Mesh Current Problems - Electronics & Circuit Analysis

[@TheOrganicChemistryTutor]

Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections

[@arsdwalos6840]

this guy is two videos shy of teaching how to build a rocket. he knows everything about science. respect.

[@prabus3562]

Well said...

[@RichOffClip]

@Devadut S Balan u take things way to literal😬

[@Jeffman529]

@@jorgelevario3478 who asked

[@triparadox.c]

@@Jeffman529 who asked

[@xlmrami2729]

@@triparadox.c who asked

[@camielkotte]

Your vids make me wiser most of the time.... If they don't.... They make me sleep real good. I value both out comes!!!!

[@alejandrogutierrez7268]

I understood mesh analysis more in 30 minutes from your explanation than I did from my 2 hour lecture. Thank you!

[@coolmonkey619]

Indian lecturer?

[@Happydayz-2025]

I totally agree. My professor is sooo bad!!!

[@luwinoah2500]

Very true

[@dharunkumar8461]

@@coolmonkey619 yes dude

[@ma.kriseldadolor2603]

facts.

[@ruchir5325]

This guy helped me get through middle school and high school . Now I am in college and I still depend on his videos to make it through.thanx mate keep up the good work!

[@corey1064]

he is so clear when teaching we can all understand when he corrects himself

[@0.Abdulrahmannn]

As an electrical engineer in college, I must say I am impressed with your way of explanation. good job.

[@jangmoses911]

I also want to be an electrical engineer. Do you have any tips?

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​​@@jangmoses911 just keep (solving)⁴ math problems and your dreams come true.

[@0.Abdulrahmannn]

Just try to get into collage. It helps you know what you need to get the degree. Finally and most importantly you've got to love it.

[@jeffspaulding9834]

This kind of video is great for people like me who just do electronics for fun. I've got a career and no interest in becoming an EE, so I can't justify going back to school for this stuff, but I can justify spending a bit of free time on my hobby. Thanks!

[@juanshaftpatel7488]

RREF on your ti 84

[@chloegrubb6721]

Thank you for everything. You literally save my grades in every class.

[@Harumy0810]

Thank you for this video! I've been confused with my teacher's method because when I change the direction of the loop, it no longer works but this still works whatever the direction of the loop was. Again, Thank you!!

[@سبحاناللهوبحمدهسبحاناللهال-ن5ض]

I was confused as well but the answer is actually correct because there are two ways to solve this. 1) (His way) to keep the polarities constant in each loop while using the previous current calculation. 2) (another way) To change the polarities according to the current flow direction and input the new difference in current by giving priority to the current that is in that certain loop. Both ways result in the same answers.

[@DaSoggyTurd]

[@gopinath9986]

you helped me when in school now in college thank you

[@ipodtouch470]

College ain't school or what?

[@ahmadgamd9215]

@@ipodtouch470 In some countries school ends with high school and any higher level of education is called collage, for example my home country Egypt.

[@VyshnaviSkate-qu9yv]

Thank you so much..... Tomorrow is my test...... I didn't understand a single thing explained by my professor who explained for three hours.... And now I understand this is jus thirty mins

[@sanelekhalala8234]

My real teacher....thank you brother keep up with the excellent work sir

[@md_nawshin_zaman]

Understood from a 27 min video that I couldn't done from a 3 week class 😅 Salute to this guy

[@obioramichael7315]

This guy spits so many facts at a time. I'm so grateful having found your channel. I really do appreciate ✊🏿

[@onwabankosana6787]

totally sastisfied i am always watching your videos for all my modules youre my first option

[@RishiVaish-ym1nr]

Thank you so much, sir. You've explained the imp details which my lecturer missed to do...

[@mechanicalkiller1061]

Friday 26 March, 2021 - 9:22 p.m. - I have a HW in EE 204 ( 2 Hours to the Dead line ) Thanks very much LUAI

[@dayannvvvf6600]

At this rate, i just should have paid you instead of my university tuition fee😌

[@batuhan34443]

kzbin.info/www/bejne/nZnVcqSwjrB8ppI if you solve more question harder one i really recommend this question.

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@@batuhan34443 aynen kanka adam burayı bırakıp senin türkçe kanalı izlemeye gelcek.

[@BiggerPunch]

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[@tebogothema1405]

Explained it better than my lecture..... your methods are easily understood...Thanks

[@ngk5239]

thank you Sir! youre helping a lot of people! ur vids are much easy to understand compare to others! God bless!

[@ntombizakhexego-jimlongo8577]

I always get clarity in your videos. Thank you, Sir. Highly appreciated

[@westcountrybob2521]

You say use Vb for the voltage across the battery but on your circuit diagram Vb is designated to the node where R1, R2 and R3 connect.

[@mrkris04]

I spent 2-3 hours on these type of questions finally someone was there to help me out thanks a lot

[@devvrath123]

Thank you! I've finally understood Kirchhoff's laws and mesh current analysis after watching this video

[@jonaslitosandersson]

Thank you! I had problems understanding this and now I feel I got it. Watched a bunch of videos on the same subject, but this is the one that made me understand.

[@olokungboyegabriel4292]

God bless you sir. You just saved my test 🙏 ❤

[@kurthayes2743]

At 14:00, why does he put 8(i1 - i2) instead of 8(i2 - i1) when i2 flows through the positive of the resistor so shouldn't i2 be positive and i1 be negative?

[@shivanshutripathi460]

Beacuse he was working According loop 1...

[@Gbajumodigitals]

8(i2-i1) is correct. I guess he missed that side

[@سبحاناللهوبحمدهسبحاناللهال-ن5ض]

I was confused as well but the answer is actually correct because there are two ways to solve this. 1) (His way) to keep the polarities constant in each loop while using the previous current calculation. 2) (another way) To change the polarities according to the current flow direction and input the new difference in current by giving priority to the current that is in that certain loop. Both ways result in the same answers.

[@androwlaurenmodric1563]

thanks man you just saved my semester in Electrotechnics 😉😉 you are the best

[@alabatchi1]

I always wonder what your major is? You actually know everything in math , chemistry, physics , electric engineering, mechanical engineering, and etc .

[@hutfiftyfive1]

you don't need a major to learn.

[@PropelledGamersz]

A lot of upper level Math, Physics, and Engineering actually all combine in various ways, (for example, a course like Statics uses concepts from all 3). Chemical Engineering could be a potential major seeing as all of these different fields combine.

[@mertenderyerli]

@@hutfiftyfive1 xhahahah

[@greenranger3441]

He is an Electronics Engineer.thats why

[@ibrahimalizaini9411]

You are awesome man..you help me since i'm matriculation until im undergraduated

[@muriukiamos2536]

there is happiness when i search a subtopic only to see he has a video on it💯💯💯💯💯

[@hardcoredoufu6199]

Start to watch your video since I was in yr11, now I'm a uni student and still keep watching XD

[@Tihcar_x.x]

i think in loop 2 the V2 will be 8(i2 - i1) not 8(i1 - i2) as the dominating loop is 2nd not 1st

[@gamingfreak4178]

It still made sense tho

[@reginabower7041]

Love this guy's videos. Helped me several times already!

[@olbluelips]

In example 1, why is the current flowing through R2 the difference between I1 and I2? Is it just convention to make both loops flow in the same direction clockwise? (That is, Mesh Analysis does not work if we do not do it this way?) I'm confused by the arrow on the current source. To me it seems to say that I2 should flow in the *opposite* direction, but perhaps I am misunderstanding

[@luis4ever887]

This video helped me a lot. You've done a tremendous work explaining this topic. Thank you!

[@NkamKacyNdoh]

Jeez I understood mesh more than I did in my 3hrs class Thanks very much sir

[@umutaydn6184]

Thank you so much for publishing these videos. You helped me so much already.

[@sleepwalker1803]

You are really good at teaching. Thanks for your effort and time!!

[@Kobbygroovegh]

Infact you are the best teacher in the whole world 🌎 Love u so much

[@AzeezFolajomi]

You have helped me to pass my exam tomorrow already

[@thaigo972]

16:55 shouldn't V4 be 2(I3-I2)? It's a drop for I2 and a rise for I3. Why does he flip it?

[@ntwisisochauke3495]

2 years later i'm still confused

[@kumaraditya5513]

2 months later even I'm confused@@ntwisisochauke3495

[@Blupanther54]

man ur brilliant bro full support from my side Love from India

[@inasfawzi103]

he is called organic chemistry tutor but he teaches everything

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We need a face reveal you have taught me so much

[@Coreyahno]

I have been watching your videos for years, but with this class I don't know if I can. My professors unfortunately uses different conventions on when a current is negative or positive which is the opposite of yours, so even though you're much better at teaching this stuff, I think it's just going to cause confusion learning two different conventions at once. :/

[@habeeb3438]

Eggzactly

[@berimayawamponsah4295]

You’re so good…I love you Man 😁

[@rauldiab9830]

Bro, You’re going to heaven.

[@thompsongift7776]

Thanks I understand this better with your explanation

[@ziadtarek4826]

Thanks from Egypt ♥️

[@deuce-way1440]

this was a very good example. Thanks

[@marsbar3991]

you're my new hero

[@menglimarrero4296]

14:03 Sir Isn't it should be 8(i2- i1)? Coz i2 is potential rise and i1 is potential drop

[@menglimarrero4296]

Edit: I compared the approach of other vloggers, in this video R2 and R4 remains with their polarity that's why 8(i1-i2) In the other approach they reverse the polarity between the meshes Mesh 1 R2 is Positive UPWARD Current downward Mesh 2 R2 is positive DOWNWARD current upward Mesh 2: - 8(i2-i1)-5i2-2(i2-i3)= 0 BY INSPECTION this video is right. 🙏 Thank you for this video

[@سبحاناللهوبحمدهسبحاناللهال-ن5ض]

I was confused as well but the answer is actually correct because there are two ways to solve this. 1) (His way) to keep the polarities constant in each loop while using the previous current calculation. 2) (another way) To change the polarities according to the current flow direction and input the new difference in current by giving priority to the current that is in that certain loop. Both ways result in the same answers.

[@jasperwetzel593]

Bro i owe you an engineering degree, Thank you for all of your videos.

[@jailsondias4102]

At 4:20, he says Vb is 90V, but we can only know Va is 90V and that Vb is in fact smaller than that.

[@derickprinceumanhan3573]

he said Battery

[@vailethmgussi7095]

You are the best GOD bless you sir 🎉

[@mohamedgasim8330]

very good explanation do you provide private tutorial

[@muratgultekin1917]

G.O.A.T tutor. However, at 14:20 it should be I3 instead of I2 I believe.

[@mandymcfadden584]

Organic chemistry tutor? I say organic chemistry god.

[@HossamGezera]

Thank you, you always have what I'm looking for❤

[@abhisheksaraswat1964]

Your explanation is really awesome. Thankyou so much for this one. 💯💯👌👌

[@as.trendygh]

In fact you helped me. 🤝

[@rakeshm2389]

Hi, Thanks for the wonderful video and teaching. One query that in mesh 2, since current is flowing in clock wise, then in v2 = R2 (I2-I1) should have come right? instead of R2(I1-I2) in the equation of circuit 2 (8ohm(I2-I1)) since electrical potential is moving towards higher potential from lower potential. @TheOrganicChemistryTutor

[@joshp3446]

forgive my ignorance, (first problem) but was this just an example problem? or is it somehow actually possible to have more Voltage than what the battery outputs? because if the battery is 90V and point C is 94, im wondering how its possible, does it have to do with the current source? thank you in advance

[@millenjanclarkconsuegra4907]

I also have the same question and also commented on this, and I'm waiting for the response.

[@as.trendygh]

Thanks from Ghana 🇬🇭

[@r2_playz_wr452]

Nice explaining, good steps 🎉

[@barsilgen120]

Thank you so much Tutor. Highly appreciated!

[@Eyeleaf]

Hi. Can you please make a tutorial about BJT and FET circuits?

[@jdndeebee]

hi, can you also do a video for delta to Y transformation? thanks.

[@shinjaokinawa5122]

Good idea.

[@aiditan2338]

u r a life saviour

[@JackMassey-fv8mt]

you know its good when you watched the video understood it and then the second you get stuck come straight back watch a few seconds and it all clicks again. I think its a linked memory with voice complex that recalls information

[@rhisykangale3367]

Thank you Sensei 🙇🏾‍♂️

[@MillerMoore-gq2pe]

Is there any way to find whether my answer is correct or wrong?

[@MatthewTorres-gu9bf]

in the second example, I believe you could have solved the system of equations faster by solving for i1 in the first equation and solving for i3 in the third. Then just plug it all back into the second equation. Then plug in i2 into equations 1 & 2 to solve for i1 and i3, respectively.

[@kevinkibet-n7m]

Be blessed... Thanks 🎉

[@Boomshakalaga]

hello I did the same calculations but in the end, I used Cramer's rule but I got different results on examples at 10:9 my results are i1=15.97 A i2=-9,84 A i3=9,95 A I am certain my matrices are correct.

[@ThilebanTheEngineer]

There are mistakes in this video. He took voltage rise to be negative which is false. Your answer might be right.

[@lewiswilkinson6094]

unbelievably explained, thanks.

[@mailo1787]

Bro this was super helpful Did way better than my college lecturer lol 😂😭

[@abdullazuber2401]

Thanks bro it really helped me a lot

[@sohailjanjua123]

Hi, I like your lecture

[@anwarhussein3180]

Dude I am a stone's throw away from building a ballistic missile thanks to you

[@jasha7579]

How do you know in which order to put I1 and I2 when calculating the difference between them? Why is I1 always first? Is it because that's the order of the loops or? Why isn't it I2-I1?

[@johncabanilla9365]

Man you're the best

[@kifter4254]

There is a error at 15:07. it should be negative v4, its a voltage drop for loop 3 for r4 not a voltage rise so -v4

[@Scarabola]

are we seeing the same video?

[@paulobatitay9362]

Thanks, man. Very informational video.

[@gaiusvalerius6282]

What if you have more than five resistors like adding one or more resistors at the bottom of the circuit please make a video of it 🙏🏾🙏🏾🙏🏾

[@haydnoleary6937]

This man has never said "g" in his Life. Its always "goin" and "doin" and "flowin"

[@pemifo260]

How do we know that I2 equals to 5A? Isn't something coming from the left side? Does this have to do with being "closed loop"? What was going to happen if we didn't have independent current source of 5A?

[@Samuel-ik5wp]

I came into KZbin with an AS in Engineering Technology, I am leaving with a PhD because of this guy.

[@EasinHosen]

you are a life saver man... ❤️❤️

[@versatile_ac2792]

Thanks a lot! You save my day.

[@Lexyvil]

No wonder I kept messing up, my school teaches the other way where if you go from - to +, you put a negative sign in the equation. I interchanged both often.

[@nax1807]

I believe there is an error in the calculation, What he's effectively done is swapped the polarity of the voltage across the 2 ohm resistor R2, here's how, in the first loop he designated I1 flowing from high to low potential through R2 and I2 flowing from low to high, that's fine, but then in the second loop he has designated I2 flowing from high potential to low potential by making the equation -8I2 and designated current I1 flowing from high potential to low potential by making the equation +8I1, this is effectively changing the arrangement of the signs of the voltage across R2 when analysing the current through R2 in the second loop compared to the first how can that be correct? Would the same be true if R2 were a battery? Because the sign of a battery doesn't change since the direction of voltage across it is fixed, and according to the math he's done, he isn't sticking to the sign convention he has assigned for the voltage across R2 from the first loop, i understand he is taking the difference between the currents I1 and I2 but he's doing so in the wrong order, i believe it should be 8(I2 -I1), if you disagree that's totally fine but i would appreciate if you explained why. Many thanks friend.

[@ArjolP]

I got confused at that part as well. Your reasoning is correct I think. I also had a sort of "rule" that I followed for mesh current analysis. When you are working inside a loop, the positive sense of the current is the sense of the current of your current loop. At the first loop, the positive sense would be that of I1, therefore the current at R2 would be I1-I2 because I2 is in the opposite direction from that of I1. At the second loop, the positive sense now becomes that of I2, so the current at R2 would be I2-I1 because I1 is now in the opposite direction of I2 (which is the positive sense). However, it seems that doing it like that is wrong. I checked the values in Multisim (a circuit simulator) and his values are correct. If you solve it with R2(I2-I1) you get wrong values. I hope someone explains why that is the case as I don't really understand it. Edit: One possible explanation probably has to do with the fact that the current has to flow from a point with a higher voltage to a point with a lower voltage. Since one end of R2 is connected to ground, if you take I2 as a positive quantity you are assuming that the current I2 is flowing from the ground up to Vb. Which is impossible. I am not sure if this is the right explanation though.

[@240mains]

The video is too much of a spin . the video is just a bad description of equation writing . And the video lacks detailed information of technique . Confusion number 1 : the Video does NOT use Mesh currents thru R2 , instead he is adopting a Branch current technique thru R2 , because he is using a Single +-polarity across R2 . Basically , the video is a mess and needs to be redone . the Two Fragments would be written this way , when using a Branch current flowing Down thru R2 : +( I1 - I2 )R2 for Mesh I1 , and -( I1 - I2 )R2 for Mesh I2 . however , when using "Mesh Currents" flowing thru R2 , the Two Fragments would have been written this way : +( I1 - I2 )R2 for Mesh I1 , and +( I2 - I1 )R2 for Mesh I2 notice for both Mesh I2 fragments , they are Identical : -( I1 - I2 )R2 is the Same as +( I2 - I1 )R2 . however , the Symantic of writing these Fragments is Hugely different . As said , one is based on using a Branch current thru R2 , while the Second writing is done using Mesh currents thru R2 . if these Fragments seem odd or confusing to write , then you do NOT yet underand the basics of KVL , Ohm's Law , Branch currents , and Mesh currents . NOT your fault , as many books are Poorly written by people who do NOT know what they are talking about ,...especially 2 year Tech school level books ( the worst ) the video is very lacking of KVL with Ohm's law equation writing details .

[@240mains]

@@ArjolP what would happen if someone Pre-labels a +-polarity across a resistor that is NOT +pos Ohm's law , and they are asking for the voltage across that resistor . would that pose any issues during the equation writing process ? the answer should be No . the circuit is still just as easy to analyze regardless of the +-polarities across the resistors . There should be absolutely No confusion . if there is confusion , then something is not yet understood .

[@240mains]

@@ArjolP you do not yet understand how to solve simple physics problems. you have taken the video's analysis Out of Context . you are trying to use a Convention that is in your head . however , the Convention that is in your head is NOT the same convention the video is using . i am posting a new response to Numan Ahmed with a Full explination as to why the first level equations in the video are Valid and Correct , for R2 in the 3 loop circuit . please note , the video is trash and is a very bad way to present circuit analysis .

[@240mains]

yes , the video is trash . however , the first level equations written in the video are valid and correct . to understand this , you MUST use the same Convention and Orientation the video is using . you have a particular Convention in your head that you want to use , however , other peoples analysis might be using a different Convention . Thus , to follow someone elses first level equation writing , you MUST know what Convention they are using . i analyzed his analysis ( Meta analysis ) to understand what he did . ( i can do that ) the 3 loop circuit : the video's convention writes the KVL +-sign as he Exits each component . the video's convention is using Branch currents thru R2 ( the 8 ohm resistor ) the video says he is using mesh currents , however , he is actually using Branch currents . thus he does NOT know how to use mesh currents . But ,... based on the Conventions that he used , the First Level equations are Correct. Here is how he wrote the Fragment you speak of , for R2 , starting with loop I1 : he is Traversing CW ClockWise and he is writing KVL +-sign as he Exits each component. Exiting R2 at the Bottom of R2 is -neg . thus he writes -neg8 ( I1 - I2 ) . note that ( I1 - I2 ) is the Branch current thru R2 . next , for loop I2 , still Traversing CW ClockWise , at the Exit point of R2 ( Top of R2 ) , he writes +pos . +pos8( I1 - I2 ) . again , ( I1 - I2 ) is the Branch current thru R2 . he could have shown : I4 = ( I1 - I2 ) where I4 is the Branch current thru R2 . with I4 flowing Down thru R2 . Your ( observation and curiosity ) are Out of Context . Realize , there are many , many Conventions that can be used , and thus there are many , many ways to write first level equations for the same circuit . All of the Conventions that could be used are ALL Valid , and ALL the first level equations that are written of each of those conventions are ALL valid . however , once we choose a particular ( Convention and Orientation ) we need to "Stick with it" , so we do NOT contradic our selves , and to avoid a convoluted mess ( such is your question ) you should solve a basic vector based projectile physics problem , and apply all that technique to solving electric circuits . ( read beyond the words in the electronics book ,...go deep ) we can always analyze the same circuit using another ( different ) Convention . our initial first level equations will look different . but in the end , the numerical answers will still describe the exact same circuit operation . ( provided we have No errors in our math manipulation )

[@josephangelosangabriel8606]

YOURE THE BEST! THANK YOU!

[@ezekielkibet7930]

Be blessed tomorrow being My exam time

[@abdouabdou-bl5cx]

you helped me a lot thanks

[@DavidGlendaleArdenaso]

had an entrance exam in a job interview where I was to utilize mesh current but R2 has no resistor and is just a wire (or just two points from A to B?) and I'm to find the voltage there; got hardstuck

[@je_ster]

thanks alot for this video, you're a huge help!