surface integral, example 2 (KristaKingMath)

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Krista King

Krista King

Күн бұрын

Пікірлер: 73
@saltygoose2943
@saltygoose2943 Жыл бұрын
It’s amazing how each person who teaches this does it a different way.
@tanjents
@tanjents 5 жыл бұрын
You are the best. The video was super clear and concise!!!
@davenrai
@davenrai 7 жыл бұрын
Krista, thank you so much for always posting the same problems from the textbook! It helps so so much.
@kristakingmath
@kristakingmath 7 жыл бұрын
Glad it could help!
@tanakachiwara6530
@tanakachiwara6530 4 жыл бұрын
Which textbook is this?
@Iris-zr1rf
@Iris-zr1rf 8 ай бұрын
@@tanakachiwara6530 Stewart Calculus section 16.7 Question 17
@prasanjitsamantaray5902
@prasanjitsamantaray5902 4 жыл бұрын
I like your voice with very simple and clear explanation 👌
@danika1425
@danika1425 5 жыл бұрын
Nice explanation, thank you :)
@mentorman6285
@mentorman6285 8 жыл бұрын
You've saved me - thank you so much Wish my lecture can see what it really means to lecture Maths
@kristakingmath
@kristakingmath 8 жыл бұрын
+Caiphus Man You're welcome, I'm so glad I could help!
@Neueregel
@Neueregel 10 жыл бұрын
good example of multivariable calculus
@dhimanroy1671
@dhimanroy1671 9 жыл бұрын
You are a very good teacher
@denizozbek9962
@denizozbek9962 10 жыл бұрын
Helped so much! You are very sweet for posting these videos :)
@kristakingmath
@kristakingmath 10 жыл бұрын
I'm so glad it helped!
@AriyanAghamiri
@AriyanAghamiri 2 жыл бұрын
Great as always!
@MyThundermuffin
@MyThundermuffin 8 жыл бұрын
KRISTA ! I LOVE YOU
@wahidhamidy6886
@wahidhamidy6886 7 жыл бұрын
that was so helpful miss! i appreciate your effort!
@kristakingmath
@kristakingmath 7 жыл бұрын
I'm so glad it helped! :D
@moustaphayoussoufissa544
@moustaphayoussoufissa544 4 жыл бұрын
Thanks so much. Isn't for the spherical coordinates we have phi ? You just consider theta and r . I really appreciate if you make this point clear for me?
@vanillapie8321
@vanillapie8321 3 жыл бұрын
same question, what about phi?
@EricPham-ui6bt
@EricPham-ui6bt Жыл бұрын
We may be better off put the z component in the trigonometric form of component x = r cos theta and y = r sine theta then derivative may be found
@pauljohnson3867
@pauljohnson3867 Жыл бұрын
Very lucid explanation
@marcellacella8293
@marcellacella8293 3 жыл бұрын
Clear explanation
@tebokgondou5219
@tebokgondou5219 Ай бұрын
Thank you ❤
@kimmy208
@kimmy208 8 жыл бұрын
thank you for a great video tutorial, it helps a lot, hope you can do more examples :)
@kristakingmath
@kristakingmath 8 жыл бұрын
Thanks!
@joydeepdeb2025
@joydeepdeb2025 3 жыл бұрын
Thank you Maam, Just one question can we do it using Divergence theorem
@vanillapie8321
@vanillapie8321 3 жыл бұрын
what in the limit determines that it is only the positive half sphere instead of the whole sphere?
@victorcamara2155
@victorcamara2155 2 жыл бұрын
You made this understandable but it's still so complicated 😭😭
@lucascorleto2389
@lucascorleto2389 7 жыл бұрын
Hello, I want to ask what exactly are we calculating? its the surface of the function in the enclosure xx + yy + zz = 4 or it is a volume? hope you can clean this doubt for me. very thanks
@nanorbalian6037
@nanorbalian6037 7 жыл бұрын
thank you very much your videos are great ! what if we are calculating for a portion of a sphere in the first octant ? what would the angle be ??
@unfeickmas9960
@unfeickmas9960 3 жыл бұрын
hello, I think It would tetha from 0 to pi/2
@unfeickmas9960
@unfeickmas9960 3 жыл бұрын
It would be
@jimbookiller
@jimbookiller 6 жыл бұрын
I love you. Excellent tutorial
@amararyan4128
@amararyan4128 7 жыл бұрын
Made me understand. Thank you very much ma'am.
@kristakingmath
@kristakingmath 7 жыл бұрын
Glad it could help!
@ashutoshpanigrahy7326
@ashutoshpanigrahy7326 3 жыл бұрын
Thank you so much for the example!
@kristakingmath
@kristakingmath 3 жыл бұрын
You're so welcome, Ashutosh! :)
@taimur1050
@taimur1050 7 жыл бұрын
How would we do the same integral over the whole sphere rather than just the top half?
@kristakingmath
@kristakingmath 7 жыл бұрын
Since the sphere is symmetrical, you could just do the top half like we did, and then double your total in order to get total volume for the whole sphere. Or, you could change the bounds on the integrals.
@AtliTobiasson
@AtliTobiasson 4 жыл бұрын
Cool, but what about the bottom flat surface of the hemisphere?
@kakomamululu8652
@kakomamululu8652 4 жыл бұрын
Say our our surface integral double S, has three components I,J and K. Does this method work seeing that this example only contained I and J??
@neetiverma8988
@neetiverma8988 4 жыл бұрын
ma'am, what if we consider sphere in place of sphere? How will it impact the answer?
@Elliott_Ives
@Elliott_Ives 3 жыл бұрын
What if it is bounded by Z ≥ 1? How does that change the problem?
@bestsetpantakul6065
@bestsetpantakul6065 4 жыл бұрын
If I do it with plane z=1 it would be the same?
@jmmanda1234
@jmmanda1234 8 жыл бұрын
What if you do not want to change your equation to polar coordinates? Can you still stipulate D and solve this surface integral?
@kristakingmath
@kristakingmath 8 жыл бұрын
+jmmanda1234 Yes, you don't always have to change to polar, it's just that sometimes it's easier to change to polar, which is why I did it here.
@meep6188
@meep6188 8 жыл бұрын
i'll stipulate the D for you
@salvationude-natha398
@salvationude-natha398 10 ай бұрын
what coordinates is this? Spherical or cylindrical?
@kristakingmath
@kristakingmath 10 ай бұрын
Spherical 👍
@hollywood1476
@hollywood1476 7 жыл бұрын
Helpful video
@tommywalker1631
@tommywalker1631 Жыл бұрын
so anytime i can any integral funtion and i see the equation for a circle or cynlinder i automatically and ro start thinkig of the limites being 2pi \0 or pi\0
@exploringnaturalbeauty2102
@exploringnaturalbeauty2102 5 жыл бұрын
Thank you mam..love from india
@kiennnguyen1842
@kiennnguyen1842 7 жыл бұрын
Can we use spherical coordinates to evaluate this integral ???
@nikolaiguzman6142
@nikolaiguzman6142 4 жыл бұрын
I have the same question :(
@agpiccolo
@agpiccolo 4 жыл бұрын
Sure. Keep rho=2 and integrate phi from 0 to pi/2 and theta from 0 to two pi. I got the same answer.
@barshapal3229
@barshapal3229 4 жыл бұрын
What if sphere is off centre?
@scottsmith4778
@scottsmith4778 7 жыл бұрын
is this Surface integrals of scalar functions or vector field??
@moipnou
@moipnou 7 жыл бұрын
scalar
@ankeshpatel523
@ankeshpatel523 8 жыл бұрын
awesome
@steventhangcem125
@steventhangcem125 8 жыл бұрын
you are an amazing.
@kristakingmath
@kristakingmath 8 жыл бұрын
I'm glad I can help. :)
@xiii1818
@xiii1818 8 жыл бұрын
Why Zx = -x/z ? It should be: -2x ?
@JKhal
@JKhal 7 жыл бұрын
factored it down 2z = -2x 2's cancel leaving -x/z
@engineerhere1061
@engineerhere1061 4 жыл бұрын
U r awesome thank you so much dear love you
@vivekvarasada2806
@vivekvarasada2806 2 жыл бұрын
F = [5x³, 5y³, 5z³], S: x² + y² + z² = 4 surface integral by gauss thm im getting ans 640 times pi but book says ans is 384 times pi can anybody help me out🥲
@lenapaulsstepbrother2338
@lenapaulsstepbrother2338 3 жыл бұрын
The fucking GOAT.
@pratyushkumarrout9781
@pratyushkumarrout9781 4 жыл бұрын
Sweet voice
@margaretbelanger2537
@margaretbelanger2537 6 жыл бұрын
i love you. i want to make you a cake. thank you haha
@studymode5899
@studymode5899 6 жыл бұрын
Aint it shud be 0 to pie instead of 2pie?
@michaelkindle3391
@michaelkindle3391 5 жыл бұрын
no, remember, you are integrating with respect to the whole upper hemisphere. which is still 360 degrees. you are in R3. Remember, the upper half of the sphere has a trace of a circle, and a circle is from 0 to 2pi. You are thinking in terms of going from x=2 to x=-2 when in fact if you look at the graph, you are going from x=2 to x=2, which per the unit circle, translates to the angle of 0 to 2pi.
@igorfritz2973
@igorfritz2973 3 жыл бұрын
no
@vanillapie8321
@vanillapie8321 3 жыл бұрын
@@michaelkindle3391 what in the limit determines that it is only the positive half sphere instead of the whole sphere?
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