U3 L4.3 | 3 Bit Asynchronous Counter | MOD-8 counter | Mod 8 Asynchronous counter using T Flip Flop

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Techno Tutorials ( e-Learning)

Techno Tutorials ( e-Learning)

Күн бұрын

Пікірлер: 16
@daishakpatel224
@daishakpatel224 Жыл бұрын
Thank you mam for making this video.
@TechnoTutorials2783
@TechnoTutorials2783 Жыл бұрын
Thanku for watching
@gayathrigayu4741
@gayathrigayu4741 5 ай бұрын
Mam can you explain in video about asynchronous mod8 down counter using jk flip flop.
@TechnoTutorials2783
@TechnoTutorials2783 5 ай бұрын
kzbin.info/www/bejne/r4vOoK2uYsySftE Refer above video all will be same only use JK FF in place of T
@gayathrigayu4741
@gayathrigayu4741 5 ай бұрын
@@TechnoTutorials2783 tq mam 👍
@SerishaAwale
@SerishaAwale 2 ай бұрын
why didnt u use nand gate??? when should we use nand gate???
@TechnoTutorials2783
@TechnoTutorials2783 2 ай бұрын
In this case max count value is 7 and by using 3 binary digit we can represent 0 to 7 If 3 bit counter will count less than 7 like 4 or 5 then we will use nand
@shivamnirmalkar6251
@shivamnirmalkar6251 Жыл бұрын
Thank you Mam
@TechnoTutorials2783
@TechnoTutorials2783 Жыл бұрын
My pleasure dear
@nmn00
@nmn00 3 ай бұрын
Thank you maam
@TechnoTutorials2783
@TechnoTutorials2783 3 ай бұрын
Good luck for exam
@Vaibhavshot
@Vaibhavshot Жыл бұрын
Mam mod 6,7,8 asynchronous counter will same
@TechnoTutorials2783
@TechnoTutorials2783 Жыл бұрын
Yes for 6 and 7 Only input for nand gate will be different In case of mod 8 nand gate not required only 3 flip flop
@Vaibhavshot
@Vaibhavshot Жыл бұрын
@@TechnoTutorials2783 can u please tell the reason for mod 8 asynchronous counter why don't we use nand gate?
@TechnoTutorials2783
@TechnoTutorials2783 Жыл бұрын
@@Vaibhavshot because for mod 8 only 3 flip flop required Mod 8 will count 0 to 7 By 3 flip flop max value is 111 Hence nand gate not required 8 =1000 If u rbusing 4 ff for mod 8 then nand required But we caount using 3 ff
@Vaibhavshot
@Vaibhavshot Жыл бұрын
@@TechnoTutorials2783 ok ma'am thanks 😊
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