Kinetics of Particles Example in Cartesian Coordinates - Engineering Dynamics

  Рет қаралды 40,519

structurefree

structurefree

Күн бұрын

Пікірлер: 18
@julseu_lol
@julseu_lol Жыл бұрын
2 hours of paid lecture from my professor and all it took is someone from youtube and 30 mins (introduction + this video) of my time to finally understand the concept. You're a lifesaver, man! Thank you.
@SuperJclam
@SuperJclam 8 жыл бұрын
THanks! for explaining step by step! my professor wont explain anything he just derives the formulas :(
@TheLevidance
@TheLevidance 7 жыл бұрын
Exact same here, he spends 500 hours every lecture deriving formulas, and then goes through an example thats literally "Here are our equations, lets sub in some values, cool, thats our answer". If it weren't for structurefree, I'd have failed long ago
@ireneyousif1513
@ireneyousif1513 6 жыл бұрын
Your voice is very soothing. You really help me get over my ex.
@structurefree
@structurefree 6 жыл бұрын
If I could be a material property, I would be the modulus of toughness...💪....I hope you finish your engineering degree and become the baller you were meant to be!
@seabasschukwu6988
@seabasschukwu6988 3 ай бұрын
Kinda lost me where when we tried to prove that acceleration is constant. Around 13:20
@kitho147
@kitho147 9 жыл бұрын
You are truly amazing at presenting those concepts! Big thanks!
@structurefree
@structurefree 8 жыл бұрын
Thanks!
@2ris2
@2ris2 11 жыл бұрын
I didn't understand how you factored out (g) from the step at 11:51. I don't think you can factor out the (g) like that. if you see the previous step g(sin theta) - uk(cos theta) = a, g was multiplied only to the (sin theta) and not the coefficient of kinetic friction. If you leave (g) un-factored you get a value of 2.1526 m/s2 as your acceleration.
@Hanker14
@Hanker14 9 жыл бұрын
shouldnt the X componet Wx be Wx CosTHETA rather than SINE, can someone please tell me why it isnt.
@structurefree
@structurefree 9 жыл бұрын
+Ehioze Hanker i use sine because the 15 deg angle is between the W vector and the y-axis, which is perpendicular to the inclined plane.
@droe1337
@droe1337 11 жыл бұрын
I think its pretty clear... Thanks btw! learning alot
@michaelmolter6180
@michaelmolter6180 7 жыл бұрын
For me, the hardest part of these problems is converting a horizontal angle to a vertical angle (6:34). Every instructor brushes that part off, but that's where I make the most mistakes. Where can I learn more about doing that switch correctly? I just don't see it intuitively.
@DeanOckenden8
@DeanOckenden8 6 жыл бұрын
Move the block down to where the angle is. As in, the block would be sitting on a rotated Cartesian plane. That should show that when say the X plane is rotated, the y plane rotates proportionally. Then slide the block up X plane to its current position and you'll realise no rotation has changed and the rotation is still proportional. Probably a very poor explanation. Something much easier to teach in person. Probably worth asking your professors about it one on one.
@abhishekgiri4694
@abhishekgiri4694 3 жыл бұрын
why did you put Wx = Wsin@ but not (Wcos@) and Wy = Wcos@? Can you explain a bit, please? (@ = theta)
@Ahmedkhalid-su
@Ahmedkhalid-su 3 жыл бұрын
because the 15 deg angle is between the W vector and the y-axis, which is perpendicular to the inclined plane.
@deno141
@deno141 11 жыл бұрын
should have gone to spec savers.
@sribantichakraborty5503
@sribantichakraborty5503 7 жыл бұрын
thanks
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