pH of Weak Acids and Bases - Percent Ionization - Ka & Kb

[@TheOrganicChemistryTutor]

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[@georgesadler7830]

Professor Organic Chemistry Tutor, thank you for a fantastic explanation on how to calculate the PH of weak acids/bases and Percent Ionization in AP/General Chemistry. The problem selection is excellent; however, I am still confused on solving ICE table problems. This is an error free video/lecture on KZbin TV with the Organic Chemistry Tutor.

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Amazing way of explanation, very clear in explanation.

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I'm so glad to have you The way you explained the ka,kb and percent ionization is explicit

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[@paollamwamba8813]

Thank you ❣️ so much 🥰 it has been long time i studied this topic acid and bases and when I reach at weak acid I'm always confused 🤔 but today i found this video 📸 and i understand easier, may the Lord 🙏 bless you 💯💯💯😊

[@jcynana857]

I want to ask something because i don't understand. What if the Ka is not small enough to ignore the x? how to change it into ax2 + bx + c = 0?

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how can a person dislike this

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wierd ppl

[@ahaf4654]

9.03...I don't understand the link between 10^-5 being small and getting rid of -x at the bottom?

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[@fikakahle_nzuza]

Hey, I’d like to ask about Cl. Why didn’t we include it in the reaction ?

[@kosardhashemi]

yeah i got lost there and on 4

[@maxymtaras2464]

I guess the general gist of it is that Cl is a spectator ion because the compound is a salt, so its kinda like the water where you can ignore it because it would be important. However yeah still a bit confusing on when or when not does this happen.

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very helpful especially for biochemists taking sch 100 and sch 101

[@hlimsmdova5841]

Which of the following aqueous products in the same environment has the lowest freezing point? A) 0,20M K2SO4 B) 0.25M NaCl C)0.15 M CH3COOH D)0.15 M C3H5(OH)3 E) 0.40M C12H12O11 Pls help

[@timbers4166]

A

[@ethkid8925]

You can calculate 1-4 much faster using pH = (-log(Ka)-log([HA])/2 Alternatively you get pOH for Kb: pH = 14 - pOH and Ka = 10^-14/Kb

[@lemonyman1218]

if you do use this method wont the values be different from the ICE table (because in ICE we ignore the -x)?

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😮

[@susantori6625]

Could you please make a video for solving the Systematic Treatment of Equilibrium?

[@joyofliving5352]

Hi teacher, could you do a tutorial for relationship between ionic strength and pka for weak electrolytes (including biological environments)? There's this consensus that an activity coefficient is required in practical terms to be able to calculate dissociation equilibrium constant - as solution departs from ideal behaviour. If you can derive the equations and do few examples, and indicate when low or high ionic strength may or may not affect pKa or pH, that's helpful.

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Awesome video with so many examples with different situations ❤❤❤

[@mahya8450]

Thanks very much for these videos😍, but I didn’t understand why sometimes we use Ka and other times we use Kb ?

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[@prinzecesartonares9332]

at 16.38 what will happen to Cl atoms ? didn't the problem states NH4Cl, so why only use NH4?

[@Yumia5472]

I think there is an error here

[@benjaminadams3813]

At 9:08 you say "that because 10^-5 is pretty small, so we can ignore that x", why can we ignore that x? Also, how do you know when to use the positive or negative value to the +/- of the square root? Thank you in advance, sorry for the questions!

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[@najatmakinde5955]

For the 3rd question, why can’t we use NH3 + HCl -> NH4+ + Cl-

[@karllouieclaro2090]

I just have one question in mind, at what Ka value is it considered to be a weak or strong acid?

[@kyzola569]

When Ka is greater than 1, it is a strong acid because that means the numerator is larger than the denominator, so there is more ionization, so the acid is stronger

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[@subulwasitimela3334]

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[@aditya06panda]

At 3:42 Ka . Kb = Kw = 1 x 10^-14 is temperature dependent then what would be the equation at 0 degrees celcius?

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[@litaz4378]

20:13 where does the CL come from in the question

[@nweed4449]

ya i was thinking the same thing

[@matixx9180]

I was wondering the same thing

[@keelinm2898]

NH4Cl should dissociate into NH4 + Cl-

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No examples with a coefficint? My teacher didn't do one either but of course gave us one to do

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[@arif-erzincani]

Can you help me solve this question -> calculate the pH of 0.250 M NaHCOs at 25 °C. K41-4.30 x 1077 and K>- 5.60 x 107 ! for H2COs.

[@emmanuelaikins1924]

Thanks a million for this video. But you didn't explain why Na in NaF is a spectator ion

[@handersonhasseth132]

You want to write an ionic equation and then a net ionic equation. Once you get it, you will see that Na+ is going to be on both sides of the equation and thus, it cancels out.

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2. The dissociation constants of HCN and NH4OH are 7.2 x 10-10 and 1.85 x 10-5. What is the pH of a 0.05M NH4CN solutio

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