I love your slow, patient method of explaining! It feels like the video was really made with learners in mind. I always used to get confused about whether a critical point meant that one of the partial derivatives was zero, or both of them were zero. This video provided great intuition why the latter is true. Thanks! :)
@TomRocksMaths4 жыл бұрын
This is really great to hear - thank you for sharing :)
@majidshajarat8120 Жыл бұрын
Very good ❤
@StradexEngine4 жыл бұрын
From my perspective of things, you are the coolest person alive.
@TomRocksMaths4 жыл бұрын
You're too kind
@rohithnarra90263 жыл бұрын
Man I love that navier stokes tattoo Dr Tom
@TomRocksMaths4 жыл бұрын
Part 2 on classifying the critical points here: kzbin.info/www/bejne/a37CpaZuhpd_e68
@itsreeah26633 жыл бұрын
I’m really blind and just 14 and I’m watching this
@sam-ui5lc3 жыл бұрын
I have my maths exam tomorrow and this was really helpful. Thanks a ton
@TomRocksMaths3 жыл бұрын
Good luck!
@dragoncurveenthusiast4 жыл бұрын
Thanks for this, Tom! I'm relatively familiar with differentiation and liked the exercises in high school, but it's good to get a brief refresher on partial differentiation! You are such a patient explainer, it's so enjoyable to follow you through the steps of the example.
@TomRocksMaths4 жыл бұрын
Amazing thanks! Part 2 is now live here: kzbin.info/www/bejne/a37CpaZuhpd_e68
@dragoncurveenthusiast4 жыл бұрын
@@TomRocksMaths Thanks :-)
@I_like_science3 жыл бұрын
I really enjoy your videos even though I never really understand what you are describing or doing on the board. They encourage me to go and learn. Your channel is small and it's definitely not because your content isn't good. I respectfully suggest you to think about approaching more people like me who are truly fascinated by math but never got the chance to pursue higher maths after highschool. I'm sure you are a very busy but consider making a series of courses that starts with high school maths and then move on to higher maths. This approach was taken by Daniel Schiffman from the KZbin channel ,The coding train. This resulted in his channel growing at a very fast pace and getting people REALLY interested in coding. Thank you for taking time out of your day to make these videos.
@TomRocksMaths3 жыл бұрын
Thank you
@topilinkala15942 ай бұрын
MIT has very good Calculus courses on video.
@Esternosis574 жыл бұрын
Hello, my name is Omar from Venezuela, excellent class, when do you publish the second part? If you don't mind, could you give us an example of these solutions applied in real life
@TomRocksMaths4 жыл бұрын
Hi Omar - part 2 will be out next Wednesday (October 14th).
@rogerjohan96214 жыл бұрын
WOW Dan TDM is teaching me maths!! (awesome video btw)
@TomRocksMaths4 жыл бұрын
My friends agree with you...
@michaelhall58013 жыл бұрын
So true! The accent, tattoos and hair are all so similar XD
@deeppathak62043 жыл бұрын
Amazing explanation 🙌🙌👍
@TomRocksMaths3 жыл бұрын
Thanks Deep!
@charlesabernathy58426 ай бұрын
Oxford?! I am in the boring New York City. Just kidding.
@Synthenist4 жыл бұрын
I appreciate your ambitions, but I still do not know what your hand gestures wanna try to tell me 🙈😅 But jokes besides - I really love how you explain things, very enjoyable :)
@TomRocksMaths4 жыл бұрын
Haha - awesome thanks
@jorgelechon80444 жыл бұрын
I'm not speak English, but I could understand a little. I really enjoyed the video thanks so much.
@SaschaRobitzki10 ай бұрын
My z=x^2+2xy-y^2+y^3 looks very different on Maple. 😆
@deang5622 Жыл бұрын
This is school level maths that we studied at age 16-17. It is not even university level.
@birdost8448 Жыл бұрын
senin canını yerim, çok güzel anlattın çok teşekkür ederim.
@sanujatharinda65254 жыл бұрын
Amazing teaching...
@TomRocksMaths4 жыл бұрын
Thanks Sanuja!
@JetteroHeller832 жыл бұрын
Anyone know how to change the window limits for the 3D plot in Maple Calculator?
@TomRocksMaths Жыл бұрын
I think it's been updated so you can just drag them now
@wingslax3 жыл бұрын
I wish you had taught me multivariable calculus when I was in college. This is great stuff!
@TomRocksMaths3 жыл бұрын
Glad it helped Ben :)
@harshsharma57683 жыл бұрын
We can have a inflection point where slope is not zero right?
@TomRocksMaths3 жыл бұрын
For a true inflection point the gradient has to pass through zero. You can have curves that look like they have inflection points, but if the gradient never reaches zero then they are not true stationary points.
@desklamp7013 жыл бұрын
I'm watching your videos to make A-level maths look alot easier in comparison which kinda helps me :)) Any tips to achieving an A*?
@TomRocksMaths3 жыл бұрын
Beyond working hard and doing lots of practice questions, exam technique is also really important for the top marks. Make sure you re-read every question so that you are answering what it is asking, not what you want it to be asking... Also, leave some time at the end to double check your answers all make sense!
@desklamp7013 жыл бұрын
@@TomRocksMaths Thank you Tom!!
@lsubandtrumpet2014 Жыл бұрын
Where do u get -4y from?
@MarkusDarkess4 жыл бұрын
You said you like tint numbers. Plankth length. Is tied to special right triangles. Initial square has 4 special. Right triangles. So when it is cubed it has a square with bottom surface 4 special right triangles top of cube 4 special right triangles. And the 4 surfaces around the cube each have 4 special right triangles. So special right triangles of that square cubed Is 24 special right triangles. So a 1ft by 1ft by 1ft cube has a surface area. Of 24, special right triangles. The square half its size. Is 2 special right triangles. . Cubed. Has 2 special right triangles on top and bottom and the for surrounding walls. Has 12, special right triangles. So 2-D. Goes from 2-4-8-16-32-64-128,etc.. 3-D from 12-24-48-96-192,ect.. Minecraft. Cannot construct a 16,by 6 cube with out adding extra surface area. And that circles at these spots. Should be doubling in area as well. And the area of a circle is just pie. Immeasurable.. And then if you make a square. The half sized square is immeasurable. And all the perfect squares it creates. Are also immeasurable. Pythagream thearum says. As long as I have a right triangles. With 2equal sides. I can double area. 1to two. Then the next doubled square has 8x the area. Or eight special right triangles. Because 0,0/0,1/-1,0 3^2+4^2=5^2. The 2-d points Can be shifted around To make a square. One way. Then a cube. And another way makes a 2-d rectangle. But the 3-d rectangles can be made 2-ways of varying heights.
@eulersfollower71403 жыл бұрын
Not changing? ,do u mean the derivative is zero? Thank you for this amazing explanation🎉🎉
@TomRocksMaths3 жыл бұрын
Yes that's correct. If a function isn't changing at a certain point, then it must have zero derivative there.
@ikhandlelatertiaryaccessso12143 жыл бұрын
Thank you
@TomRocksMaths3 жыл бұрын
You're welcome :)
@nicholasspeechley97854 жыл бұрын
I am also single.
@CGKittenz4 жыл бұрын
Waiiit how did we get to -4y+3y^2=0???????
@TomRocksMaths4 жыл бұрын
The df/dx = 0 equation gives that x=-y and so we substitute this into the df/dy = 0 equation so 2x - 2y + 3y^2 =0 becomes 2(-y) - 2y + 3y^2 = 0 which gives the equation you asked about.
@CommanderdMtllca4 жыл бұрын
If df/dx of y^(n) is 0 then isn't df/dy of x^(n) also 0 instead of 2x?
@TomRocksMaths4 жыл бұрын
Yes - the 2x term in the df/dy calculation comes from the y-derivative of the 2xy term.
@NoahPrentice4 жыл бұрын
in that part of the video, he's doing df/dy of 2xy. Since df/dy of cy (where c is a constant) = c, and since 2x is a constant, df/dy of 2xy is 2x.
@CommanderdMtllca4 жыл бұрын
@@TomRocksMaths Woops! Missed that part lol
@Yamil.-1234 жыл бұрын
Se ve que explicas muy bien el cálculo gracias por tomarte el tiempo de ensenar. Te agradecería mucho si pudieras poner subtítulos.
@TomRocksMaths4 жыл бұрын
Thank you - I'm afraid I don't speak Spanish, but you are most welcome to add them yourself through community contributions!
@Yamil.-1234 жыл бұрын
Bueno de todos modos muchas gracias
@HasekuraIsuna4 жыл бұрын
Would be great if you had shown the (-4/3,4/3) on the graph after calculating it.