Wonderful lecturer that makes physics fun and understandable !!!
@Yungmo018 жыл бұрын
Classic static problem. Thanks for sharing.
@yoprofmatt8 жыл бұрын
+Yungmo01 Yungmo, Yes this is definitely one of the classic problems. I'm hoping to hit them all soon. Cheers, Dr. A
@1oakdesign3533 жыл бұрын
Great video! Would you mind explaining how to figure out the tipping point for a pedestal table. I’m having trouble deciding the amount of allowable overhang past the table base. Thanks.
@JoeySalinas125 жыл бұрын
Wait a second... is this guy writing backwards?
@yoprofmatt5 жыл бұрын
Nope. Secret here: www.learning.glass Cheers, Dr. A
@scratch123678 жыл бұрын
Thanks. You really helped me out.
@yoprofmatt8 жыл бұрын
+scratch12367 You are very welcome. That's the goal is to help people out. Cheers, Dr. A
@user-fr9ec4xq1e3 жыл бұрын
god bless you young man 🙏
@haddow7772 жыл бұрын
Huh, I must be misunderstanding how this is all done. Of course, I only did up to early college calc a couple decades ago, so my skills are terrible. I'm just interested in the math for a problem. Why is the axis, which I would assume would be the point where the beam would rotate around, be at N0? You said you wanted to solve for X, the point where the man would be standing on the overhang, where it would lift the beam off N0. So, wouldn't that make the axis point be over N1, since the beam would be rotating over that post? Or, is the axis the area where the range of motion will be? Sorry, just confused by the lingo. Maybe I'm mixing up axis for axle.
@yoprofmatt2 жыл бұрын
When objects are in equilibrium (net force = 0 and net torque = 0) that means that you can pick ANY axis of rotation you want. Obviously, if the object has not started rotating, it is not rotating about any axis. So you can absolutely pick a different axis of rotation and if you're careful with your math, you should end up with the same result. Cheers, Dr. A
@haddow7772 жыл бұрын
@@yoprofmatt oh, okay. Thank you.
@macworldrecord82734 жыл бұрын
Thank you so much!
@yoprofmatt4 жыл бұрын
Muhammad Rashid, You're very welcome. Glad you're enjoying the videos. You might also like my new site: www.universityphysics.education Cheers, Dr. A
@tinybabyseal5 жыл бұрын
You rule.
@yoprofmatt5 жыл бұрын
Thanks. I'm enjoying it. Cheers, Dr. A
@detabernard7 жыл бұрын
It's so helpful....but I don't understand smth: Why we don't have a normal force acting on the place where the man is on the beam??? Why you didn't mention it....I sow another problem where also they didn't take in consideration that force, but I don't understand why since the man is over the surface???? There are n1 and n0 force but where is the normal force acting on the man???
@puneetpst5 жыл бұрын
The normal force is applicable in the free body diagram of the man - not the FBD of the beam - as it acts on the man, not the beam.
@rootclasses50383 жыл бұрын
thanks sir
@danielleng77075 жыл бұрын
Could you make a video about your set up? What are you using to project the transparent board? Thanks!
@yoprofmatt5 жыл бұрын
Check our webinars at www.learning.glass Cheers, Dr. A
@aifazabbasi57056 жыл бұрын
great video but bruh you lost me on looking at you in the background
@jasonwu78237 жыл бұрын
thx
@alistairtodd15156 жыл бұрын
This was as clear as day to me right up until the last equation. How did you derive that?
@yoprofmatt6 жыл бұрын
The second to last equation has the torque: force * lever arm. The very last equation is setting the torque equation equal to zero and solving for x. Try it yourself on paper. Cheers, Dr. A