What's the Difference between Ka and Kb?

[@KITRONIX111]

Dude this needs more views. Thank you for opening another door of chemistry for me to jump through!

[@soniamorales3633]

THANK YOU. You're the only one I could find who explained this and made it so SIMPLE.

[@ankushraj9583]

You saved a life today. It was awesome.

[@Cowboy_Consultants]

thank you. finally some damn intuition. too many videos out there just repeating the formula

[@jannahpath9044]

Bro that was precise and clear

[@ayushbhandarkar8394]

You are great...... Great teaching.......this really helped

[@Footballstreamings]

5:28 what do you mean here?

[@memyselfandyourcat799]

Thanks. This really helps

[@minabish1783]

Question, The secound part doesn't make sense, if it takes back the proton shoudn't it logicaly take it from hydronium and form water rather than OH? As a reversable reaction?

[@soumikdutta7200]

thanks dada(Elder brother)iam from india !thankss for sharing.

[@georgehennen4659]

When you find the (x). And put the negative log of x. Do you get the ph or poh?

[@shinellejack6921]

you are heaven sent. Thank you!

[@carlosamaya8427]

Loved it, helped me a lot

[@betheladekogbe5559]

Super clear. Super helpful. Thank you

[@tamaradifc7566]

Paid 18K yet have the worst chemistry teacher at school. Thank you ChemistNATE for giving us the opportunity to learn.

[@muhamoto7317]

How does this video not have a 1000 likes already? I would give 1000, but I can only give 1 haha.

[@connordejager1125]

Ahhh I was confused about the Kb of the conjugate base of a strong acid ... I figured they should be the same because dissociation is dissociation. However, I did not realize that the Kb expression assumes the proton is extracted from water, not hydronium. That clears it up.

[@mohfa1806]

Thank you for your great educational videos...iam confused and have two questions please : 1) About the HF example , in the F- 2nd reaction equation at equilibrium , shouldnt the F- reacts with H3O+ instead of H2O?. 2) why the concentrations of F- and HF are equal in both reactions inspite that they are two different reactions ? . Am i missing something i the concept ?...i am totally lost :( ..thank you in advance

[@yanic-p162]

Before I explain, note that HF and F- in both equations are represented as acids and conjugate bases for each equation where HF is the acid in the first one but a conjugate base in the second. Same follows for F-, but flipped for its case. 1. If you look at the first HF example next to the F- examples, we see that the HF and the water molecule has reacted to produce the product of F and H30, so therefore the F- wouldn't react with the h30 (they're both products of the same reactants) H from h2o was given another h from HF which then led for F to be left alone in the products. 2. Folowing from the above explanation, the reactions might not look the same, but it's from the same interactions between the F and the HF of the two equations. In the first equation F- is produced and as a lone molecule, it seeks other H2O molecules to attach to form another equation to yield the HF and the OH molecule. I hope this helps :)

[@Ilikestrawberriessss]

@@yanic-p162 you helped me, thank you!!

[@baileepasienza9509]

you are amazing!! thank u so much

[@youkey1090]

thx man .

[@devta7730]

Thanks it helps me a lot

[@ahmedsalehalharthi9069]

My question is ...what is Ka and Kb??😅😅

[@Ilikestrawberriessss]

The rate at which the Acid (Ka) or Base (kb) dissociate in water

[@souadalabd175]

مين عربي هون😅😅

[@thomaswinfrey3429]

This taught me where my chem teacher didn't