Surface Integrals

[@schrodingerscat3912]

i don't know who spread the word that calc3 was easier than calc2 but no

[@jamesperry4470]

seriously. Calc II like 1/10th the visuospatial skills and critical thinking

[@marybean2231]

I personally loved calc3 way more because I can logic my way through it and it's easy to read. Memorization isn't my thing but I love this!

[@Name-jw4sj]

The concepts in Calc3 are definitely more difficult, however, the computations are harder in Calc2.

[@nitotech]

Both easy if done with enough practice.

[@phantomfaith2001]

@@Name-jw4sj no

[@jonathanrivera5712]

Very organized and consciousness towards different audiences. Color coded, preview, nice! Well done!

[@masoncobb6001]

For anyone wondering about the derivation of the unit normal vector for the sphere: The normal vector for a sphere centered at the origin is always , as this is the vector field that points radially outward from the origin. To derive a unit vector, it is the vector itself divided by its magnitude. The magnitude of the vector is found by taking the square root of x^2 + y^2 + z^2, with the x,y, and z coming from the x,y, and z components of the vector we are finding the magnitude of, which is just . As given in the equation for the sphere, x^2 + y^2 + z^2 =4. Since the magnitude of the vector is the square root of the quantity x^2 + y^2 + z^2, which is equal to 4 by the equation for the sphere, the magnitude is found to be equal to 2. The original vector then just needs to be divided by the magnitude, hence the 1/2 out in front of the for the unit normal vector.

[@ModernTruthRevelation]

GOSH THAT IS AWESOME. PLEASE MAKE THAT EXCELLENT WORK CONTINUE

[@esenniiazov]

change speed to 1.25 Your are welcome!

[@MCSGproject]

try 2

[@KevinS47]

haha funny

[@johannes5000]

amazing video, simply amazing!

[@marybean2231]

Simple and elegant explanations!

[@andreluisal]

Excelllent video!!!! Thanks!

[@jakehealthx]

Very informative! Thank you so much!

[@Gipsy4u]

Great work, very helpful, Thanks

[@nirashrov1071]

Awesome job thanks a lot!!!!!

[@mr6462]

very helpful drawing! thank you!

[@mohammedkhan4990]

Excellent presentation!!!

[@abdelaziz7298]

good movie thanks you very mutch

[@narutouzumakix9201]

awesome video, quite clear

[@cmdrbobert9862]

I'm a bit confused about how you are calculating n hat dot dS. Why ? did you take a derivative some where?

[@Arseniy_Afanasyev]

Bravo! I love this systimatization(regimentation)

[@davidfield5295]

super useful and well organized

[@boletokuchhbhi0003]

the best explanation of surface integrals thank you sir

[@TheArt832]

Very Helpfull.Thanks.

[@ananurlaila255]

When F= (yz + zx + xy ) through an area S which is part of a circle with radius a in the first quadrant of the xy plane. Calculate the flux?

[@7SOON26]

thanks that very helpful

[@andresmena8278]

BEST EXPLANATION EVER OD DOUBLE AND SURFACE INTEGRALS> I LOVE THAT YOU COMPARED BOTH OF THEM TO SHOW THE DIFFERENCE AND SIMILARITIES AS WELL AS GAVE ALL THE POSSIBLE CASE. AMAZING VIDEO!!

[@jameyatesmauriat6116]

I disagree, it's too wordy and confusing

[@user-gt8mb7uw2r]

you solved my problem 👍

[@serialglobetrotter]

r u a robot ?

[@kyrulazwari]

Thanks!

[@thomasdiprima2629]

Surface area of a sphere = 4pir^2 which would be 16pi for this problem. How did he get 32pi?

[@EricPham-ui6bt]

If we use geometric element like square or circle like pixel in computer term on one dimension then intergate on a limited range and domain and error trapping method

[@sureshakella4263]

Nice

[@stephenhopkins5177]

You print, how cute

[@adosar7261]

why ds=dv/dρ and not ds=dv/dθ or ds=dv/dφ?

[@hiw92]

thank you very much

[@SSJPokaLink]

Doubt this will be seen before my final lol, but can anyone help explain how he derives the normal vector in the second example? Since he's using the formula form that converts the vector field into a scalar of two variables, I want to think we need to some rphi X rtheta cross product, but I'm sure I'm just thinking about getting normal vectors wrong.

[@dmannen2362]

Maybe the gradient?

[@akashchaurasia3587]

solve one question by taking surface of ellipsoid.

[@aanandhatamil-4577]

Using Gauss divergence theorem ,the last sum answer is 3×volume of sphere=256π Is it correct or not,anyone guide

[@esraasalamaq]

شكرا

[@kewtomrao]

Not bad! But our sirs explanation is top class n he recommended everyone to check this vid out. He has 22 research papers!

[@jameyatesmauriat6116]

Who's your sir?!

[@thomasanderson4877]

Thank uuuuuu

[@bulldawg4498]

You glossed over too many details in the sphere example. Could use more detail on normal vector determination, too. Overall, very helpful.

[@remygelenidze980]

"There is a flux form which looks like double integral over a surface of some vector fields dotted with the normal vector times the surface element" I don't understand this sentence

[@rmsvideos1335]

Remy Gelenidze the flux form basically shows the flux through the entire area. The double integral is just multiplying the summed dx and dy, so length times width should ring a bell here. And the vector function is just your function f, the normal vector is the direction perpendicular to that area given by dxdy, so you just want to find how much of your vector function is in the direction of the surface dxdy in the direction perpendicular to it (normal vector). Hope this helps

[@sakshishukla5255]

very difficult to understand

[@frankyesjosh587]

Wonderfull lf you have problem for sleeping !

[@attitudegirlfainat7933]

😂😂😂😂😂😂

[@user-kh8lv1wl4w]

ㄹㅇ 설명 개찰지네

[@scimitar95]

When youre doing the unit vector, why dont you divide it by its magnitude?

[@MrHjld]

I don't get this either!

[@keppersjc4018]

because it cancels out

[@cobalt789]

the magnitude of any unit vector is 1.

[@ssctarget7953]

Any body got the answer

[@latzobear]

@@ssctarget7953 magnitude of a unit vector is 1

[@milesdavidsmith]

varibles

[@AnasKhan-eo4xn]

Are you sure you explained double-integrals correctly? As far as I know, double-integrals are integrals of 3-dimensional functions and they give you the volume of the function in some defined region. The way you say it, they don't appear to be any different from single integrals.

[@danielschwegler5220]

No. Double integrals are double integrals

[@chramarajupusapti7428]

dont go speed in subjects

[@mounir9311]

yes

[@bernarddoherty4014]

Holy shit! This guy put me to sleep in exactly 7 minutes. I am gonna play him every night to doze off. Very very monotonic.

[@curiousbit9228]

Wow!

[@JakeMcBain]

wow...very dry..........

[@Ensign_Cthulhu]

The voice sounds synthesised or electronically masked, which I find extremely hard on the ear.

[@relexmind7331]

Please speak slowly i can't hear you properly

[@ente866]

His voice is unbearable

[@fortoday04]

horrible