First Law of Thermodynamics Example 1

[@TutorialsPoint_]

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[@SanathanDharmaa]

sir as u said in previous vedio that Q will be + for supply and negative for rejetion

[@Persian_Rifleman]

If heat is added to the system, then Q > 0. That is, during isobaric expansion/heating, positive heat is added to the gas, or equivalently, the environment receives negative heat. Restated, the gas receives positive heat from the environment. If the system rejects heat, then Q < 0. That is, during isobaric compression/cooling, negative heat is added to the gas, or equivalently, the environment receives positive heat. Restated, the environment receives positive heat from the gas.

[@sudiptapaul9138]

one thing which I found strange is the sign of work for isobaric process.....if work is done on the system it increases the systems internal energy hence the convention sign should be positive 10

[@SanathanDharmaa]

YES CORRECT . are u preparing for gate.so i am a junior to u

[@ashtonlobo9930]

Sir can u explain more on why Internal energy is not used in this case????

[@muhammedwaseem2466]

because in a cyclic process , change in the internal energy is zero. Hope you understand it now :)

[@VIPER-nc1pw]

isn't it +10??