Thank you so much for the super thanks, I really appreciate it!!!
@gandalfthethotful4793 жыл бұрын
@@drpeyam absolutely! I love the way you teach. Less boring and more by example 👍
@frozenmoon9984 жыл бұрын
Casuals: *homomorphism* Dr P: *homeomorphism* I've waited for this for a long time - it's quite the treat.
@jrm611410 ай бұрын
he said that they are different
@izaakvandongen74044 жыл бұрын
At 11:00, it certainly is possible to remove a point from that interval without disconnecting it. Just take an endpoint! I think the more usual topological invariants used here include "can remove two points without disconnecting it" or "the number of points you can remove that do not disconnect it" or "the number of points you can remove that do disconnect it".
@naturemeets4 жыл бұрын
WoW !, Thanks, Dr. Peyam. " NEVER ENDING LEARNING"
@carterwoodson88184 жыл бұрын
@5:16 Remembers pate a modeler but not play-doh that was excellent! Ive heard rubber sheet geometry as well, would say "modelling clay" if wanting to avoid the brand name haha
@sostotenonsosjojododahohlo458010 ай бұрын
Dr. Peyam, you are one of the greats on math youtube. I am studying topology right now and some concept can be hard to grasp. Thank you for making videos like this, it really helps! Also you seem like such a fun guy to be around, the energy you give off is amazing. Keep up the good work!
@drpeyam10 ай бұрын
Thank you so much :3
@SebastianBaum-z2l Жыл бұрын
I enjoyed this video really much. You explained it clearly, while you have such an good welcoming attitude. Keep going!
@francaisdeuxbaguetteiii73164 жыл бұрын
topology is one of my favourite subjects.
@francaisdeuxbaguetteiii73163 жыл бұрын
What the hell happened here
@AmjadKhan-dj8lj2 жыл бұрын
@@francaisdeuxbaguetteiii7316 Also my favorite subject... Please share your Whatsapp no.
@gmjammin4367 Жыл бұрын
Okay Adam
@francaisdeuxbaguetteiii7316 Жыл бұрын
@@gmjammin4367 who is adam
@AltinoSantos4 жыл бұрын
A good video. Good selection of properties and examples. Congratulations.
@dabbinrascal79754 жыл бұрын
Yes I’ve been waiting for this!!! Thank you :)
@denifventear6093 жыл бұрын
You wouldn't believe it but I had to learn and apply this notion in literature for a project haha... So thanks for making it easy enough for me to understand!
@BaterWottleDog Жыл бұрын
im learning this to make math jokes in ceramics class
@dariushanson3142 жыл бұрын
I did not expect an Animorph’s reference. Excellent video.
@umerfarooq48314 жыл бұрын
'Coffee cup is like a donut' well so much for my donut cravings
@vardhanshah Жыл бұрын
Great explanation!
@darrenpeck1562 жыл бұрын
Wow, awesome and concise presentation.
@willnewman97834 жыл бұрын
20:23 Compact subspaces are not always closed subsets, so this proof does not work. Also, the proof cannot work because it is not true that continuous maps from a compact space are homomorphism, one needs the target to be Hausdorff
@f5673-t1h4 жыл бұрын
In short: Homeomorphisms are just relabelling the points and getting the same topology.
@janouglaeser80494 жыл бұрын
Precisely
@krumpy82594 жыл бұрын
I love those "In short" comments, they give further insights.
@nocomment2963 жыл бұрын
I wasn't interested in maths but watching 3b1r bprp and some other KZbin channel including yours has completely changed my view.... Now I want to do MSc in mathematics... It's an interesting subject
@drpeyam3 жыл бұрын
Congratulations :)
@noahtaul4 жыл бұрын
13:28 ...but both (0,1) and [0,1] are open in themselves, so this doesn’t prove they aren’t homeomorphic. You just showed there’s no homeomorphism of R that sends (0,1) to [0,1], which isn’t the same thing. You need the compactness again, or the fact that there are points of [0,1] you can remove and have the remainder be connected, while this is false for (0,1).
@nocomment2963 жыл бұрын
Thanks sir for such explanation
@ahmedmghabat79824 жыл бұрын
This guy is a legend!!!
@samidracula14842 жыл бұрын
a very good video and explanation , thank you very much
@ecologypig2 жыл бұрын
crystal clear! thanks!
@aurangzeb57353 жыл бұрын
Sir at 0:43 you said that in homeomarphism the function can be from one matric space to another space and at 3:20 you said topology does not see distances. My question is, metric spaces cares about distances so how can we take Metric space as a function in homeomarphism definition?
@dariushanson3142 жыл бұрын
I recommend Munkres Topology for this. Metric spaces are how topological spaces are constructed, and if the inverse of a bijective mapping from one topological space to another is continuous, you have yourself a homeomorphism.
@Zubair622 Жыл бұрын
You made topology interesting
@FT0294 жыл бұрын
I really like all the motivating examples you give (e.g. the continuous bijection whose inverse isn't continuous)! I am a little curious about the proof of the property at 9:14.
@drpeyam4 жыл бұрын
Continuity and Compactness kzbin.info/www/bejne/bILPZ4emo9Wqeqc
@FT0294 жыл бұрын
@@drpeyam thanks!
@shivaudaiyar25564 жыл бұрын
Thanks for such a great content with love from India
@soumyadipdey4733 жыл бұрын
Very nice sir
@chriswinchell15704 жыл бұрын
Hi Dr., If you find time, can you make a video about the first homology group? Thanks.
@drpeyam4 жыл бұрын
No way haha
@chriswinchell15704 жыл бұрын
@@drpeyam I’m fairly sure you must have taken algebraic topology and you took it more recently than I because you’re still suffering from ptsd.
@deeptochatterjee5324 жыл бұрын
I don't know much about topology, is there a way to define the limit of a sequence in a topological space without a metric?
@drpeyam4 жыл бұрын
Yes, sn goes to s if for all neighborhoods of s there is N large enough such that for n > N, sn is in that neighborhood
@aneeshsrinivas908811 ай бұрын
Fun fact, JRPG maps are the same as a donut; not a sphere. This is another interesting example of a homeomorphism.
@drpeyam11 ай бұрын
Interesting!!
@Happy_Abe4 жыл бұрын
Animorph fans represent!
@dominicellis18674 жыл бұрын
if you were to curve out the real line into a circle does that mean circles are homeomorphic to the real number line and subsequently any interval on the real number line could you also map the xy plane/the complex plane to a sphere mapping x to a circle generated by theta and y to the semi circle generated by angle psi?
@Apollorion4 жыл бұрын
So far as I understood it... - The real line has two open ends, but a plain circle hasn't, so they aren't homeomorphic. - If from the plain circle you'd take away a single point though, what'd be left of the circle would be homeomorphic with a line. - Those semi circles need to be open ended, too. So the complex plane won't be homeomorphic with the full surface of a sphere. The way of projection you propose leaves open the poles, as shared end points of the semi circles, and also doesn't include a continuous curve on the sphere surface connecting these poles and that's nowhere parallel to the equator. If you 'wish' to project the complex plane on the surface of a sphere, I think a sort of Riemann sphere would do better: - where the equator equals the unit-circle, - one pole equals the origin, - the other pole equals infinitely big, which is the point that is not part of the complex plane. - Longitude is just the argument or phase of the complex number. - Latitude is just dependent on the modulus.
@wiloux4 жыл бұрын
maths is just playing with some pâte à modeler after all ;)
@narutosaga124 жыл бұрын
11:50 how is it that it is both not homeomorphic and homeomorphic at the same time?
@drpeyam4 жыл бұрын
No they are not homeomorphic. If I said they are, I misspoke
@FloduQ4 жыл бұрын
Is it enough to find one homeomorphism f, so that M and N are homeomorphics ? or do we have to say they are homeomorphics for the specific homeomorphism f ?
@drpeyam4 жыл бұрын
One is enough
@SS-ld2hk3 жыл бұрын
does (0,1) homeomorphic to R imply that any interval in R is homeomorphism to R
@drpeyam3 жыл бұрын
I think so, at least any open one
@aneeshsrinivas90882 жыл бұрын
is there a special name for homeomorphisms which are uniformly continuous?
@drpeyam2 жыл бұрын
unimorphisms
@aneeshsrinivas90882 жыл бұрын
Imagine being able to transform any object into any other object as long as they are toplologically homeomorphic in real life(like for example being able to transform a torus into a coffee mug)? How would that be as a superpower ?
@drpeyam2 жыл бұрын
Not very effective…
@anchalmaurya23722 жыл бұрын
Sir, 1/2x is not continuous at 0 but apne [0, 2] liya h?
@drpeyam2 жыл бұрын
?
@ekadria-bo49622 жыл бұрын
By the definition, i wonder: Is R^N Homeomorphic to any interval?
@drpeyam2 жыл бұрын
No if n >= 2 because if you remove a point from R^n it’s still connected but if you remove a point from an interval it becomes disconnected
@ekadria-bo49622 жыл бұрын
@@drpeyam i wonder now. What its still true in R^1 and 2 ?
@isobar58574 жыл бұрын
Well you may not know the the difference between a donut and a cup of coffee but I do...I can eat a donut . Did I pass the test...it was a test, wasn't it ? Sorry for the levity...I gave up on maths after calculus 3. Have a good day sir.
@Tomaplen4 жыл бұрын
Will Lord Peyam have differential geometry videos on 2021? Would be amazing
@drpeyam4 жыл бұрын
I’m planning on doing a miniseries on differential forms, sometimes later this year
@aneeshsrinivas90882 жыл бұрын
But is there an explicit formula to go from a coffee cup to a donut?
@drpeyam2 жыл бұрын
I bet
@Caleepo4 жыл бұрын
Isnt homeomorphism the same as isomorphism ?
@mikhailmikhailov87814 жыл бұрын
In the category of topological spaces it is. The notion of isomorphism is that you can exactly match two objects and their structure, whatever the structure in question might be.
@Caleepo4 жыл бұрын
@@mikhailmikhailov8781 aight thank you for your answer, But is there a case in which they are actually different ?
@mikhailmikhailov87814 жыл бұрын
@@Caleepo isomorphism is just a generic term for any sort of equivalence between mathematical objects.
@gordonchan48014 жыл бұрын
donuts at home
@lacasadeacero4 жыл бұрын
The morphism Is something new. Like Stokes theorem. I think we'll find a profound use.
@vedants.vispute774 жыл бұрын
What is your IQ sir?
@dgrandlapinblanc2 жыл бұрын
Ok. So (f)-1 is continuous on the circle of radius 1 to the (0,2pi] because she's one to one and not onto sorry. Thank you very much.