Young's Modulus & Vernier Scales - A-level Physics

[@retooluvyuhx5569]

WE TRULY APPRECIATE YOUR EFFORTS AND TIME SIR

[@aaronbrooker8098]

Think I've found my 'free science lessons' of A Level

[@ScienceShorts]

No offense taken.

[@aaronbrooker8098]

Science Shorts I’m only kidding you are better than him :)

[@ScienceShorts]

😉

[@snhtsljedc9803]

Science Shorts 😂💀🤡✌🏻

[@inzayn1d]

lmaoo

[@mohamedrashed6643]

watching this vid 30 mins before exam its a great help thx

[@vahe057]

Lol same

[@benb758]

Is this 1 video every day? That's kind of insane. (And extremely helpful)

[@ScienceShorts]

+Ben B Not anymore! I'm done for now :D

[@Zravi1234]

All your videos are absoulutely amazing and saved my A-Level, I've started rewatching all of them. Just wondering what % of the A-Level would you say you have covered and have you gone over all the required practicals?

[@ScienceShorts]

Thank you! There's not a lot I teach on top of what's covered in the videos (I don't do any of the other AQA optional topics), apart from the odd little bits of knowledge missing, like metastable states, for example - but this is stuff that's easy to check on with the spec. So I'd say I've covered ~95% of the course. The important thing to do is answer questions to improve your exam technique and pick up on the subtleties the exam board look for in your answer.

[@Zravi1234]

I have been doing some practice questions my teacher has set me, however due to the new reformed A levels there is only 1 past paper and 1 specimen available. Any advice on how to aid my revision even further?

[@retooluvyuhx5569]

you can do papers of other exam boards then regarding the topics you choose, if you have only one specimen and 1 past paper then that wouldn't be enough for the revision as u can get a bunch of differently asked questions that can be really tricky, Idk but I would do that if I was in your shoes. idk for how long this comment has been here I just thought that my reply might help in a sort of way

[@musfirakhurshid]

Chris Hemsworth teaches Physics. Wow! 👌🏼

[@norahzidyana508]

😂

[@inzayn1d]

its thor the god of science

[@DanielTshipama-w5y]

7 years later and its still helpful

[@chenulgomes8234]

Hey, I don’t know who you are but you have been pulling me through my exam. Thanx

[@alastairbennie5168]

thanks very much, will come in handy for my advanced higher project! (especially liked the vernier scale explanation)

[@elliewhiter]

so so helpful. I have spent so long trying to read a vernier scale and now I finally understand how to

[@muhammadanas7791]

Got my A-level physics Paper 1 in 3 days. I'm killing it

[@elliotverry730]

A little bit of me died every time I saw I had to draw out another graph haha, great video though thanks for the help :)

[@yikesQuakes]

Your explanation is truly beautiful sir as clear as crystal

[@stanislavshelemekh2162]

Very very very well explained!

[@lethbophilip6365]

Apprghe knowledge fam... Be blessed 🙌 ❤

[@dyxtopia21]

This was very helpful thank you

[@invictusgaming3622]

hi sir! what about the features of a force-extension (or stress-strain) graph for rubber? how will the gradient look?

[@ScienceShorts]

Curvy. Have a look at OCR 2017 paper 2, there's a question on it.

[@emilythompson3678]

man you are going to save my life

[@rachelallsop6524]

This is so helpful thank you !!! really helped explaining the graphs and why it means what it does ^-^

[@selleryy]

Great video, thank you Sir.

[@kanyakinanti]

Very helpful. Thank you, Sir

[@wafa2075]

How does extension increase with length?

[@pranjalbanerjee6986]

Is l the strengthen length or unstressed lagers?

[@lethbophilip6365]

Appreciate 😢

[@Swaglander]

thanks for the help

[@sakifnewaz7212]

Thank you very much

[@xgenarater]

Would u not do a force extention graph instead of a mass extention graph?

[@seemadevi-mk8pz]

Very good explanation. Thanku

[@moodymonstrosity1423]

I have a question: When you made the equation for the youngs modulus :- E =FL/A x extension, why didn't you take a constant k because in hooke's law we had a constant while forming an equation F = k(x) Please clear this for me as I am really confused. Thankyou.

[@radowanahmedbaized3597]

Youngs modulus is the constant for stress-strain graphs. "K" is the constant for Force-Extension graphs for Hooke's law.

[@moodymonstrosity1423]

@@radowanahmedbaized3597 huh?

[@sangodan3031]

@@moodymonstrosity1423 you only need k when trying to calculate an extension by a force, in this you already have the force and the extension so k is irrelevant

[@aitchisoniantutor1625]

Very helpful

[@s3lim77]

Ahh it was Mr Rhys from Malmesbury Science all along...

[@ScienceShorts]

Nope. Rather, Mr Rees was Science Shorts all along.

[@s3lim77]

@@ScienceShorts had to guess which Rees it was going to be :/

[@ScienceShorts]

Don't worry, even my pupils spell it wrong.

[@GamingGuyGus]

legend

[@SonLyAu]

Thank you

[@ibrahimabulwifa4296]

brilliant

[@evolvinggenius198]

very cool

[@d.k.6015]

Ohmygod bless you

[@Koltary]

I need definitions for hard and malleable and the other characteristics

[@luqmanhakim-kq7so]

CAN YOU SHOW ME THE YIELD POINT SIR?

[@miesht430]

hi sir this is not for edexcel right

[@maazraza4895]

this is on the Edexcel syllabus

[@williamwelmans3026]

What can I say sir! "Excellent" comes to mind! " Wish I had you as a Teacher!"

[@DahliaArgue]

not a fan of this topic for some reason… thanks for the help!

[@samirhussain458]

you god

[@kieran7610]

What i've never understood is why the yield point decreases in stress and then increases again.

[@alymaghraby6923]

You dont need to know this, but in simple terms: The graph doesnt take into account the changes in surface area when the strain increases. So that little dip in stress is just due to the area increasing while the wire is extending.

[@courtneyallen5685]

100

[@yuki002x]

that vernier caliper tho 😭

[@musfirakhurshid]

Chris Hemsworth teaches Physics. Wow! 👌🏼