DC parallel circuits explained - The basics how parallel circuits work working principle

[@EngineeringMindset]

⚠️ *Found this video super useful?* Buy Paul a coffee to say thanks: ☕ PayPal: www.paypal.me/TheEngineerinMindset

[@cameron-wy4wd]

The Engineering Mindset if I break one bulb in the parallel circuit does the A reading for the other bulb go back to full flow? Or is it still split in half even tho the electrons are no longer flowing through the other circuit. In other words would one bulb get brighter the moment you broke the other or would it stay the same brightness. Probably a dumb question but this is a new found interest of mine thanks to you. You do a great job of explaining now I just need to commit all of these formulas to memory. Thanks a ton for the videos

[@cameron-wy4wd]

0.5A+0.8A=1.2A...

[@superpayaseria]

Are you sure the calculation at 3:24 is correct?

[@DavidMullins1]

@@superpayaseria kzbin.info/www/bejne/a6bce5iwhrOGftk

[@backdubts6776]

@@cameron-wy4wd 11w%

[@PhilEvansOnline]

Correction at 8:12. 0.8 amps + 0.5 amps = 1.3 amps. 😉

[@EngineeringMindset]

You're correct, well spotted.

[@bgregg55]

whoops

[@Charliegray83]

Was shouting at the telly there for a minute

[@vladimirputih]

Wow

[@binaryparrot3352]

lol I instantly paused the vid to search for this comment.

[@whogavehimafork]

I have a degree in mechanical engineering. Was never terribly interested in the electrical side of things because it was harder for me to grasp, so I never paid much mind to my electrical classes. Not to mention I had a very quiet professor from I think the Shandong region of China with a thick accent. She was a perfectly nice and pleasant person but when you can barely hear or understand the lecture in a big lecture hall you become even more disinterested than you already were. Fast forward to today and a large part of my job is troubleshooting and resolving electrical issues in an industrial environment. Finally having hands on experience and excellent one-on-one instruction from my boss (an electrical engineer) has *sparked* an interest in electrical systems and hobby circuitry. So here i am, refreshing myself to fill the gaps in my knowledge. I can wire up a 3-phase motor complete with relays wired into a PLC, but I couldn't remember the basic principles behind current in series vs parallel circuits. And it turns out mechanical systems are quite lovely when you know how to electrically automate them.

[@EngineeringMindset]

See our new video on how to build mechanical versions of electronic circuits? Watch here: kzbin.info/www/bejne/kKecgmqfnZlri8U

[@moonson8804]

Your channel is a gift to humanity. May we cherish it.

[@theavsm16]

you're under his genjutsu

[@TheRambler7480]

As someone who struggles to learn things "just because", I really appreciate your explanation of why we calculate total resistance in a parallel circuit that way. Will definitely help make it stick now I can actually rationalise it. Thank you 👍

[@stevenpersaud5694]

I got a wireman exam coming up nowhere online gives u the refreshing of basic electrical work like you do thank you for these videos god bless you 🙏🏻🙏🏻🙏🏻

[@RLH007]

How'd you do on the exam?

[@the_notoriousdriver]

@@RLH007 he got 0

[@Akachi_]

​@@the_notoriousdriver😅

[@GREEENZO]

Thank you for these videos. A few weeks ago I knew NOTHING and just wanted to learn some basic circuitry for low voltage DIY projects for gardening, automation, etc. You helped me grasp all of this and realize electronics aren’t just “magic”. Thanks again! :)

[@tracymathews4122]

3:05 Your example is 2 Amps, but the meter is showing 3A. This may confuse some. I apologize if I'm not the first to point this out, but with 318 comments, I wasn't going to read through them all.

[@LeviM-oj5qw]

Thank you, I was wondering about that!

[@cnoyes98]

Also worth noting that this example provides a figure for total resistance before the video has explained how this figure is derived, which is a little confusing on first viewing. Excellent series though, thanks!

[@newtonnicholas4836]

I was going through before I comment just to make sure 👍

[@XJapa1n09]

super confused. I'm a frustrated newb and I saw that and nearly threw my computer out the window because I thought I was missing something.

[@SNAKEPIT359]

Up until a few weeks ago my electrical understanding extended to being able to wire a plug. With your series of excellent videos you have expanded my understanding in this area. Thank you very much for sharing your knowledge.

[@robincross4625]

I learned both directions of current flow. After 50 years of working in electronics as a broadcast engineer, I came to the conclusion that theoretical direction of electrons doesn't matter. It only mattered in school. In the field, I have never needed to ascertain which direction. It only matters that they are flowing, by how much, or not.

[@paulanicole-rivera5268]

Answer: 1.) 1.0169 2.) 0.4 A 1.5 A 4 ohms

[@tedlahm5740]

Paul: At 3.22 the amp meter shows 3A. Although the math is correct. This error was put into the graphic to see if we are (paying attention) learning anything.

[@andrewangerer1399]

I came here looking for this. I dont know how he got the numbers for the formula either. I suppose the formula itself is important. I got that the voltage is 36

[@kylehendrickson8527]

@@andrewangerer1399 I got confused at this part too. He does write in the video description this was an error and that the multimeter should read "2A" not "3A" I'm still confused as to why the resistance is 3 ohms

[@EngineeringMindset]

Check our new Multimeter tutorial out ➡️ kzbin.info/www/bejne/ap2kqq2IrdiVesU

[@shembhalangsuiam]

Thank you for this video, And also I've learnt so much from this channel... I've seen the comments about your mistakes in this video... I want to say, We all are imperfect and make lots of mistakes and learn from that.... Ans no.1). The total resistance of the circuit is 1.01 ohm Ans no.2). Current on R2 is 0.4 Amp Current on R3 is 1.5 Amp Resistance on R3 is 4 Ohm

[@iam.tariro]

How can someone possibly dislike this video?? Thank you for such a well detailed video. I have exams in 2 months

[@KingHarry1]

8:05 total current is 1.3A 😊 Resistor 1 and resistor 2 is the sum of 0.8A + 0.5A = 1.3A

[@EngineeringMindset]

Check out NEW resistor video, everything covered! ➡️ kzbin.info/www/bejne/eorGfXl-nLt2pJI

[@SkyAssassin9]

studying for a med entrance exam after several years of not studying physics. Your videos have been the most helpful so far for electricity. Thank you so much, I'm very grateful !

[@linkdude600]

How did it go?

[@ryanschwan2507]

​@@linkdude600yeah

[@alichoudhary9156]

I just realized my love for this channel

[@UnboxWithUmer]

Question 1: Rt = 1.020 Ohm Question 2: I2 = 0.4A I3 = 1.5 A R3 = 4 Ohm

[@buddablackmusic]

I got 1.017 Ohm (60/59), it could be rounded to 1.02, but the extra zero after the 2 I believe is a precision error. I may be wrong tho

[@tomasgarza1249]

@@buddablackmusic Calculate the total resistance first, then use that total resistance to check if your values are correct

[@pierrot8358]

Great video but at 8:10, total Current of 0.8+0.5=1.3A! Not 1.2! ;-)

[@EngineeringMindset]

You're correct, well spotted.

[@amidfallen]

god, I love the way you explain things... sometimes I watch videos from different sources and got more confused than before the watch. It is apparent that you put the work into explaining things in the clearest way possible. Thanks :)

[@manzarazam8661]

Excellent. I wish I ve the gold medal to gift u......

[@johnallums3134]

Lmao i just spent 20 minutes trying to quantify how 0.8 + 0.5 = 1.2 amps.... then i looked at the comments. 🙃

[@ryanfinlay7791]

I also spent too much time questioning my sanity

[@kevish2109]

😂​@@ryanfinlay7791 same

[@newtonnicholas4836]

lol same with me 😂😂😂😂

[@tedlahm5740]

KCL Kirchhoff's current law. Wonderful explanation. Paul: A little too fast on the excellent graphic and voice over. Perhaps trying to squeeze everything into the 16 minutes.

[@ChinhLe-jm1mf]

Bro... i used to learn electrical engineering... my instruct sucks.. I quit because it was so boring.. im enjoying your teaching instead... I've learned something for sure!

[@timothyburge4081]

youve done more to teach me than my teachers have

[@andrewahlstrom-c9b]

thanks for describing the theory behind that equation. taking the reciprocal of the sum of conductance is much easier to remember than a random equation. Loving the videos so far. They're explained so well that I'm wondering why I struggled so much before.

[@johnx9318]

That BUT, at 12:02 was the missing link in my understanding of electricity understanding. Brilliant, thank you!

[@icedclips725]

Never knew about electronics but this series has sparked my interest.

[@GabrielSantos-tb2zo]

I'm running for an opportunity in my job as a process technician and I came here to review. I understood better in English than in my native language (Portuguese) hahaha thanks a lot !

[@Artem992]

wow, the explanation for parallel resistance and all of the divisions NOW totally makes sense! thx !!! and here's my 5 cents: a good (and quite extreme) example would be to make a short circuit in parallel, thus (despite the other resistors) the current would flow via the easiest path. It's easier to see it as "leakage". the smaller the resistance - the bigger the hole is. therefore, the more "joints" = the more holes you have with current leaking through. therefore, in parallel setup - the total resistance would ALWAYS be smaller, than the weakest part. 12:20

[@zarpedon3541]

THANK YOU! YOU FREAKING SAVED ME

[@enriquegrageda]

for anyone wondering how he got 3 ohms for total parallel resistance at 3:05.... (use this formula.. this works for exactly with 2 resistors) Rt=(R1∗R2)/(R1+R2) R1 = 6 ohms R2 = 6 ohms (easy math, subsitute and solve!) Rt=(6 ohms * 6 ohms)/(6 ohms+6 ohms) Rt=36 ohms/12 ohms Rt= 3 ohms formual for more than 2 resistors is... Rt = 1/(1/R1 + 1/R2 + 1/R3 + etc....) 😸

[@gurpreetarora6036]

Hi bro I have been watching this video again and again but I am unable to solve my problem if you can help me

[@charlesporsbjer2416]

Thank you for explaining where the ones come from! Things like that help me out immensely!

[@srivenkateswara371]

i) Total resistance Rt=1.020ohms ii) current through 15 ohms is 0.4 Ampere and R3 is 30 ohms and current through 30 ohms is 0.2 ohm .Thank you so much sir for giving excellent information and excellence explanation

[@AverageTPSenjoyer]

No the R3 current is 1,5 amps and the R3 ressistance is 3 ohm, to get the current of R3 you just need to: I(3) = I(t) - [I(1)+I(2)] I(3) = 2,5A-[0,6A+0,4A] I(3) =2,5A-1A I(3) =1,5A For R3 ressistance you just use ohms law, which states that ressistance is Voltage divided by current, in this case the current we use to get the R3 ressistance is the R3 current, so: R3=V÷I(3) R3=6V÷1,5A R3=3 ohm Hope it helps

[@trapiz9356]

@@AverageTPSenjoyer Your way of calcylating is right, but 6V / 1.5A equals 4Ω, not 3Ω,

[@AverageTPSenjoyer]

@@trapiz9356 Thanks for pointing it out, I think the rest is right

[@dennisshaw5013]

This is the best video I have seen on electricity, Thanks, Paul.

[@azy3929]

All my questions about WHY that i found no answer are solved in your channel. Visual examples + WHY explanations are top quality content, you make people learn for real

[@EngineeringMindset]

Glad to help!

[@CaptM44]

I’d love to see your take on Kirchhoffs laws, and nodal analysis.

[@EngineeringMindset]

I'll add them to the list

[@anshulpowersmart4729]

Thank You so much, this helps for my exams and general understanding a lot

[@stiffler2k246]

Applied to my local college the other day to get on their electricians course, i hope you're still gunna be uploading for the next few years aha

[@EngineeringMindset]

Best of luck! yes, hopefully so

[@amongabor]

So, how is your electricians course going?

[@lightwishatnight]

Lovely animations, and I liked that there was a mistake in the calculations, made me feel more confident, and know how to stick to my guns.

[@md.tanviryusuf]

0.8Amp+0.5Amps=1.3Amps. You are welcome. BTW Your videos are best to the point videos on KZbin.

[@edwardscomputers]

Thanks!

[@edwardscomputers]

is this enough for a coffee?

[@EngineeringMindset]

I can definitely buy coffee with this, thank you again Corey

[@hezdraws1379]

I do not understand the example on 3:23. The illustration circuit shows that current is 3A and resistance is 6 Ohms per resistor how is it that when calculating voltage you are using values that are not in the illustrated circuit?

[@TheGamecheater100]

man, you explain this things alot better than how they were explaining me in school, its alot easier to understand electricity with these video, you re doing a great job

[@anthonyantoine9232]

Just to be a little extra difficult on question 2, you can also sort of work backward and find R3 first using the known amperage after the first branch (1.9A) to figure out the total resistance of the remaining circuit (3.158 ohms) and then using the given 15 ohm resistor to find R3. Then when you have the resistance, you can find the amperage for the third branch and then the remaining amperage which would go through the second branch (or vice versa finding amperage for branch 2 first).

[@Juan-rb1ni]

for parallel resistor, 11:50 this is the most important concept i need, i don't like people to just throw the formula without explain it where it come form or how the formula work that way...

[@ninjapanda1018]

3:15 I’m not quite understanding where you’re getting 2A and 3 ohms from. But if I base this off the diagram Voltage = Current x Resistance Which means base on the numbers in the diagram, the voltage should be 18V 18V = 3A x 6 ohms If I’m wrong about that then the only other answer I can think of is 36V = 3A x 12 ohms

[@bjdent]

your videos have changed my life. all kinds of projects and homowner diy cost savings are attributed to these videos. also, per my research @7:29 connecting batteries in series does not increase amps, but volts instead.

[@TheGiantHog]

I'm kinda of confused at 3:10. The diagram says 3A but the problem says 2A. The resistors are both 6 Ohms but resistance in only 3?

[@EngineeringMindset]

Well spotted. It should read 2A on the multimeter.

[@TheGiantHog]

The Engineering Mindset What about total resistance? Why is it 3 ohms? Is it due to the resistors in parallel? Like 3ohms = 1/((1/6ohms) +(1/6ohms))

[@EngineeringMindset]

Check our new Multimeter tutorial out ➡️ kzbin.info/www/bejne/ap2kqq2IrdiVesU

[@EngineeringMindset]

Check out NEW resistor video, everything covered! ➡️ kzbin.info/www/bejne/eorGfXl-nLt2pJI

[@kravatapraimuu]

Your videos are helping me get an intuition for electricity and electronics and I really needed this since I started a job in embedded development and I really wanted to be able to understand the PCB designs and why certain things are done the way they are. Amazing content, I have subscribed and am binging like crazy!

[@sindhujachinnam516]

I really found this video very helpful. I have been through so many videos but this really helps to know much more easier for Series connection and Parallel Connection, and their advantages and disadvantages. I have fixed spots lights in series connection and the first light is very bright and the rest are dull and flickering. Then I have been through this video and connected spot lights in parallel connection. Now it's really cool. I must really thank you, you made my day easy. All the best :)

[@awesomerpyt6594]

Hey, at 3:42 if you knew only voltage (12V) you determine resistance by looking at the lamps description and the calculating the current right?

[@zoolmakesmusic]

Thanks

[@EngineeringMindset]

Thank you, Zool!

[@tedlahm5740]

Wonderful explanation of total resistance of parallel resistors.

[@EngineeringMindset]

Check out NEW resistor video, everything covered! ➡️ kzbin.info/www/bejne/eorGfXl-nLt2pJI

[@avinashs7284]

SIR THANK U VERY MUCH FOR GIVING ME THESE ELECTRICAL VEDIOS.. Iam a mechanical engineering student but Very weak in electrical engineering.. Now I'm using ur channel to improve my knowledge and its awesome.. Ur teaching is just extraordinary with beautiful animations and examples for beginners. Thank u very much sir

[@mohdishaq9250]

Beautiful explaination for Basics

[@MayaDevi-pk9bu]

1)0.90 OHM 2)R2=0.4A R31.5 A and 4 ohm

[@Samara200M]

We need to add resistance for filter DC voltage

[@blackbeardpapa9547]

awesome. Just awesome. You should make an online course for electronics. I would buy it. Also...the soldering kit on amazon is not available. Recommend another

[@Nomenius1]

Holy crap, that conductance bit made it make so much more sense. Thanks a lot.

[@_itstmanh]

thank you for doing this video. It's help me a lot in my final exam lol!

[@SpreadtheWord.podcast]

Thank you so much sir. This video helped me a lot. God bless you 🙏

[@aaradhyabharadwaj255]

What an amazing explanation of the parallel circuit. Wish someone would have taught like this in school. Great job

[@HaloWolf102]

I have a question. At 5:35 a battery at 1.5 V, and a total resistance of 2, equals 3.0A. At 6:12 a battery at 1.5 V, and a total resistance of 3, equals 2.25A. At 7:07 a battery at 1.5 V, and a total resistance of 3, equals 4.5A. At 7:07, you have the same setup(a total resistance of 3), but this time it equals 4.5A, instead of 2.25A. How can a total resistance of 3, with 2 different circuits, equal different Amperage? I see the equations, and I understand the math, but you can't tell me that the numbers stay the same(total resistance, and total voltage), but then you add a lightbulb, and it magically increases the amperage.

[@zykli1332]

OK, after some more research I found a more intuitive answer… Imagine the following We start with a simple circuit (no branch) and a resistance of 1Ohm and 1.5V. Clearly the total current should be: 1.5V/1 Ohm = 1.5A. Now we add a new branch (lightbulb with 1 Ohm). Instead adding the Ohms, calculate the same way as in the first case (only one branch). As every branch gets the same voltage (as there are consumers before the bulb, the „full“ volt is present on each branch). So „before“ ach lightbulb we have 1.5V and 1 Ohm, thus I = U / R = 1.5 V / 1 Ohm = 1.5A „before/after“ each lightbulb. As every branch has/needs 1.5A, we have a total of 3A. If we would add another branch (3 branches with lightbulb with 1 Ohm) this one would also „need“ 1.5A, resulting in 4.5A in total. No matter how many branches/lightbulbs we add, the voltage on each branch is the same, so is the amps. I like to think about ampere as workers who transport the energy (actually ampere are a bulk of electrons, so maybe not that false?). If we add more branches we need more workers, as the total number of workers have to be split across all branches. The total resistance can be calculated with R = U / I and as every branch adds more ampere the total resistance decreases. Maybe one can think of this as the „effectivity“… If we imagine we have only one branch with 2 Ohms we get some numbers, 100% current „flows“ through this branch. If we add another branch with 1 Ohm, some current of that previously 100% will flow through this branch… The percentage will follow the distribution of the resistances, in this case 33% in the 2 Ohm branch, 66% in the 1 Ohm branch. So the „effectivity“ of the 2 Ohms is only 33%, thus the total resistance decreases (compared to only one branch). But how do we get these numbers 33% and 66%? Let’s make it more complicated to see, if it works with also with „not synthetic“ numbers: 15 Ohm, 50 Ohm, 150 Ohm (3 branches). A first idea could be: add everything to 165 Ohm and then 100/165 = ~0.6 (~60%), 50/165 = ~0,3(~30%) and 10/165 = ~0.06(~6%) (should add up to 100%). No matter what these numbers are a bit misleading as 100 Ohm should lead to far fewer current than 15 Ohm… Thus this cannot be right. So if 100 Ohm leads to less current than 15 Ohm, the percentage of 15 Ohm must be higher than the percentage of 100 Ohm. Lets try 1/100Ohm = 0,01, 1/50 Ohm = 0,02, 1/15 Ohm = 0,066 (from Ohms law with 1 volts). It s seems they already add up to 1 (or 100%) but they don’t (imagine we would remove the 15 Ohms, we would get the same numbers but would definitely not add to 1). Instead we calculate the percentage of these numbers… add them up (1/100 + 1/50 + 1/15) and calculate the percentage if 1/100, 1/50 and 1/15 relative to the sum: (1/15) / (1/100 + 1/50 + 1/15) = 0.6896551724 -> ~68% (1/50) / (1/100 + 1/50 + 1/15) = 0,2068965517 -> ~20% (1/100) / (1/100 + 1/50 + 1/15) = 0,1034482759 -> ~10% these will definitely add up to 1 Now we have the percentages of how much current will flow through each branch (depending on the relative resistance). A small test: we pick 225V, which gives us 225/100+225/50+225/15 = 21,75 Amps in total (each brach would be 225V/100 Ohm = 2,25A, 225/50 = 4,5A and 225/15 = 15A). Actually we can achieve the same thing with our percentages (if we somehow knew the total amps)… 21.75 * 0.6896551724 = 14.9999999997 A 21.75 * 0,2068965517 = 4,4999999995 A 21.75 * 0,1034482759 = 2,2500000008 A The percentages seem to work and give us the „amount“ of current „flowing“ through. We can see that we have 100 Ohms but they are only „applied“ to 10% of the current which is why it is less „effective“. Thus, the total resistance gets lower because the resistance is „applied“ to less current. This thinking only works for a fixed number of branches (or a fixed number of amps)… As you can see the amps increase if more branches are added… then we need workers/amps as we have more branches. Again, I’m not a noob but this way it makes a bit more sense and maybe this helps somehow ;) OLD: I’m a complete noob but according to 11:40 the total resistance is calculated differently in parallel circuits. For 1. 6:12 I get a total resistance of 1/( 1/2 + 1/1 ) = 0.6666666667 Ohm For 2. 7:07 I get 1/( 1/1 + 1/1 + 1/1 ) = 0.3333333333 Ohm If we plug this in I = U / R for 1. I = 1.5V / 0.6666666667 Ohm = 2.25A and for 2. I = 1.5V / 0.3333333333 Ohm = 4.5A It seems counterintuitive but I guess this is how current works?

[@mattw5840]

WOAHHHHH!!! YOU JUST HELPED ME UNDERSTAND JUMPING CAR BATTERIES

[@mattw5840]

NEVER MIND I'M STILL CONFUSED, BUT LESS SO

[@mattw5840]

NOPE I GOT IT, THE DEAD BATTERY SUCKS JUICE LIKE A SLURPY STRAW

[@mattw5840]

I GOT CONFUSED CUS BOTH BATTERIES CONNECT THE POSITIVE TOGETHER

[@mattw5840]

BAD NEWS BOSS, THE REST OF THIS VIDEO REALLY LOST ME, I'LL REWATTCH IT LATER WHEN I'VE HAD MORE COFFEE

[@octavylon9008]

7:12 why adding another branch increase total voltage ?

[@Squash101]

small tip to understand 5:40 a bit better calculate the individual currents FIRST

[@stanislawstachowski8330]

13:43 There exists one more (third) formula to calculate power consumption: I^2 x R. I don't know why is it skipped in the video. Beside that, very good video!

[@yegorborovkov]

It's skipped probably because it's a combination of 2 formulas V^2*R and V=RI, but im not sure

[@fakrulislam5404]

the video is very helpful for me. thank you very much.

[@indiapunjab1259]

Your every video is a masterpiece.

[@bluex217]

5:40 when you connect a 2nd 1 ohm lamp, the current increases to 3 amps. Why? We just said current = voltage / ohms. 1.5 volts / 2 ohms total = 0.75, not 3. Is it because current splits in parallel circuits and so each lamp is receiving 1.5 amps which *2 totals 3?

[@Raikura]

I gotta ask, do you know any Canadians? This is literally the next module (the one we're doing tomorrow!) in my electrical course. I've watched a lot of your previous videos but I find it funny on the timing for this. Anyway, I shot you $10/CAD on Paypal so hopefully that's enough to buy yourself a coffee. Thanks for making this series! I'm a very visual learner & I haven't found any electrical series on KZbin that can hold a candle to yours!

[@EngineeringMindset]

Thanks for your support, Brian. Really much appreciated. Very glad to be helping your studies and great to hear you enjoy the topics.

[@deepakbisht7839]

4:50 sir you said in your previous lecture that voltage are responsible for speed of electrons if we provide more voltage the speed of electrons increase but here you said is that electron speed is remain same after the voltage of 9voltage

[@EngineeringMindset]

The speed remains the same, the amount of electrons changes

[@AdamyaAdmi]

(at: 7.16 minute)does battery series increase current (double up voltage also double up current ) when it connected to a parallel circuit ?

[@1905AdamH]

At 3:06 the diagram does not seem to correspond to the explanation. Presume it's an error.

[@skkeldon8769]

Thank u bro my brain is fully advance now 💯👍❤️

[@sharangmorye7753]

Excellent content!

[@jcwick0859]

how is the total resistance 3 ohms if they eatch have a 6 ohm resistor at 3:10 ... wouldnt it be 12ohms? im confused

[@EngineeringMindset]

Check out NEW resistor video, everything covered! ➡️ kzbin.info/www/bejne/eorGfXl-nLt2pJI

[@MTECHINDUSTRIES]

Im in love with this channel ❤️ 🌩 ⚡️

[@olegchernov8784]

Thank you so much! How can I calculate the maximum power of a resistor? I have desoldered a lot of old circuits, but there are no inscriptions on them except of color stripes indicating resistance. Knowing the resistance, is it possible to somehow calculate the maximum power?

[@EngineeringMindset]

See our resistors explained video

[@placidoabatista549]

It had help me tremendously, Thanks

[@danielmarquez2485]

gracias mi rey se me aclararon varias dudas de el como funciona la electricidad, incluso sobre la importancia de los circuitos en serie (en mi carrera no los entendí, ni mucho menos su importancia y aplicación)

[@quicknaturalbeauty]

Best engineering learning site, with well explained topics and proper diagrams . 💯 Glad to find the channel👮🏻‍♂️

[@siriany]

at 3:21 you said there's 2 A of total current but the manometer show 3 A at 8:12 0.8 amps + 0.5 amps = 1.3 amps

[@alexismitchell7932]

So helpful. I have a whole bunch of tests coming up and this is saving my grades. Thank you :D

[@BLACKHOLE3421]

Q1 ___ 1.167ohm Q2____R2 .4 amp Q3--------R3 1.5 amp Q4-------4ohm

[@user-sz7mq5hx9f]

At 3:12 why issit said that the current is 2 A and the total resistance is 3 ohms when the multimeter states that it’s 3A and each of the resistor is 6ohms?

[@EngineeringMindset]

See video description for correction

[@Xematix]

At 7:00 Why do we not measure/place the multimeter after the merge of the 3 branches to measure the total current? Does the Batteries not just release another round of 1,5A of Current at the start before splitting? Can someone explain this to me?

[@EngineeringMindset]

Check our new Multimeter tutorial out ➡️ kzbin.info/www/bejne/ap2kqq2IrdiVesU

[@syndicatee8115]

At 5:39, how does the total amps get increased to 3 Amps? I thought amps were calculated with volts divided by ohms, wouldn't the total amps be 1.5V / 2 Ohms = 0.75 Amps?

[@syndicatee8115]

Nevermind, I think I figured it out, you calculate the voltage based on the ohms in each branch and then add them, not just total voltage divided by total ohms of the entire circuit. Edit; played the video a bit more and literally answered my question a few seconds later.

[@gokerbg]

I am an amateur, I can answer as much as I learn from your lesson. Answer 1 - 1.02 Ohm... Answer 2 - R1: 10 Ohm and 0.6 A ; R2: 15 Ohm and 0.4 A ; R3: 4 Ohm and 1.5 A. Correct?......

[@brunojani7968]

Correct

[@gokerbg]

@@brunojani7968 Thank you.

[@mithudas7924]

This explanation was best

[@danielteyehuago1633]

Thanks for sharing it with us

[@MarcusT86]

Great video and I fully understand the explanation. But what I can't get my head around is how in domestic lighting and plug socket circuits, the voltage supply is 230v (UK) so why is it not blowing light bulbs up when from what I've seen all that's resisting the flow is a mere 10 ohms per bulb. Could you do a video on typical measurements, figures, resistances, etc. in domestic circuits please?

[@ModernGunCraft]

The bulb assembly should have resistors in it. And the resistors built into the socket as well limit the {Current}. I think I have that right.

[@EngineeringMindset]

Check out NEW resistor video, everything covered! ➡️ kzbin.info/www/bejne/eorGfXl-nLt2pJI

[@chance2223]

At 3:11 how is the resistance 3ohm when you have 2 6ohm resistors

[@EngineeringMindset]

Check out NEW resistor video, everything covered! ➡️ kzbin.info/www/bejne/eorGfXl-nLt2pJI

[@TURNKEYiNK]

Great video, thanks. But. I don’t understand how placing two 1.5v batteries in series works (how does it double). If I no current flow can occur from the negative terminal to the positive terminal, then how does connecting the positive terminal to the negative terminal of a different battery work? ...shouldn’t the electron difference between the touching terminals balance out immediately (like shorting a single battery with just a piece of wire)?

[@EngineeringMindset]

Check this out, how a battery works: kzbin.info/www/bejne/homxfJ6Zd5Wjf5Y

[@xiaogangdasha]

How about we change one of the resistor to inductor, in the inductor video, you said current don't go through inductor first but later all go though it, seems outside law of parallel circuits. 🤔

[@VolcanoGamingVR]

When you asked what the voltage is with multiple batteries, I got 18V since you said current 3A (according to the multimeter) * 6 ohms, l for 18 so I am very confused. Can you explain

[@iperpituallocomotionz7751]

Can a regular two 1.5V batteries supply 9.0A? and for how much time? 7:25

[@ImFlash6]

Paul is an absolutely fking Chad he explained the whole lesson is a few minutes better than my physics teacher could ever in his life

[@李大宝-l5m]

Thank you for the video! I have benefited a lot！