Transforming an infinite horizon problem into a Dynamic Programming one

  Рет қаралды 39,515

Constantin Bürgi

Constantin Bürgi

Күн бұрын

Пікірлер: 47
@caniggia1993
@caniggia1993 7 жыл бұрын
Thank you my friend, maybe my professor should be watching this.
@md.arsalasif7522
@md.arsalasif7522 17 күн бұрын
This solved almost all of my doubts. Thank you!
@Meowmix8088
@Meowmix8088 6 жыл бұрын
University of Chicago student here. This is super helpful. Thank you
@zoesoohyunlee7209
@zoesoohyunlee7209 3 жыл бұрын
Thank you so much for the video! Saved my life for this term XD
@martinbrolarsen6580
@martinbrolarsen6580 7 жыл бұрын
This just made it all clear. Thanks a lot, sir!
@pawaredpiyajitmetta2172
@pawaredpiyajitmetta2172 6 ай бұрын
Thank a lot professor, it is so clear to me.
@carloottomano4243
@carloottomano4243 7 жыл бұрын
This was fantastic and extremely clear. Thank you very much!
@scarlettliu885
@scarlettliu885 3 жыл бұрын
Thank you very much!!! This Vedic helps me a lot.
@TheBboy0720
@TheBboy0720 3 жыл бұрын
Excellent and extremely clear
@forwoz
@forwoz 7 жыл бұрын
Really awesome. Thx you for your explanation.
@62294838
@62294838 3 жыл бұрын
This is incredibly prefect!
@mohammadrezamahmoudi8564
@mohammadrezamahmoudi8564 5 жыл бұрын
Thank you very much for your amazing and helpful tutorial!
@adrianschroder4847
@adrianschroder4847 4 жыл бұрын
Much appreciated!! Great breakdown
@osvaldoquintellajunior9858
@osvaldoquintellajunior9858 2 жыл бұрын
Fantastic explanation! Thanks a lot!
@fatimazaidi7068
@fatimazaidi7068 5 жыл бұрын
This is perfect. Thank you!
@niazghumro2350
@niazghumro2350 3 ай бұрын
Very informative video but screen is little bit dim. Please refer the book which you are following in this course. Thanks in anticipation prof.
@АлександраТеплоухова
@АлександраТеплоухова 5 жыл бұрын
Спасибо большое! Очень понятно и просто! Thank you! So clear and easy!
@wondwesenwubugetahun3415
@wondwesenwubugetahun3415 6 жыл бұрын
It is brief and interesting. Thanks!
@villageandanimals6986
@villageandanimals6986 4 жыл бұрын
Thank you very much.
@ablaamegadze9964
@ablaamegadze9964 3 жыл бұрын
Thanks very much my teacher .
@kamrulhassan7157
@kamrulhassan7157 6 жыл бұрын
Wonderful lecture. Thanks a lot.
@zzambezi1959
@zzambezi1959 2 ай бұрын
If the function to be maximized is an infinite series, I think it is needed to suppose that beta
@simonandradefonfach2317
@simonandradefonfach2317 6 жыл бұрын
grande juliprofe gringo
@rodolfosaturninoperezrodri7473
@rodolfosaturninoperezrodri7473 4 жыл бұрын
Great Video!! Why do we have a beta in front of L1(k) ? Isn`t that part of the equation already discounted?
@j.brightlee3314
@j.brightlee3314 4 жыл бұрын
can someone tell me what he said at 8:30, "and it drops xxxx, what it does current stuff does not have xxxx ~ ". I have watched it over and over again, but still yet figured out what the word is... thx. My English is too bad...
@aesahettr
@aesahettr 3 жыл бұрын
indices
@MrMytubevidmaker
@MrMytubevidmaker 5 жыл бұрын
10:29 How do you obtain u' if you're deriving with respect to k'? You should be left with -u.
@constantinburgi3995
@constantinburgi3995 5 жыл бұрын
I use the chain rule. If you take the derivative of g(f(x)) with respect to x you will get g'(f(x))f'(x). Or here: the derivative of u(x-y) with respect to y is -u'(x-y). As an intermediary step, you can also define f(x)=v, then the derivative of g(f(x)) is equal to the derivative of g(v) with respect to v times the derivative of f(x) with respect to x. Once you took the derivative, you replace v with f(x) again to get the above result.
@chardduc
@chardduc 4 жыл бұрын
goshh...much better than my professor
@francoisallouin1865
@francoisallouin1865 7 жыл бұрын
GREAAAAAAAT !!! Bravo.
@mleodej
@mleodej 6 жыл бұрын
Very helpful, thanks!
@user-vd8pc1vh6j
@user-vd8pc1vh6j 4 жыл бұрын
why is r constant? shouldn't it be function of t?
@ablaamegadze9964
@ablaamegadze9964 3 жыл бұрын
Can you help me for a problem solving a exemple ?
@johnnymonteiro5577
@johnnymonteiro5577 3 жыл бұрын
Thank you!!
@gunnarulfars
@gunnarulfars 7 жыл бұрын
Hello, Im wondering how to euler and the policy/decision rules will change if interest are a function of time? Best regards.
@constantinburgi3995
@constantinburgi3995 7 жыл бұрын
As long as the path of the interest rate r is deterministic, there is little change. ct+1 is the optimal response to all future interest rates and thus ct is a function of the optimal consumption tomorrow ct+1 and the current interest rate rt.
@lannister1877
@lannister1877 8 жыл бұрын
Good! very useful!
@zhifengwang5455
@zhifengwang5455 7 жыл бұрын
thank you very much
@pedrolopes2811
@pedrolopes2811 6 жыл бұрын
excellent
@francoisallouin1865
@francoisallouin1865 7 жыл бұрын
At 12:09 you say " that's gone". This is false my dear . You can't apply the first order cond. directly to a max operator. You need to use the envelope theorem again which leeds to a cercle of infinite derivations ....your method in not correct.
@constantinburgi3995
@constantinburgi3995 7 жыл бұрын
You are right that I do not go into the details of explaining the Benveniste - Scheinkman envelope theorem (and its assumption). Once applying it though (after verifying the assumptions), it is easily shown that the term disappears.
@francoisallouin1865
@francoisallouin1865 7 жыл бұрын
Thank you very much for sharing this knowledge . Once again you prove you are awesome !! with respect.
@constantinburgi3995
@constantinburgi3995 7 жыл бұрын
No worries, I should have pointed it out in the video! As a side note, if you want to derive the envelope condition, you need to take the derivative of V(k'') with respect to k''' and multiply it with the derivative of k''' with respect to k'. Given that the first derivative is 0 based on the first order condition, you immediately get the result you wanted.
@KirilStanoev
@KirilStanoev 6 жыл бұрын
Your t and + look the same and it is confusing!
@BilBumm
@BilBumm 4 жыл бұрын
Haha I tell you I have not seen any macro prof whose t doesnt look like a + ;D
@theinstigatorr
@theinstigatorr 7 жыл бұрын
I love you
@yaathumoore360
@yaathumoore360 3 жыл бұрын
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