Uniform Circular Motion - Calculate Tension Force In a Horizontal & Vertical Circle

[@TheOrganicChemistryTutor]

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[@skie1433]

There are really people that are born to be teachers. They explain everything nice and clear. I do hope my teacher could develop those things. Thanks btw.

[@techltrick]

Yeah he born to be a teacher but you are born to be a stupid piece

[@Zephyr-tg9hu]

Just to clarify for others who are confused as I was with this topic, I think it's worth pointing out that "centripetal force" does not actually exist separate from the net force. It is not a special force that is created only when objects move in a circle, it is simply the net force acting on the object as it undergoes circular motion. Edit: Improved wording

[@sea5205]

THANK YOU

[@Zephyr-tg9hu]

@@sea5205 Glad I could help!

[@calteckk]

YESSS

[@v_munu]

@Langston Bodie @Ledger Benton cringe fuck off

[@iexplainjokestomakethemles1560]

thats wrong. centripetal force is very much existent. its centrifugal force that is "pseudo", and exists only to oppose the centripetal fore.

[@andyvargas8590]

Spent over an hour staring at a problem just like this. After watching this video I solved it as fast as I was able to write. Thank you!

[@getnetatalie363]

yes bro it more to say

[@hafezmousavi9043]

For those who might still see this video in the future, I have to say that the formula provided in 3:40 is incorrect. And it is incorrect when he says the force is approximately mv2/r but if it moves slowly it is the root-square norm of mg and mv2/r. That is incorrect. The correct answer is that the mv2/r force is equal and only equal to the net force of all centripedal and cetrifugal forces(radial forces). So the forces that are perpendicular to radius (angular forces) are not considered in the formula. Therefore, for any arbitrary point with an angle \theta from the negative y axis, the tension force will be T= mgcos(\tetha) + mv2/r and there is also an angular force of -mgsin(\theta) perpendicular to radius, which does not have anything to do with the tension because it is orthogonal to the rope. Its job is to slow down the ball as it is going upwards so the one who is rotating the ball should increase the speed of movement manually. Getting back to the formula T= mgcos(\tetha) + mv2/r, when the \theta becomes 90 degrees which is at the middle point the T=mv2/r.

[@jimred1369]

i have a curious thought. an internal 5.25 pc harddisk spinning horizontally and an external standing 5.25 harddisk spinning vertically, which is more efficient (in term of force required to spin them). if the vertical spin is less efficient, why they built it that way?

[@screwandwrenchrob4778]

Person of the century right here.

[@rajveerbhardwaj8470]

Here to study for my Physics Test , Thank you for making my life easier

[@moonnyy364]

OMG! I was stuck on this for 3 weeks!! Thank you so much for such a clear explanation!!😁

[@bobjesus7768]

My guy out here carrying me through PHSX 220 thanks man!

[@janeh9962]

as usual, you are an absolute LIFESAVER. i hope you know you are going to be half the reason i get my degree :')

[@Abenezer-Eth]

At 10:11 NB: Fy=-mg(opposite in direction) ,but if we square Fy^2=mg^2

[@living_human83]

I’m pretty sure there’s a mistake at 3:48 . Gravity doesn’t affect tension at points B and D, since it’s perpendicular to tension.

[@joewatson249]

thought that as well

[@Why-cl8pf]

9:17. He says that it is slightly "tilted."

[@lexanris]

Yes, not really any horizontal component of gravity

[@cursedgrapefruit3570]

Thank you so much, you saved my grade on my physics test!

[@aronpeter1486]

thank you so much, you helped me on my physics homework :)

[@gerrah27]

You are my favorite human being

[@dwijjoshi6214]

Bro u have no idea how many times ur vids have helped me. Especially in the lockdown... Thx a lot

[@videosdiary464]

i really love the way you explain

[@keshavshah752]

How do you know if it’s “moving fast enough”? i.e. How can you check/know which of the two formulas you need to use for calculating the tension at locations B and D

[@NZC_Meow]

If you want you can just use the second one for everything

[@l6e6i6n]

brilliant teacher

[@sea5205]

This guy has the best videos, God bless!

[@mushroomgodwhowillnotstepony0u]

thank you for teaching me more in five minutes than my physics teacher does in 20 years

[@GamerX-ns6sj]

😂😂😂

[@mashrafimorshed18]

Nicely explained. Thank you very much.

[@jimred1369]

i have a curious thought. an internal 5.25 pc harddisk spinning horizontally and an external standing 5.25 harddisk spinning vertically, which is more efficient (in term of force required to spin them). if the vertical spin is less efficient, why they built it that way?

[@AnoldKayamboma]

You are the best sir,

[@eggxecution]

Ohh I see the tension doesn't have a formula but it instead relies on centripetal force

[@TongFreytag]

in this case, when tension and gravity are acting onto the object, the object will NOT have constant speed.

[@tubeazariyatube7078]

I love your teaching style .......But i have question????????

[@reemjassim2559]

Unbelievably helpful! thank you so much x

[@astock95]

What a gentleman!

[@baslealdereje5369]

Thank u my professor

[@fadlyahmad9363]

what if only given revolutions and time to find tension force?(revolutions mean the rotations)

[@Shaash_S]

Where do you get these practice problems, because I would like to try some more?

[@patrickdevaney4662]

the best

[@ynl_rm3411]

Perfect, thank you

[@ayshabushra1794]

What will we do if the speed is constant

[@sbraypaynt]

The speed is always constant The velocity isn’t If any object is in uniform circular motion (moving at constant speed in a circle) it’s velocity is never constant Because if something is moving in a circle It’s always changing direction Therefore it’s velocity must be changing because velocity is a vector

[@eoinMB3949]

Let me ask you a question abut the Tension.........at what point or under what circumstances is the Tension greater or = to 0?

[@mtdjasya127]

A merry go round horse is encircling the ride at a speed of 6 m/s. If the diameter of the ride is 18.64 m, how much force is the horse exerting, provided that its mass is 152 kg? Can someone help me with this

[@Evans808]

Is there one for this but with a velocity that naturally varies?

[@marissapayne5535]

I keep getting 1.3 instead of 35.05 for the first example... why? I'm pretty sure I'm just being dumb, but could you help me out?

[@kamyim3214]

Why minimum velocity equal to sqrt(gR)

[@mukundathakali5281]

Thank you

[@Insatiable_Monk3]

are central forces = centripetal forces?

[@simeonssinfulshoulders7451]

God i am dying 😂 i can't feel my brains

[@lishanzeleke4459]

What about we have a given angle ፀ

[@carolstclair8040]

Can anyone please tell me what the speed in MPH of a two pond steel ball on a six ft rope swinging in a circle/

[@KalkidanBirhanu-hq2db]

at the top ,isn't tension 0?

[@chiaotzu-fu6vy]

So is tension force equal to net force?

[@tomatotomatoe7172]

Why is it not -9.81 m/s^2??

[@atomicheadphones]

Acceleration due to gravity is positive because although an object might not be traveling in the “right” direction it’s still gaining speed so it is accelerating.

[@Zephyr-tg9hu]

In these types of problems, it is standard practice to choose a coordinate system in which anything pointing radially inwards is positive. For example, the net force at the top of the circle would be FT + Fg, since both forces point towards the center of the circle (down). The net force at the bottom of the circle would be FT - Fg since tension points up.

[@whoami6560]

very awesome pants

[@GadirAkilBaba]

6:34

[@jaganreddy886]

Don't you know English