I've seen many amazing lectures on QFT (Coleman, Tong, etc), but this are the best I've seen on these topic of renormalization and other topics also. Lectures 8 and 9 on this course on QFT2 and the renormalization lecture in your QFT1 (don't remeber the number of that lecture) are the best material available. Thank You very much for sharing.
@renzotamirovillazonscholer56665 жыл бұрын
OMG! This lecture is pure gold. I remember taking a Harvard QFT course, I kept quiet and calculated, it went well. But I never understood what I was doing until seeing this video, finally! Thank you so much!
@UnforsakenXII5 жыл бұрын
What a lucky scholar to take it at Harvard. I'm hoping that Berkeley lets me into their class this fall. : D
@VPN144943 жыл бұрын
the philosophy behind renormalisation was very elusive to me, at best I could do calculations... Now I understand better. Brilliant lecture. Thanks Tobias
@Simonchongqing6 жыл бұрын
Amazingly clear presentation of the renormalization theory! Thx a lot!
@oguzhanyucel62576 жыл бұрын
Perfect Bro! But please try to use bigger letters. We can not see it. Just an humble idea: maybe you attach the corresponding notes below.
@Mvu65 жыл бұрын
Wow, you are doing important things! Thank you very much!
@UnforsakenXII5 жыл бұрын
I just realized that this is a summer course. They don't offer summer grad courses at UCB unfortunately.
@madhavestark31733 жыл бұрын
This is weird. But I am thinking of attending physics grad school at UBC. Mind giving some advice?
@UnforsakenXII3 жыл бұрын
@@madhavestark3173 UBC or UCB?
@madhavestark31733 жыл бұрын
@@UnforsakenXII my fault....I m dyslexic and read it as UBC
@UnforsakenXII3 жыл бұрын
@@madhavestark3173 No problem. Good luck with your application nonetheless!
@rafaelbendavid40414 жыл бұрын
Dr. Osborne. I have a question: that integral I=2iC9sqr(k)/2 appears to be a complex function. is that problematic?
@tobiasjosborne4 жыл бұрын
thankyou for your comment. I am not sure which integral you are referring to? (What is the time stamp?) If it is the integral I = 1/2(-i\lambda)^2 (i)^2 \int ... etc. then this is not a problem: this integral appears in an expression for a probability amplitude and hence may be complex. (The probability we get by taking the absolute value squared will be positive). I hope this helps; sincerely, Tobias Osborne
@rafaelbendavid40414 жыл бұрын
@@tobiasjosborne , 1:18-19 I=2iClog(k^2/2). Yes, that makes sense . Thank you!
5 жыл бұрын
You are doing this like a genius you know :-) tnx man
@arjunkolli9924 жыл бұрын
I might be being stupid but isn’t the inverse temperature directly measurable because the temperature is directly measurable so it’s not a parameter? Excellent video btw
@tobiasjosborne4 жыл бұрын
Many thanks for your comment. I would say that, for gapless scale-invariant systems, the temperature is measurable up to an overall scaling of the energy. (That is, the temperature is only defined once we've chosen an overall energy scale.) This is analogous to measuring energy where we can only measure differences: we need to set the zero point of the energy before we can measure energy. I hope this helps. Sincerely, Tobias Osborne
@samreenzaman81122 жыл бұрын
hi , can someone please recommend a good book/notes for more mathematical description of renormalization of phi cubed or phi four theory for someone self studying
@MrMas92 жыл бұрын
Useful QFT books I found are Ryder, Schwarz, Srednicki
@mattmolewski74756 жыл бұрын
Thank you so much for sharing these.
@davidhand97213 жыл бұрын
I generally like this line of reasoning and it's a good observation, but explanation is not strictly equal to compression. A compression would be a theory that describes and reproduces every data point you have - but that's the limit. It can't theoretically generate predictions, and predictions are a better metric of understanding.
@nujuat4 жыл бұрын
Wow, I actually understand this now. Thanks :D
@markkennedy97678 ай бұрын
This dude has some serious blackboard game. The philosophical prelude is interesting so far.
@aueltis1894 Жыл бұрын
May I ask how did the differential equation in 1:27:30 arrive?
@tobiasjosborne Жыл бұрын
If I remember correctly, I believe one differentiates both sides of the equation for M wrt K_C. Since M is constant you get the DE.
@wulphstein5 жыл бұрын
We should talk about the physics constants.
@georgiossmyridis61452 жыл бұрын
Absolute Legend. One question though, what does he exactly! mean by operational meaning of a variable.
@tobiasjosborne2 жыл бұрын
thankyou for your comment. The definition of "operational interpretation" (or "meaning") I am using here is that there exists, at least in principle, an experiment that is capable of measuring the quantity or variable. E.g., a global phase in QM has no operational meaning or interpretation because there is no experiment which can measure it, even in principle. I hope this helps. Sincerely, Tobias Osborne
@jonashartmann66876 жыл бұрын
Great lectures. For some reason the video stutters for me which is a shame
@tobiasjosborne6 жыл бұрын
Many thanks for your comment. The stuttering might be due to the quality settings overtaxing your computer. Try watching at a slightly lower quality to see if the problem persists. Sincerely, Tobias Osborne
@kilianklaiber6367 Жыл бұрын
Great lecture, but the elaborate justification for "subtracting infinities" doesn't convince me.
@shayangfkk79483 жыл бұрын
wow amazing wish I have found you sooner
@aeroscience98344 жыл бұрын
1:20:00 I don’t see how this is correct. Taking s=0 leads to a divergence even with finite k_c, but that shouldn’t happen.