Slip Speed and Slip in a Motor

[@ztoastinator2091]

Thanks! This helped me a ton! I didn’t understand at first why a slower rotor speed induced more torque, but now I get it!

[@justinstallings7844]

Great video! You missed some great opportunities to discuss how the second most popular boy band were such big proponents of induction motors.

[@ZackHartle]

HA HA! I'll try not to miss the opportunity next time

[@corymichael9625]

Awesome videos. 3rd year electrician here. Rotor frequency has come up in class before and just trying to grasp this concept. From what I understand rotor frequency goes down as Slip goes down. Is rotor frequency how many times the stator passes by the rotor?

[@ZackHartle]

Rotor Frequency and Slip are directly proportional. When slip goes up, frequency goes up. The frequency is actually the induced frquency into the rotor. Think of it as the sine wave of the current and voltage that are getting induced into the rotor.

[@aryandubey1351]

Extending on the example in the end, in a practical scenario, if the load suddenly drops, what would happen to the current on the motor, if it was measured in real time, would it drop or rise?

[@blueberet7272]

Good explanation, what would be the slip at no load condition?

[@ZackHartle]

Very small. Usually like 1-2%

[@rever4217]

@@ZackHartle Is that because there's always some sort of load even if we don't put anything on the motor? Like the rotor pushing through air resistance or rolling resistance or friction between the moving parts?

[@ZackHartle]

@@rever4217 You could say that. There was to be a difference between Sync and Rotor, because there has to be relative motion in order to cause the force in the rotor to spin. If your rotor ever did spin as fast as sync, there would be no relative motion, therefore no current produced in the rotor, therefore no magnetic field to oppose the stator, and then the rotor would slow down.

[@rever4217]

@@ZackHartle but the rotor would only slow down because it was encountering some resisting force like friction right? Under ideal conditions once in motion it would stay in motion and there would be no need for any force to keep pushing it.

[@abelferia1]

Thanks for the info, it really helped understand 👍

[@ZackHartle]

No problem 👍

[@GiStormy]

Thank you!

[@jacobtylerjoyce8169]

Very nice. Thank you,

[@rever4217]

Am I thinking of this correctly? The rotor rpm is trying to catch up to the stator magnetic field rpm due to the force induced (somehow, I'm yet to understand this part) from the difference of their rpm's. The greater this difference (called slip speed as you said) the greater the force (linear relationship? e.g. double the rpm = double the force?) and hence torque outputted by the motor.

[@ZackHartle]

This other video might help out a bit too: kzbin.info/www/bejne/a3ipdGCJptOdh68

[@rever4217]

@@ZackHartle Thanks for the video, although I still have many questions, and my previous ones weren't fully answered either. e.g. x2 rpm = x2 torque?

[@ZackHartle]

@@rever4217 I don't think it's a linear relationship like that. All motor rotors will react a bit differently dependent on their design.

[@eeemuse]

thanks a million

[@alissa.azrull]

how to calculate slip at half rated load?

[@sailingeden9866]

Wouldn't stator speed always be zero, because it does not move?

[@ZackHartle]

It's the speed of the rotating magnetic field

[@RohitKumar-fy9fp]

wow , i just unknowingly landed on a diamond mine

[@ZackHartle]

Glad you like it!

[@Deepanimosity]

Are you writing backwards?!?

[@InforcetechAnkleshwar]

അജീഷ്.k.s

[@InforcetechAnkleshwar]

Vande Bharat