I(1)n1 nullyfying l(2)n2 & I(0) maintaining the initial flux So how can we say (I(0)+I(1))n1=I(2)n2 ?
@suryanarayana85304 жыл бұрын
she didnt say like that....
@sudarshanpoudyal50893 жыл бұрын
Because i0 is very very small 0.2 x i1 ......so its effect is neglegible in the sum of product ixn..
@amitbaroi91623 жыл бұрын
I1n1 nullifies I2n2 only in ideal transformer, where i0 is 0. But in case of practical transformer I1 has to supply for both nullifying and i0. So I1n1 will be equal to I2n2 + ion1. After nullifying only ion1 will be the net MMF.
@shreenathkamble58622 жыл бұрын
We can just say like this, The flux which neutralised The flux established by the Io, will be neutralised by the I1, so that N1*I1= N2*I2, so that I0 will again be able to establish the required flux in the core. In short, I0 will always do the job of establishing the flux in the core, and Additional I1 will do the job of power transfer. i.e. V1*I1= V2*I2. Corollary to this that in load case, power transferred is zero, cause I2=0, and ideally I0 is also zero.