Trick to write the product of Williamson's ether synthesis.

This video helps you to write the products of Williamson's ether synthesis.

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[@wwetheme9733]

Answer is "A" mam.wow awesome tricks u were telling mam.Thanks for ur dedication mam

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[@aravindbabu1680]

"a" route is correct for ether synthesis mam. Test yourself question..mam.

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Mam a is ans. Thank u so much mam for it valuable help. I like watching ur videos. Cuz u teach in a very easy way.

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Good 👍

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a, is the correct option mam. I depend on your classes to prepare for neet.I really like your classes .you're GREAT

[@amrittiwari2173]

Plz Ma'am, make a video on reaction conversions in organic chemistry (short trick)

[@gangangangan2816]

Route 'a' is correct option mam ,becoz 'b' is not sp^2 hybridisation so it is not SN^2 reaction mam

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[@KomaliMam]

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[@roshinimathala4580]

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[@rambabunamana105]

'A' is the correct option mam

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Kindly make a video on identifying thr type of reaction. I mean to say thay in exams they give an equation and ask us to identify the type if reaction involved and the intermediate formed. Donno how to do these type of questions

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[@KomaliMam]

Thank you Manoj 😊

[@user-mu6ti6ry1w]

Answer a should be correct as the bridged benzene do not act as alkyl halide part so obviously methyl group me the alkyl halide part which is clearly shown in option A

[@gugulothsairam2226]

a is correct mam for good yeild of ether

[@Sanjaychaudhary-xb7ej]

mam organic chemistry me rxn kese yad kare its so confusing to learn all

[@praveenjeyachandran8100]

a is the correct answer, ........ thankyou mam

[@Tejasiwini___]

Absolutely we can say that option A is the correct answer Me--cl 1' undergoes SN 2

[@shaikvayyakantikhajamohidd1397]

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[@Drdebjitjana]

Ma'am pls make a video on how to choose the reactants when hydrogen halides or when sodium halides are given ..!!

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Debjit Jana YA we need it...... 🤔🤔🤔🤔🤔🤔🤔🤔

[@allamrajkumar6120]

Debjit Jana a

[@sudhayank6912]

Do you get mbbs

[@anupamafrancis739]

last question answer :a . Thanks mam...

[@shambavikr3940]

You made it mam your classes always give happiness😇😇 opt a mam

[@ajeetazad7086]

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[@lathas0210]

a is the best way to get product because in b sp2 hybridized carbon is not there

[@mathivarshini8148]

Mam , A is the correct answer

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[@panimathi4136]

a the correct answer and u r a very good teacher mam

[@hemalatharamalingam461]

Ans is a mam. Becoz alkyl part should not be bridged halide

[@neelamgupta5174]

"a" is correct option

[@rosyt8252]

Very nice explaination mam.your writing is neat n clean

[@chinna.c268]

Hand writing super akka

[@Faizanyoutuber]

Ma'am Base catalyst ( NaOH) ki jaga Acid catalyst i.e, sulfuric acid use kr sakty Hain?

[@aswathiazh3617]

Thnk u mam. trick is very useful. "a" is the answer.

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a gives better yield mam.u r class is superb . 😍😍😍

[@HangingQueen]

Answer is A You are excellent mam You are super mam

[@subasuba8731]

a) is correct mam

[@ghssmavadipannai8338]

Madam, alcohol doesn't react with sodium hydroxide, it reacts with only sodium, please confirm, thank you. Annalakshmi. S

[@karivedamanikantachowdary86]

option a mam. ''WONDERFULL EXPLAINATION MAM''

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[@karthicsurya5536]

Option a ma'am . Because in b bridged halide is present it doesnt gives sn2

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Love from Bengal

[@SureshKumar-tk3jr]

through 'A' path the reaction will take place mam

[@ghssmavadipannai8338]

Mam, your videos very nice, but alcohol doesn't react with Sodium hydroxide, only with sodium.

[@poonamgautam7835]

a option is correct!!!! Thank u ma'am

[@dorothybrinthajasmined7853]

Mam a is the correct answer

[@rashiraghuwanshi3332]

A is correct option mam...

[@divnoorgill3958]

option A is the correct answer Me-Cl + tertiary sodium alkoxide

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Mam answer is root a.

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A is correct option

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Mam please solve more questions from alcohol phenol and ether which are asked in previous neet exam

[@bhavadharshikat.j6336]

Option A is correct answer Mam option b is wrong because it is bridged

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A is the correct answer

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[@chethangowda4045]

A is correct option ma'am

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[@dhilipkumar246]

option (a) is correct mam

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A is the correct answer tq mam

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a is correct mam, ur genious mam

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Mam please explain the hydrocarbons conversion

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thank you maam

[@srikanthp4419]

Transition state hybridisation in sn2 is sp3d madam not sp2

[@sridevibalsubramanian7426]

A is the best route to prepare ether...

[@yamini9986]

Mam A route gives better yield mam

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A mam ans ☺☺ mam Super explain

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Mam for this test your self question better way is a for the production of methoxy bycyclo (2,2,1) hexane

[@hussainmaxkaizer2567]

Path A is favourable since alkyl halide cannot be on a bridge head carbon.

[@krishgupta1450]

A is correct options Mam

[@harisubhiksham5011]

Thank You Mam For test yourself ques is the ans (a) mam ?

[@jayasritutika8631]

A mam because it is primary halide part

[@harshbardhansharma7003]

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[@Cricketglory901]

Answer will be a) because second one have bridge benzene ring

[@anandramesh1885]

hello maam, I am a student of SRI CHAITANYA TECHNO SCHOOL BANASWADI branch only. i m CT batch student.what SRAVAN sir told was if the alkyl halide was a tertiary one it would undergo Elimination reaction and not Substitution nucleophilic unimolecular reaction and in O P tandon also its given the same thing. Please tell me which one should I follow.....

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banglore bhai

[@harshbhatt1504]

1 thing is wrong .....hybridisation of c in transition state is sp3 ...

[@bhimtravellers3263]

answer to the question is A

[@payalbarfe7673]

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[@adyashadas15]

Path A is more favourable as bridge head halide cannot undergo SN2 reaction mechanism while Me-Cl can .

[@rdxmnt714]

Options a is the correct one

[@priyanshuverma2720]

Mam 2* alkyl halide bhi use kr skte he

[@shivanigore9033]

Option no.(a) is correct

[@ygeethika2942]

A is correct option mam

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[@palakurthigayathri1389]

Answer is option A mam

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A answer is correct man

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[@pradeepkumarparikirala6595]

Tertiary alkyl halides with alkoxide ion gives elimination product? Is it correct?

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I hope Sn1 mech not possible

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How many min number of carbons are required for an optically active ether

[@nallisparjanraju9989]

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[@Pari_2813]

mam try yoursel answer is option a Me-Cl

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Mam is A is the answer

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[@sujathaa2393]

A only ma'am. Since the bridge headed carbon cannot form sp2 hybridised intermediate.