Topics 7.11

Topics 7.11 - 7.14

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@mrfarabaugh 10 ай бұрын

1:15:35 I'm sorry that there is a small typo on the slide in this section of the video. Because there is a net conversion from reactants to products, this slide should say that "the equilibrium shifts toward the aqueous ions." Here is a link to a picture of the corrected slide: bit.ly/3ShAFBL

@kaitlyn8185 8 ай бұрын

At part 24:10, would it be more accurate to say that the value of [Ca+2] in the 100mL sample is roughly equal to the value of [Ca+2] in the 75 mL sample rather than exactly equal, since some (though very little) Ca(OH)2 has dissolved? Thank you!

@mrfarabaugh 8 ай бұрын

Some of the solid calcium hydroxide likely dissolved when additional water was added to the saturated solution. However, equilibrium has been re-established in the new solution. There is a distinction between the AMOUNT of solid (moles, grams) on the bottom of the beaker and the CONCENTRATION of the calcium hydroxide in the saturated solution. The concentration of calcium hydroxide must be the same in both beakers because both solutions are saturated and at the same temperature.

@kaitlyn8185 8 ай бұрын

@@mrfarabaugh Ohh I see! So though the AMOUNT of the calcium hydroxide solid does decrease, the concentration remains the same, as it takes up the same "amount/percentage" of the solution? That is, mol/L?

@mrfarabaugh 8 ай бұрын

@@kaitlyn8185 Yes. You can think of the Ksp value (at 25°C) for an ionic compound as a property of that compound. It applies to the equilibrium system of being a saturated solution of that compound. Once you have established a saturated solution of an ionic compound, then the concentration (mol/L) of the ions in that saturated solution (at 25°C) is only dependent on the value of Ksp itself. The concentration of the ions is NOT dependent on the volume of the solution. In fact, the specific reason **that I wrote** parts (d) and (e) of Question 2 in this packet was to address that issue and the potential misconception associated with it!! Thank you for your comments.