The Carnot Cycle Animated | Thermodynamics | (Solved Examples)

[@cerealbowI]

You were the only person who was able to explain this so simply! Took me 2years of studying this just for me to learn everything in a 10min video

[@QuestionSolutions]

I am really happy to hear this video helped you. Thank you for taking the time to write your comment, it was really nice!

[@muhammadhussain356]

YOU ARE THE GOAT BRO I'VE WATCHED YOUR ENTIRE STATICS, DYNAMICS, AND NOW THERMODYNAMICS SERIES AND THEY HAVE BEEN SO INSANELY HELPFUL TO ME I ALWAYS RECOMMEND THESE VIDEOS TO MY FRIENDS. Sorry for the capslock lol but I just needed to express my gratitude to you bro you've literally been the biggest help in my engineering degree!

[@QuestionSolutions]

YOU ARE VERY WELCOME! Honestly, thanks for taking the time to write a comment like this, it makes me really happy to know these videos helped (which is why I made them in the first place.) I wish you the best with your studies, keep up the awesome work and I hope you become a great engineer!

[@olaoluwaogunsola5205]

@@muhammadhussain356 Actually, he was so good with the dynamics and statics too And now thermodynamics

[@SteelRoninTT]

I have my thermodynamics final exam 11 hours form now. This video came in just the right time!

[@QuestionSolutions]

Glad to hear! I wish you the best with your exam, do your best :)

[@dimitriso.5904]

I feel so privileged that i found your channel , when i was taking statics course. Since then i've always come back here for help with dynamics and now thermo as well.Thank you!🎉🙏

[@QuestionSolutions]

I am really happy these videos are helpful to you. Keep up the great work and best wishes with your studies :)

[@nanribetishaya4029]

Much needed 🙏🏽 Better than a 2hr lecture

[@awanrehan6653]

I have thermodynamics exam tomorrow and you just saved me, thank you so much for your help. you are GOAT :)

[@QuestionSolutions]

I'm happy to hear this video was helpful to you :) Good luck on your exam!

[@crystalsgalaxy4987]

this is so underrated, simple explanation, no complexities, love every part of the video! thank you!

[@QuestionSolutions]

Thank you very much, I really appreciate your comment. Glad to hear this was easy to follow :)

[@mariociencia12]

Thank you very much! I finally understood the basics of Carnot cycle!

[@QuestionSolutions]

You're very welcome! I am really happy to hear this helped :)

[@DirkdeZwijger]

He's back!! I've been using your videos again, I will definitely use this video in the near future, as I am restudying thermodynamics

[@QuestionSolutions]

I hope it's helpful to you. Best wishes with thermodynamics.

[@r2k314]

This is best explanation of this cycle I have ever found. It seems so obvious that this is the best way to explain it. Yet it is never done. Thank You.

[@QuestionSolutions]

Thank you very much. That was a really nice comment :)

[@TiếnTạTrầnĐình]

Ive learned the heat transfer and thermodynamics course long time ago, almost forgot about carnot cycle and some basic process until see your video. So amazing, simply and fully

[@QuestionSolutions]

Thank you very much!

[@terrancepage9163]

I have never been as confident in my engineering program as I am after watching your videos. You make me feel like I can solve anything! Thank you very much for your hard work

[@QuestionSolutions]

Well, that's because you CAN solve anything. I am really glad these videos help you out, and I wish you the best with your studies.

[@yigitcan824]

Looking forward to see more videos from you professor,they are so helpful for us!!😊

[@QuestionSolutions]

I am glad to hear that :) Keep up the great work!

[@yigitcan824]

@@QuestionSolutions Hi again I have another question here. Are _heat addition_ and _heat rejection_ *isothermal* in carnot cycle?

[@QuestionSolutions]

Are you asking if the temperature of the reservoirs don't change? If so, then they do not change, it's theoretically maintained to be constant. @@yigitcan824

[@MoNoilnona-nr9rh]

Thank you, you helped me very much, your Content is very helpful and interesting 🤩

[@QuestionSolutions]

I'm glad you found it helpful! 😊

[@engineeryarisowchannel8095]

I haven't watched it yet, I want to watch it after hours, but I already liked and shared it because I know that it is helpful video thank you very much teacher, and I will not get tired of thanking you for the time you dedicate to us and the development of our knowledge and minds, thank you teacher.

[@QuestionSolutions]

Thank you very much, I really appreciate it. Your words made my day! You are a very nice person and I wish you the absolute best in everything you do. :)

[@shreshth691]

Very good explanation 👍

[@QuestionSolutions]

Thank you very much! :)

[@satryoprayogaputra6066]

when 11 minutes much better than an entire lecture for 4 hours

[@QuestionSolutions]

Thank you very much!

[@KiratKaur-b2m]

Seriously this is the real truth bruh.....❤love from India...... Thanks aloottt for such a beautiful lecture.....

[@QuestionSolutions]

@@KiratKaur-b2m You're very welcome! ❤❤

[@pusat17]

bro you are insane how can u good like this editing or posting kinda videos thank you

[@QuestionSolutions]

Thank you very much :)

[@deimonfighter]

Great timing. Thank you for making this video.

[@QuestionSolutions]

You're very welcome!

[@fatimakabir5632]

You saved my life, thank you ❤️

[@QuestionSolutions]

You're very welcome! :)

[@PRS-e2z]

Amazing 🙌🏻

[@QuestionSolutions]

🙌🏻

[@clayelliott3054]

Dude you are so goated thank you

[@QuestionSolutions]

Thank you very much!

[@omkarreddydevarapalli130]

Why is the area under the pv graph not zero as work is done in opposite direction hence the should cancel out right??

[@QuestionSolutions]

Can you give me a timestamp so I know where you're referring to? Thanks!

[@sukhchainsingh1606]

​@@omkarreddydevarapalli130 because work done during isothermal expansion is not equal to work done during isothermal compression due to different temperatures as W = nRTln(V2/V1) , work done at high temperature is greater than work done at lower temperature ,

[@clearflow7925]

Hope you know what you're doing matters a lot. How many videos are there left of the thermodynamics playlist?

[@QuestionSolutions]

Thank you very much. I am not sure how many are left, maybe 3 or 4.

[@JGambrosia]

Hell yeah another video 🎉🎉🎉🎉🎉🎉🎉

[@QuestionSolutions]

:)

[@helloplz8242]

Have you heard of the Karno generator from Hyliion? They are claiming 90-95% heat efficiency paired with a linear generator claiming 50% electrical efficiency. They say they are able to achieve the heat efficiency because of additive manufacturing allowing them to make very complex heat exchangers and parts for flameless oxidation. My question is, is this type of efficiency even possible? Hopefully the Karno piques your interest because I would love to see a video theoretically breaking it down and explaining how it works and if those numbers are even possible. Cheers!

[@QuestionSolutions]

I am not sure, I'd have to look into it. Though what you said did pique my curiosity. Thanks for sharing!

[@anishahossain544]

can you please elaborate in the 1st step you said the gas is allowed to expand , without transfering heat or pulling the piston outside the gas can expand at first

[@QuestionSolutions]

Yes, that's correct. What part would you like me to elaborate? I don't know what else to say 😅

[@nicholasdeg7025]

great video

[@QuestionSolutions]

Thank you very much :)

[@samrm-tn8bt]

Hand up! All 4 procrsses have FORCE to slowly pull and push piston all along the processes, Right? If yes, big thanks to you. I've been stucked here for many years.

[@QuestionSolutions]

Force, yes, but it doesn't have to always be an "external" force. For example, when the gas expands, that creates a force on the piston, but that's not like someone is pulling the piston from the outside, it's done by the gas itself.

[@DaleMcLoughlin-c2z]

Great video :)

[@QuestionSolutions]

Thank you very much :)

[@AmitPola-o1b]

Thankyou sir

[@QuestionSolutions]

You're very welcome!

[@kenichiishirahama215]

For the last example (~ 11:30) I thought it was only for a Carnot engine that the efficiency is a function of the reservoirs temperatures (TL and TH). So shouldn’t the efficiency be 1- (ql/qh)

[@kenichiishirahama215]

Nevermind I tried the other way (equating the efficiency of the Carnot to that of a regular one to give you (qh/ql)=(th/tl) and it’s the same andwer

[@QuestionSolutions]

@@kenichiishirahama215 Awesome. Thank you for actually trying it yourself, rare to see :)

[@Dharani-eo8tb]

Nice 👍

[@QuestionSolutions]

Thanks 👍

[@numankashif6158]

in last question is our heat engine is reversible or not/ because u use efficiency formula of reversible to find TL. or we can use it always anytime for any heat engine

[@QuestionSolutions]

All the problems in this set are about Carnot engines/ reversible engines. You can only use the efficiency formula of reversible engines on just reversible engines.

[@numankashif6158]

@QuestionSolutions sir if the last question is in the paper, how i find out this problem is about carnot or reversible engine.

[@QuestionSolutions]

Most of the time, it will state that it's a reversible engine, or a Carnot engine. If it doesn't, you can compare the efficiencies as shown at 8:30 using the efficiency equation for any heat engine.@@numankashif6158

[@celestinaluna5036]

Sirrrr I have a question. I'm confused. How did you derived on the unit kW in second problem? The answer there is in kW unit. Please answer this huhu ASAP

[@QuestionSolutions]

1 watt = 1 J/s. From there, you should be able to derive kJ/min to kW. Let me know if you are unable and I will help.

[@gorkemeker574]

The king returned to his throne

[@QuestionSolutions]

😅Thanks, you are too kind.

[@NadimGhaddar]

🐐goat

[@QuestionSolutions]

Thank you!

[@mansoorshakeel7939]

ive a final tommorow is there any other upcoming video today regarding this topics

[@QuestionSolutions]

There are other videos coming up, but none before your final if it's tomorrow :( Do your best and I hope you do well!

[@bumxrr]

when its reversed 6:52 it turns out to be a refrigerator right?

[@QuestionSolutions]

Yes, that's right.

[@Prof5680]

I love the way he says reservoir 😂

[@QuestionSolutions]

😅

[@hyperviperjax198]

Just in time for Tuesdays final lol

[@QuestionSolutions]

Best wishes with your final!

[@sebastianjimenez2184]

REAL

[@QuestionSolutions]

😊