To Construct Any Regular Polygon Given the Diameter of a Circle - Method 2

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His Grace Tech. Tutor - Technical Drawing ACADEMY

His Grace Tech. Tutor - Technical Drawing ACADEMY

Күн бұрын

Пікірлер: 20
@MasuzyoMunkondya
@MasuzyoMunkondya 2 ай бұрын
Thank you 💕❤
@annewolf459
@annewolf459 7 ай бұрын
Thank you for giving me answer to my long term quest to be able to draw an equilateral pentagon inscribed in a circle. 👌🏿
@HisGraceTechTutor
@HisGraceTechTutor 7 ай бұрын
All thanks to God
@annewolf459
@annewolf459 7 ай бұрын
@@HisGraceTechTutor may God bless you with wisdom. Now that is said, will you tell as how to set up the square when drawing the line to divide the diameter into equal parts? Thanks 🙏
@ThePaulTM
@ThePaulTM Жыл бұрын
Excellent Work. Helical order is the System of Life Forms not Chaos.
@HisGraceTechTutor
@HisGraceTechTutor Жыл бұрын
Thanks
@babbaroots
@babbaroots Жыл бұрын
This method is for the diagonal (across-corners) of a polygon.
@HisGraceTechTutor
@HisGraceTechTutor Жыл бұрын
Yes
@annewolf459
@annewolf459 7 ай бұрын
It looks like your circle diameter is less than 6mm. Why?
@HisGraceTechTutor
@HisGraceTechTutor 7 ай бұрын
I don't know
@wizrom3046
@wizrom3046 11 ай бұрын
Draw lines from P through all the even numbers, not just 2. So from P through 4 Also P through 6 That will give you more polygon points without the accumulated error from repeated compass arcs
@HisGraceTechTutor
@HisGraceTechTutor 11 ай бұрын
Thanks
@rodneysomebody3009
@rodneysomebody3009 3 ай бұрын
Can you draw a nonagon with this method
@HisGraceTechTutor
@HisGraceTechTutor 3 ай бұрын
Yes
@HisGraceTechTutor
@HisGraceTechTutor 3 ай бұрын
Yes
@HisGraceTechTutor
@HisGraceTechTutor 3 ай бұрын
Yes
@MohamedMathani
@MohamedMathani Ай бұрын
thanks
@HisGraceTechTutor
@HisGraceTechTutor Ай бұрын
Thanks to God
@rawarmed6873
@rawarmed6873 11 ай бұрын
Why did you use 2 on the diameter? What if it psssed through 4?
@HisGraceTechTutor
@HisGraceTechTutor 11 ай бұрын
Whichever polygon you are constructing even be it 100 sided, the line drawn from the intersection of the arcs must pass through point "2"
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