what about the rollers pushing back on the block? wouldnt you add a normal force to that block?
@studentengineering Жыл бұрын
Great question! Since that normal force is acting perpendicular to the vertical movement of the block the only resistance they would theoretically give would be rolling friction which we are ignoring here. Basically we assume that they don’t contribute any resistance to the block moving so they don’t effect the problem. Does that make sense?
@arinzeanthony74472 жыл бұрын
A question please. Lest assume that those bearings aren't there. Does it mean that it isn't necessarily to include frictional forces, since they're coming equally from both sides of the wall?
@studentengineering2 жыл бұрын
Great question! If you’re getting friction from both walls, those friction forces don’t cancel each other out, they add together.
@nadinelanz62973 жыл бұрын
Because we have .35 acting on the wedge at Nab, if you wanted to show that on the cylinder since it acts on the cylinder as well, what would be the opposing force to the .35 Nab on the cylinder?
@studentengineering3 жыл бұрын
Great question. You are correct. The friction force .35Nab acts on the cylinder as well as the wedge but on the cylinder it will be acting in the opposite direction of that friction force on the wedge. On the wedge, that force is pushing towards the left, so on the cylinder it would be pushing towards the right. Does that make sense?