the solution.
@dancmkiii8461Ай бұрын
If you want to know how it works Steven, you should buy Simon's book.
@Raven-CreationsАй бұрын
This is great, but you don't know if they've cut to the wrong card until it's too late. If the audience members show you which cards they chose, it's a much weaker trick. You would be able to tell from the presence of a breather in the middle of their pack, or two breathers left in the main pack if they've missed the mark, but it's too late by then. Your "out" relies on you knowing that they've chosen the wrong card, but even if you do know, you have no explanation for the card that they did cut to. This places too much reliance on the audience cutting to the forced cards that I think it's a very risky trick unless you have a much stronger out.
@WawrzynPLАй бұрын
This would be more impressive if those 17 and 44 were somehow forced to the spectators and named by them. Otherwise it’s kinda pointless to have it written on the cards.
@superdavenАй бұрын
That would certainly be ideal. I was thinking the exact same thing. Do you have any ideas?
@KenFullmanАй бұрын
I really think having the different coloured cards in there spoils the illusion. Without that you could have your audience just amazed at how you can find random cards in a shuffled deck. Once you introduce the different coloured back it just makes it obvious that it's a stacked deck. Even without knowing the exact details of how it works, your audience will just think. "Oh so he rigged the deck" Not so impressive.
@schlistaАй бұрын
Not a fan of the magician cutting the deck to show the card. It's too obvious. And I'm not sure I can trust the spectator to cut accurately. What would you do if the spectator cuts it wrong?
@superdavenАй бұрын
I believe he address that situation. I’m more concerned if they expose one of the blue backs. That would take a lot away from the trick.
@NathanStevenson-g6zАй бұрын
Joe Diamond says a good magician will take risks. I'm in the same boat what if they don't do this or that and that's true for most tricks. I guess the best tricks have to have some element of possible failure to them